Ultrasound Etc Flashcards
Unit of acoustic impedance
Rayl (Ry)
Acoustic impedance (Z) equation
Acoustic impedance (Z) = Medium density (p) x Ultrasound velocity in medium (v)
Wave equation
Velocity (v) {m/s-1}= Frequency (f) {Hz} x Wavelength (lamda) {metres}
High frequency waves
-Shorter wavelengths
-Higher interaction with materials and so it loses energy (attenuation)
What are higher frequency waves used for
To detect smaller features inside the body
Attenuation of ultrasound
I=I0e^-mewx
-I=Intensity (Watts, Joules)
-I0=original intensity
-mew=attenuation coefficient
-x=distance travelled
B scans
-Brightness scan
-Gives 2D image based on A scan information
-Built up from many A scans
A scan
-Amplitude scan
-Gives numeric information
Doppler effect
The artificial modification in apparent wavelength due to relative motion between source and observer
Key bits in discharging tube
-Cathode
-Evacuated chamber
-Vaccum
-Bevel anode with tungsten target
-Voltage
-Electron beam
-Protective lead shield
Cathode in discharging tube
Gives out electrons which are attracted to anode
Evacuated chamber
The air is removed to prevent collisions (energy loss) between electrons and air molecules
High voltage
To give electrons enough energy to leave the cathode
Bevel anode
Forces x-rays to exit the evacuated envelope
Electron beam
High energy electrons, energised off the cathode, accelerated across potential difference gap & strike tungsten target with high kinetic energy
What is the potential difference between electrodes
Approximately 150kV
What happens in x-ray (discharge tube)
Electrons are accelerated via high voltage from the cathode and pass through the potential difference gap, strike the bevel anode and slow down. The energy loss is converted to x-rays