Unit 7 Lesson 2: Distance in the Coordinate Plane Flashcards
distance formula
a formula that uses the coordinates of two points to determine the distance between them on the coordinate plane
line segment
part of a line that has two endpoints
ordered pair
the two coordinates that name the location of a point on the coordinate plane
Pythagorean Theorem
the theorem which states that the square of the length of the hypotenuse of a right triangle is equal to the sum of the squared lengths of the other two sides
x-coordinate
the first coordinate in an ordered pair that tells the distance to travel left or right from the origin
y-coordinate
the second coordinate in an ordered pair that tells the distance to travel up or down from the origin
What does the lenght of a line segment indicate
The distance between two points is the length of the line segment joining the two points.
What can be the pytagoream throrem be used for
The Pythagorean Theorem can be used to find the distance between any two points in the coordinate plane.
There is, in fact, a formula that can be used to determine the distance between any two points in the coordinate plane. This formula is called the
distance formula
The distance formula is dervied from what
This formula is called the distance formula, which is derived from the Pythagorean Theorem.
What is the distance formula equation
d=(x2βx1)2+(y2βy1)2βββββββββββββββββββ
Does it matter which point is assigned to be (x1,y1)
and which is assigned to be (x2,y2)
?
The distance is the same regardless of which point is assigned to be (x1,y1)
and which is assigned to be (x2,y2)
. Because the differences between the x
and y
values are squared, it doesnβt matter whether that difference is positive or negative.
Besides using the distance formula, how else can you determine the distance between any two points in the coordinate plane?
You can use the Pythagorean Theorem to find the distance between any two points in the coordinate plane.
Explain how the distance formula works based on what you know about the Pythagorean Theorem.
In the Pythagorean Theorem, square the lengths of two legs of a triangle and add them together to find the squared length of the hypotenuse of a triangle. In order to derive the distance formula, create a triangle. You are trying to find the distance between two points of a line segment. This is the hypotenuse of a triangle. Calculate the square root of the sum of the lengths of the legs of the triangle in order to find the length of the line segment.
What part of a triangle could you assume line segment RSΒ―Β―Β―Β―Β―
creates in order to use the distance formula to solve for the distance between points R(β5,8)
and S(3,β4)
on a coordinate plane?
The distance formula could assume RSΒ―Β―Β―Β―Β―
is the hypotenuse of a triangle.
What is the distance between the points Q(β2,4)
and P(7,β2)
, to the nearest tenth? Use the distance formula to find your answer. Show your work.
d=====((β2)β7)2+(4β(β2))2ββββββββββββββββββββββ(β9)2+62ββββββββββ81+36βββββββ117ββββ10.8
adjacent sides
two sides of a polygon that share a common vertex
perimeter
the continuous line forming the boundary of an enclosed geometric figure
vertex
the point where two adjacent sides of a polygon meet; the plural of vertex is vertices
How to find the perimetor od a paralleogram
since parallelograms have opposite sides that are equal in length, you need only find the length of a pair of adjacent sides to know the lengths of all four sides. The perimeter of a parallelogram is the sum of 2 times one side length and 2 times the adjacent side length.
How can you calculate the perimeter of a polygon on a coordinate plane given the coordinates of its vertices?
If you know the coordinates of the vertices of the polygon, you can graph them on a coordinate plane. Then, calculate the distance of each line segment that make up the perimeter of the polygon. Add all of these distances together to find the perimeter.
What is the perimeter of the triangle with vertices A(β2,β2)
, B(3,1)
, and C(1,β3)
? If needed, round each side length to the nearest tenth.
AB====β(3β(β2))2+(1β(β2))2ββββββββββββββββββββββ52+32βββββββ25+9ββββββ34βββ5.8
BC====β(1β3)2+((β3)β1)2βββββββββββββββββββ(β25)2+(β4)2βββββββββββββ4+16ββββββ20βββ4.5
AC====β(1β(β2))2+((β3)β(β2))2ββββββββββββββββββββββββ32+(β1)2ββββββββββ9+1βββββ10βββ3.2
Perimeter = 5.8 + 4.5 + 3.2 = 13.5