Radioactivity Calculations/Units Flashcards

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1
Q

Speed of light

A

3x10^8 m/s

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2
Q

How do you calculate binding energy in Joules

A

Energy=Mass(Kg) x (Speed of light)^2

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3
Q

How to calculate Mass defect

A

Mass of component parts (Kg/u) - Mass given in question (Kg/u). If in u, convert to Kg to find binding energy

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4
Q

What does t stand for in decay equation

A

Time elapsed

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5
Q

What does No stand for in decay equation

A
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6
Q

Isotope definitely

A

Different form of the same element with same number of protons but different number of neutrons

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7
Q

What does the mass number tell us

A

Identifies the element

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8
Q

What does the atomic mass number tell us

A

Identifies the isotope of an element

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9
Q

Converting years into seconds

A

x60x60x24x365

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10
Q

What is the binding energy per nucleon

A

The energy required to break down the nucleus into its constituent parts

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11
Q

What is the relation between the stability of an isotope and their binding energy/nucleon

A

The higher the binding energy, the more stable the nucleus.

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12
Q

What energy level does Lymaan drop to

A

Drops to n=1

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13
Q

What energy level does Bahmer drop to

A

N=2

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14
Q

What energy level does Peschan drop to

A

3

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15
Q

What spectrum is Lymaan

A

Ultraviolet

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16
Q

What spectrum is Bahmer

A

Visible light

17
Q

What spectrum is Peschan

A

Infrared

18
Q

Which of the three energy levels requires the most energy and why?

A

Lymaan as it takes a lot more energy to drop all the way down to n=1

19
Q

Turning …x10^-7 to nanometres

A

x10^9

20
Q

E=mc^2 what is c?

A

Speed of light

21
Q

Stable nucleus

A

Even number of protons and neutrons
More protons means means more electrostatic repulsion force so more neutrons are needed to stop this.

22
Q

Unstable nucleus

A

Too many protons and not enough neutrons to stop electrostatic force of repulsion

23
Q

Why radioactive decay occurs

A

A nucleus is unstable and wants to become more stable so it must get rid of either a proton or a neutron to stabilise it.

24
Q

Proton number

A

Z

25
Q

Convert lamda to nano meters

A

X10^9 (-9)

26
Q

Nano to mew(micro)

A

/1000

27
Q

Plank’s constant

A

6.63x10^-34

28
Q

Frequency unit

A

Hz

29
Q

H

A

Plank’s constant

30
Q

Metres to nano metres

A

x10^-9

31
Q

Steps for wavelength transition calculations

A

Energy change, f=e/h, lambda=speed of light/f, convert to nm x10^-9, state spectrum

32
Q

Discrete (whole number) energy levels

A

Because the electrons in an atom can only occupy certain, specific energy levels or orbitals, so they emit

33
Q

characteristic spectra of elements (frequency and wavelength)

A

produced when the electrons in an atom or molecule transition between specific energy levels

34
Q

why the visible emission spectrum of hydrogen has only a few lines

A

Hydrogen has one electron and most transitions