Y2, C3 - Normal Distribution Flashcards

1
Q

Is the normal distribution discrete or continuous

A

Continuous

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2
Q

What is σ^2

A

Variance

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3
Q

What does a large variance do to the bell shaped curve

A

Widens it

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4
Q

What is μ

A

Mean

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5
Q

What is the area under a probability graph

A

1

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6
Q

What is the y axis of a probability graph

A

The density of the probability

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7
Q

Where are the points of inflection on a normal distribution curve

A

At μ ± σ

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8
Q

What 2 things are equal to the mean of a normal distribution

A

Mean = mode = median

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9
Q

What % of data is within one standard deviation of the mean

A

68%

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10
Q

What % of data is within two standard deviations of the mean

A

95%

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11
Q

What % of data is within three standard deviations of the mean

A

99.7%

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12
Q

What is σ

A

One standard deviation

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13
Q

X~N(20, 3^2), how would you find P(16 < X < a) = 0.3

A

Find P(X < 16) = 0.0912 (normal CD)
0.0912 + 0.3 is the area to the left of a
Inverse normal:
area = 0.3912
σ = 3
μ = 20
Answer of a = 19.17

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14
Q

What is a Z value

A

The number of standard deviations above the mean

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15
Q

Using IQ distributed as X~N(100, 15^2), what would the z value be for 130 and 85

A

130 –> Z = 2
85 –> Z = -1

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16
Q

What is the distribution formula for the standard normal distribution

A

Z~N(0, 1^2)
Mean 0, standard deviation, 1

17
Q

What is the coding formula to turn X into Z

A

Z = (X - μ) / σ

18
Q

In a Z table, what does Ф(a) mean

A

P(Z < a)
It is the probability Z is less than a constant, a

19
Q

The random variable X~N(50, 4^2), write in terms of Ф(z) for some value of z.
a) P(X < 53)
b) P(X >= 55)

A

a) P(X < 53) = P(Z < (53-50) / 4)
P(Z < 0.75)
ans = Ф(0.75)
b) P(Z > (55-50) / 4)
P(Z > 1.25)
1 - Ф(1.25)

20
Q

Determine a such that P(-a < Z < a) = 0.6

A

Symmetrical therefore P(Z < a) = 0.8
Plug into inverse normal calc
a = 0.8416

21
Q

X~N(μ, 3^2). Given that P(X > 20), how would you find μ

A

P(X > 20) = 0.2
P(Z > a) = 0.2
inverse normal calc, a = 0.8416
Use coding formula:
(20 - μ) / 3 = 0.8416
Therefore μ = 17.5

22
Q

Given that P(Y < 160) = 0.99 and P(Y > 152) = 0.90, how would you find μ and σ

A

Put into 2 forms of P(Z < a) = …
Sub values into coding formula
Solve simultaneous equations to find μ and σ
μ = 158.8
σ = 2.2

23
Q

Why do we approximate a binomial distribution using a normal distribution

A

It takes a lot of computational power to use factorials in high order binomial calculations (over 50)

24
Q

What two things need to happen to be able to accurately approximate binomial distributions as normal distributions (n and p)

A

n must be large
p must be close to 0.5

25
Q

X~B(n, p) what are n and p and X

A

n = number of trials
p = probability of successful trials
X = number of successful trials

26
Q

When converting between binomial and normal, how do you calculate μ

A

μ = n * p

27
Q

When converting between binomial and normal, how do you calculate σ

A

σ = root(np(1-p))

28
Q

X~B(6, 0.3), how does this convert to a normal distribution Y~N(μ, σ^2)

A

Y~N(1.8, 1.26) (σ would equal root(1.26))

29
Q

Apply a continuity correction on ‘6 hours to the nearest hour’ to convert it from discrete to continuous

A

5.5 <= Y < 6.5

30
Q

Apply a continuity correction on X < 9 to convert it from discrete to continuous

A

Y < 8.5

31
Q

What are the steps for applying a continuity correction

A

1) If > or <, convert to >=, <= first
2) Enlarge the range by 0.5

32
Q

Convert P(3 < X <= 6) from discrete to continuous

A

P(4 <= X <= 6)
P(3.5 < Y < 6.5)

33
Q

X~B(n, p)
What is the most accurate estimate when approximating the binomial distribution by a normal distribution.
Give a reason to support the value

A

p = 0.5
When p = 0.5, the binomial distribution is symmetrical like the normal distribution

34
Q

For a random sample of size n taken from a random variable X, what is the sample mean (X-bar) distributed with (formula)

A

X-bar ~ N(μ, (σ^2) / n)

35
Q

What happens to the variance if more sample means are taken

A

It decreases

36
Q

What does X-bar mean

A

The sample means (the mean of the samples taken)

37
Q

P(X < μ - 15) = 0.35
Find P((X > μ + 15) l (X > μ - 15))

A

P(A l B) = P(A n B) / P(B)
P(X > μ + 15 X > μ - 15) / P(X > μ - 15)
= P(X > μ + 15) / 0.65
= 0.35 / 0.65
ans = 7/13