Weeks 5+6 Flashcards

1
Q

Linkage

A

When genes don’t assort independently, genes are located on the same chromosome, more likely the closer the genes are

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2
Q

Why do recombinants occur?

A

Crossing over in meiosis I, the further apart the genes are, the more likely a crossover is to occur

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3
Q

What is Chi Squared Analysis used for?

A

To determine if numbers in categories are actually different and not due to chance - is it statistically significant?

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4
Q

Statistical significance

A

Results are not able to be explained by chance, null hypothesis is rejected, P value less than 0.05

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5
Q

Steps for doing Chi Squared Analysis

A
  • Identify parental and recombinants
  • Identify what expected values are for P and R
  • Sum of categories [(observed - expected)^2/expected]
  • Determine degrees of freedom (#categories -1)
  • Chi squared table to find P value
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6
Q

Two point crosses

A

Determine relative gene positions
- difficult to determine order when genes are close together
- actual distances don’t always add up for far apart genes

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7
Q

Three point crosses

A

Uses three marker genes, more accurate, accounts for double crossover correction

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8
Q

Steps of doing a three point cross:

A
  • Determine parental and recombinant classes
  • Compare parental and double crossovers to determine the middle gene
  • Determine distance between middle gene and adjacent (add recombinants, divide by total, multiply by 100)
  • Determine distance between far genes by adding recombinants + double X (x2), divide by total, multiply by 100
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9
Q

dNTP

A

Made up of phosphate, deoxyribose, nitrogenous base (either pyrimidine or purine)

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10
Q

How do nucleotides connect?

A

Phosphodiester bonds between 3’ carbon and phosphate group of previous base

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11
Q

Direction of DNA strands

A

Antiparallel
- phosphate is 5’
- OH end is 3’

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12
Q

Complementary base pairing

A

A pairs to T (two H bonds)
G pairs to C (three H bonds)

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13
Q

How was DNA determined to be the unit of inheritance?

A

(1944) Avery, MacLeod, McCarty added enzymes that broke down either protein or nucleic acids to bacteria to see which caused lethal bacteria to still form (using transformation)

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14
Q

Chase and Hershey

A

In 1952 they infected bacteria with bacteriophages that contained tagged DNA or tagged proteins, and saw which was found inside bacteria

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15
Q

DNA structure

A
  • Helix due to X-ray diffraction
  • Equal amounts of A and T, G and C
  • Major and Minor grooves
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16
Q

Eukaryote genome structure

A

Linear, double stranded chromosomes

17
Q

Prokaryotes genome structure

A

Circular, double stranded chromosomes

18
Q

Virus genome structure

A

Single stranded DNA

19
Q

Retroviruses genome structure

A

RNA genome

20
Q

Viruses

A

Not alive, no cells, made of DNA and proteins, requires host cell to replicate

21
Q

DNA Replication

A

Occurs in S phase of cell cycle, semiconservative

22
Q

Mechanism of DNA replication

A

Initiator recognizes origin of replication (which is an AT rich site), helicase unwinds DNA, topoisomerase relieves pressure
- RNA primer added, DNA Pol III adds bases to 3’ OH on primer
- DNA Pol I removes primers and fills in gap with DNA
- DNA ligase Attaches 3’OH and 5’PO4 ends of Okazaki fragments

23
Q

Telomeres

A

Non coding repeats at the ends of chromosomes, designed to protect DNA from degrading due to replication

24
Q

Telomerase

A

Has RNA compliment with overhang, allows DNA Pol III to bind and replicate
- Most somatic cells in humans don’t have it

25
Hayflick limit
When cells stop dividing because they have reached the end of their telomeres.