Workbook Topic 6

Question 1

The reaction of the gummy bear in the test tube produces a lot of heat. Before the gummy bear is tossed into the test tube, potassium chlorate (KClO₃) is heated to produce KCl and O₂. Consider thee following materials and compounds and identify what is the system and what is the surroundings:

a) KCl
b) O₂ in test tube
c) oxygen in room
d) the test tube
e) KClO₃

Answer 1

a) system
b) system
c) surroundings
d) surroundings
e) system

Question 2

Energy goes into the system is what kind of reaction?

Answer 2

Endothermic

Question 3

Energy going out of the surroundings is what kind of reaction?

Answer 3

Endothermic.

Question 4

Energy of the system going up is what kind of reaction?

Answer 4

Endothermic

Question 5

Energy of surroundings going down is what kind of reaction?

Answer 5

Endothermic

Question 6

Change in PE is positive is what kind of reaction?

Answer 6

Endothermic

Question 7

Beaker getting cold is what kind of reaction?

Answer 7

Endothermic

Question 8

Heat as a product is what kind of reaction?

Answer 8

Exothermic

Question 9

Energy going out of the system is what kind of reaction?

Answer 9

Exothermic

Question 10

Energy going into the surroundings is what kind of reaction?

Answer 10

Exothermic

Question 11

Energy of the system going down is what kind of reaction?

Answer 11

Exothermic.

Question 12

Energy of surroundings goes up is what kind of reaction?

Answer 12

Exothermic.

Question 13

Change in PE is less than 0

Answer 13

Exothermic

Question 14

Beaker getting hot is what kind of reaction?

Answer 14

Exothermic

Question 15

F₂ → 2F

Is a bond broken or formed?

Answer 15

Broken

Question 16

F₂ →2F

Change in enthalpy positive or negative?

Answer 16

Positive

Question 17

F₂ → 2F

Change in PE positive or negative?

Answer 17

Positive

Question 18

F₂ → 2F

Surroundings get hot or cold?

Answer 18

Cold

Question 19

2F → F₂

Bonds broken or formed?

Answer 19

Formed

Question 20

2F → F₂

Change in enthalpy positive or negative?

Answer 20

Negative.

Question 21

2F → F₂

Change in PE positive or negative?

Answer 21

Negative.

Question 22

2F→F₂

Surroundings hot or cold?

Answer 22

Hot

Question 23

When trying to determining the change in enthalpy of a bond in a molecule with 4 identical bonds what should your coeffieceint be for your x variable?

Answer 23

4