Unit 4: Congruent Triangles PART 2

Question 1

median

Answer 1

a segment from a vertex to the midpoint of the opposite side

Question 2

altitude

Answer 2

the perpendicular segment from a vertex to the line containing the opposite side

Question 3

perpendicular bisector

Answer 3

a segment/line/ray perpendicular to a segment @ its midpoint

Question 4

perpendicular bisector theorem

Answer 4

if a point lies on the perpendicular bisector of a segment, then the point is equidistant from the segment’s endpoints

Question 5

perpendicular bisector theorem converse

Answer 5

if a point is equidistant from the endpoints of a segment, then the point lies on the segment’s perpendicular bisector

Question 6

angle bisector property theorem

Answer 6

if a point lies on the bisector of an angle, then the point is equidistant from the angle’s sides

Question 7

angle bisector property theorem converse

Answer 7

if a point is equidistant from an angle’s sides, then it lies on the angle’s bisector

Question 8

the distance between a point and a line

Answer 8

is the shortest AND the perpendicular distance from the twp\o

Question 9

circumcenter

Answer 9

• intersection of each side’s (of a triangle’s) perpendicular bisector
• center of the circumcising circle that goes through the vertices
• equidistant from all vertices

Question 10

incenter

Answer 10

• intersection of all the angle bisectors (of a traingle’s) of the angles
• center of the inscribing circle tangent to the sides
• equidistant from all sides

Question 11

midpoint formula

Answer 11

(x1+x2)/2 , (y1+y2)/2

Question 12

distance formula

Answer 12

AB = square root of (x-x1)^2 + (y1-y2)^2

from midpoint to endpoint of segment! not endpoint to endpoint!