Wave Optics and Diffraction Part 2 Flashcards
What is the phase difference ΔФ equal to for two point sources at y and 0?
ΔФ = k(|x-y| - |x|)
How do you calculate the magnitude of a vector?
Square root of the sum of its squared components
What can we do with the magnitude of x-y to simplify it?
- Once expanded out, we get (|y|/|x|)^2, which can be neglected as it is negligible
- set the second part equal to t
What is |x-y| approximately equal to?
|x|(1 - (xy/|x|^2))
What is the phase difference ΔФ approximately equal to after expanding?
-k * (x*y)/|x|
What can we approximate |x-y(i)| to?
To D as the fringe spacings are negligible.
How can we separate the exponential in u(x,t) to make it into a useful form?
take the y out of the x-y part and make two exponentials with x in one and y in the other - x terms is the same for all sources but the y term is different in phase due to pinhole positions.
What is the general results for u(x,t)?
1/D * exp(ik(|x|-ct)) * sum from i=1 to N of A(i)exp(-iky(i))
What can we do for discrete pinholes?
Make the sum part an integral: integral of d^2y*exp(-iky) * a(y), where a(y) is the sum of A(i)𝛿(y-y(i))
What is u(x,t) proportional to?
u(x,t) ∝ a(k), the transform, where a(y) is a general aperture function which can define apertures finitely, and is equal to 1 inside the aperture and 0 outside.
Considering the example where the aperture is a pair of pinholes, what is a(y) equal to if the pinholes are separated by 2l?
a(y) = 𝛿(y-ly(hat)) + 𝛿(y+ly(hat))
What is the transform of a(y) equal to?
a(k) = exp(-ik(ly(hat)))+exp(ik(ly(hat))) = 2cos(k/|x| * l*x1))
How can we find the interference pattern using the transform?
- Know that I = |u|^2, and u ∝ a(k), so I ∝ cos^2(klx1/D)
- Can use this cosine function to sketch out the interference patterns on the screen by changing x values
In u(x,t), what does the A represent?
Amplitude of light emerging from each point source.
When considering a square aperture of side 2w, what do we first do to calculate the intensity on the detector screen?
- Compute a(k) by separating into y1 and y2
- y = (y1, y2, 0), so k.y = k1y1 + k2y2
- Sub this in, separate the integral and then do the integrals
- Find the trig solution