Y2, C5 - Forces & Friction Flashcards

1
Q

What direction does a normal reaction act

A

Perpendicular to the surface

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2
Q

What direction does weight always act

A

Vertically downwards

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3
Q

What is Newton’s first law

A

An object will remain at rest or continue to move with constant velocity unless acted upon by an external force

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4
Q

Why are forces resolved perpendicular to each other

A

Because perpendicular forces do not interact with each other

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5
Q

If a particle is static what do:
a) forces left equal?
b) forces down equal?

A

a) forces left = forces right
b) forces down = forces up

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6
Q

What does it mean if a bead is smooth on a string

A

The two parts of the string can be considered the same and thus the tension is the same throughout

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7
Q

What does it mean in terms of tension if a particle (bead) cannot smoothly move along a string

A

The tension is different both sides (e.g. T1, T2)

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8
Q

What steps should you always take when solving statics problems (2)

A

1) Resolve horizontally
2) Resolve vertically

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9
Q

What is Newton’s second law

A

F = ma
An object will accelerate if there is an overall resultant force on the object

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10
Q

When shown a diagram with lots of forces that need resolving, what can you do

A

Draw a new diagram with all the forces resolved horizontally and vertically

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11
Q

How can you use vectors to combine forces

A

Separate forces into i and j components
Write in vector form
Resultant force = (i, j) where all i components are added and all j components are added
Magnitude = Pythagoras
arctan(j / i) = angle

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12
Q

How should you resolve forces on inclined planes in relation to the plane

A

Parallel and perpendicular to the plane

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13
Q

With inclines plane problems can you draw a new diagram with forces resolved parallel and perpendicular to the plane

A

Yes

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14
Q

When there is no pulling force (tension T = 0), what is the frictional force and is the system in equilibrium

A

μR = 0
No friction
Equilibrium as not moving

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15
Q

When there is a pulling force (tension T < μR(max)), what is the frictional force and is the system in equilibrium

A

μR = T
Friction is the same magnitude as the opposing force
Equilibrium as not moving

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16
Q

When there is a pulling force (tension T > μR(max)), what is the frictional force and is the system in equilibrium

A

μR = μR(max)
Friction has reached its maximum limit
No equilibrium, the forces are imbalanced so the object accelerates

17
Q

When there is a pulling force (tension T = μR(max)), what is the frictional force and is the system in equilibrium (2 situations)

A

μR = μR(max)
Friction is limiting and has reached its maximum
Equilibrium - limiting equilibrium
OR
Equilibrium - object moves with constant velocity

18
Q

What is the relationship between T and μR(max) if a force is applied to an object and it doesn’t move

A

T < μR(max)

19
Q

What is the relationship between T and μR(max) if a force is applied to an object and the block accelerates

A

T > μR(max)

20
Q

What is the relationship between T and μR(max) if a force is applied to an object and the block is on the point of slipping

A

T = μR(max)

21
Q

What is the maximum friction between two surfaces equal to (formula)

A

Friction(max) = μR

22
Q

Can you have a negative coefficient of friction (μ) value

A

NO

23
Q

What direction does friction act

A

Opposite to motion

24
Q

Can friction be less than it’s maximum value

A

YES, if the force opposing it is small

25
Q

How do you use the assumption that a pulley is smooth in calculations

A

Tension both sides of it is equal

26
Q

Friction acts up a slope to stop an object from slipping. What direction does the friction act if a horizontal force is applied to the box (into the plane) given that the box remains in equilibrium

A

Friction changes direction and acts down the slope, opposing the direction of motion up the slope

27
Q

How can you find the maximum value P that can work against a friction while keeping an object in equilibrium

A

μR is at a maximum
Resolve and solve simultaneously to find P

28
Q

How would you find a range of possible values for tension that keep an object at equilibrium on a rough plane

A

Solve 2 equations for T
Slipping UP (friction works down)
Slipping DOWN (friction works up)
ans = Smallest T <= T <= Biggest T
Where smallest T is the limiting equilibrium to move down the plane and biggest T is the limiting equilibrium moving up the plane

29
Q

How do you determine of an object will move on a rough plane

A

If F > Frictional force
Compare F with μR
If F > μR it will move
(where F is the force up or down the plane opposing the friction)

30
Q

What should you take as the weight of an object if you are not given the mass

A

mg

31
Q

If a particle is projected up a slope, what is the force upwards

A

0
There is no force acting on it as it is projected, all forces will work to stop it from going up

32
Q

You have a block (P) on a rough plane attached to a smooth pulley with a block on the other end (Q) hanging freely. When the hanging block is released, how do you go about calculating the acceleration of the system

A

Write equations of motion for both P and Q separately using F = ma
Solve equations simultaneously to find acceleration and force (tension in string)

33
Q

How do you use the fact that a string is inextensible in calculations

A

Acceleration is the same in particles at both ends

34
Q

What is the equation for the resultant force exerted on a pulley by a string (over an inclined plane)

A

2 * T * cos((90 - α) / 2)
Where T is tension
α is the angle of incline of the plane

35
Q

What direction does the resultant force exerted on a pulley by a string (over an inclined plane) act

A

Directly down the middle into the incline plane (splitting the angle of the corner in half)