Radioactivity Calculations/Units Flashcards

(34 cards)

1
Q

Speed of light

A

3x10^8 m/s

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2
Q

How do you calculate binding energy in Joules

A

Energy=Mass(Kg) x (Speed of light)^2

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3
Q

How to calculate Mass defect

A

Mass of component parts (Kg/u) - Mass given in question (Kg/u). If in u, convert to Kg to find binding energy

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4
Q

What does t stand for in decay equation

A

Time elapsed

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5
Q

What does No stand for in decay equation

A
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6
Q

Isotope definitely

A

Different form of the same element with same number of protons but different number of neutrons

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7
Q

What does the mass number tell us

A

Identifies the element

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8
Q

What does the atomic mass number tell us

A

Identifies the isotope of an element

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9
Q

Converting years into seconds

A

x60x60x24x365

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10
Q

What is the binding energy per nucleon

A

The energy required to break down the nucleus into its constituent parts

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11
Q

What is the relation between the stability of an isotope and their binding energy/nucleon

A

The higher the binding energy, the more stable the nucleus.

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12
Q

What energy level does Lymaan drop to

A

Drops to n=1

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13
Q

What energy level does Bahmer drop to

A

N=2

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14
Q

What energy level does Peschan drop to

A

3

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15
Q

What spectrum is Lymaan

A

Ultraviolet

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16
Q

What spectrum is Bahmer

A

Visible light

17
Q

What spectrum is Peschan

18
Q

Which of the three energy levels requires the most energy and why?

A

Lymaan as it takes a lot more energy to drop all the way down to n=1

19
Q

Turning …x10^-7 to nanometres

20
Q

E=mc^2 what is c?

A

Speed of light

21
Q

Stable nucleus

A

Even number of protons and neutrons
More protons means means more electrostatic repulsion force so more neutrons are needed to stop this.

22
Q

Unstable nucleus

A

Too many protons and not enough neutrons to stop electrostatic force of repulsion

23
Q

Why radioactive decay occurs

A

A nucleus is unstable and wants to become more stable so it must get rid of either a proton or a neutron to stabilise it.

24
Q

Proton number

25
Convert lamda to nano meters
X10^9 (-9)
26
Nano to mew(micro)
/1000
27
Plank’s constant
6.63x10^-34
28
Frequency unit
Hz
29
H
Plank’s constant
30
Metres to nano metres
x10^-9
31
Steps for wavelength transition calculations
Energy change, f=e/h, lambda=speed of light/f, convert to nm x10^-9, state spectrum
32
Discrete (whole number) energy levels
Because the electrons in an atom can only occupy certain, specific energy levels or orbitals, so they emit
33
characteristic spectra of elements (frequency and wavelength)
produced when the electrons in an atom or molecule transition between specific energy levels
34
why the visible emission spectrum of hydrogen has only a few lines
Hydrogen has one electron and most transitions