Unit 1: Chapters 1-4 Flashcards
Density equation
D= m/v
Specific gravity equation
Units?
S.G. = Dsolute/DH2O
NO UNITS
High specific gravity has large quantities of proteins in (solutes/solvent-water) than (solutes/solvent-water)
in solutes-salts/sugar/proteins than solvent-water
Low specific gravity has much more (solutes/solvent-water) than (solutes/solvent-water)
much more solvent-water than solutes-salts/sugar/proteins
Low specific gravity is close to __’s density
water’s density
Elements are __ substances
pure substances
Compounds are __ substances
pure substances
Mixtures are a __ combination
physical combination
Homogeneous mixtures are
mixed so well you CANNOT distinguish the different components visually
In heterogeneous mixtures you (can/can’t) …
you CAN distinguish the components but may need a microscope
Heterogeneous mixture examples
blood, milk
Physical properties are
properties that can be observed WITHOUT changing the identity of the substance under observation
Physical property examples
temp at which a substance changes state (boiled water is still water), size, malleability, conductivity, density, etc.
Chemical properties can only be observed…
DURING a change in the identity of the substance under observation
Chemical property examples
a chemical might be corrosive, combustible, explosive, etc.
Physical change is
a process that does NOT change the identity of the substance under observation (just a change in physical state)
Physical change examples
melting, boiling, grinding, etc.
Chemical change is
a process that DOES change the identity of the substance under observation
The formation of a new compound in chemical changes are also called
Reactions
Chemical change examples
rusting, tarnishing, burning, etc.
Temperature equation for ℃ and ℉
5F= 9C+160
Temperature equation(s) for ℃ and K
K-273= C C+273= K
Absolute zero= _ K
K (is/isn’t equal to) negative values
Absolute zero= 0 K
K ≠ negative values
Specific heat definition
the amount of heat required to raise the temperature of 1 gram of a substance 1℃
Specific heat equation (written)
Specific heat = amount of heat energy/mass × change in temp
Specific heat equation (with coefficients)
Cp = Q/m • ∆T
Q = m•Cp•∆T ∆T= Tfinal - Tinitial
Specific heat coefficients: Cp= Q= m= ∆T=
Cp= specific heat Q= amount of heat m= mass ∆T= change in temp
Specific heat units
J/g • ℃ or cal/g • ℃
Specific heat units of water
4.184 × J/g • ℃ = 1.0cal/g • ℃