Unit 2 | Topics: Solubility, Complex Ions | 17-18 Flashcards
solubility
the amount of solid that must dissolve to produce a saturated solution
precipitation
when and how much solid will precipitate out of solution
solubility product Ksp
equilibrium constant for equilibrium established b/w a solid solute and its ions in a solution
saturated solution
a solution with the maximum conc of dissolved ions with the solution in contact with extra..
determining Ksp from solubility
- calculate molar solubility (mol/L) - use molar mass to get mol
- ICE table
- Ksp = [products]^corresponding stoich coff
determining solubility from Ksp
- make ice table
- solve for s
comparing solubilities
if salts being compared dissolve into SAME number of ions, then their Ks values can be directly compared to predict their relative solubilities
if compared DIFFERENT number of ions, solubilities must be calculated explicitly, then compared
Precipitation: If
Q> Ksp
Q<Ksp
Q=Ksp
Q> Ksp - rxn proceeds, left (rev) precipitation occurs
Q<Ksp - right (fwd), no percipitation
Q=Ksp - saturated (at equilibrium) no change
Soluble salts
- nitrates (NO3-) salts
- Alkali Metals (K+, Na+) and ammonium salt NH4+
- Chloride, Bromide, Iodide except with: Ag+, Pd2+, Hg22+
4.Sulfate (SO42-) except with Sr2+, Ba2+, Pb2+, Hg22+
Insoluble (or very weakly soluble)
- OH, Hydroxide, except Group 1 and NH4+ salts
- Sulfide (S2-) except Group 1 and NH4+ salts
- Carbonate (CO32-) except Group 1 and NH4+ salts
- Phosphate (PO43-) except Group 1 and NH4+ salts
example: KCl and BaSO4
soluble, sparingly soluble (respectively)
Predicting Precipitation formation
- Write a balance equation and determine the solubility of all species
- Calculate Q, determine initial concentrations of the insoluble species
3.if Q>Ksp = precipitate will form
Selective Precipitation
mixtures of 2 or more ions can be separated by using a reagent that will form a precipitate with only one of the ones