transcriptional circuits Flashcards

1
Q

define transcriptome

A

The segment that is transcribed

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2
Q

what are the 4 levels of gene transcription

A
  • abundant transcript ( gene gives rise to many mRNA transcripts). If one in every cell this is called a housekeeping gene ( e.g glycolytic enzymes ) - genes that are required for the functioning of all cell types
  • no transcript - not expressed or expressed in low levels.
  • • Rare transcript -may not be expressed in one cell type, however it can be highly expressed in another tissue

• Rare or no transcript - stimulus - abundant transcript.

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3
Q

what is an inducible gene

A

gene that becomes abundantly expressed in response to a stimulus such as hormones or viruses.

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4
Q

what is a promotor

A

The sequence immediately 5’ to the region to be transcribed is called a “promoter”
•Promoters recruit RNA polymerase to a DNA template

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5
Q

what is an enhancer

A
  • Sequences of DNA that are not immediately adjacent to where transcription starts that act to enhance the recruitment of RNA polymerase to a promoter
  • Enhancers can reside 5’ or 3’ to a transcription unit, and can even be located within an intron
  • Like promoters, enhancers contain DNA sequences that are very strong binding sites for specificity factors or “transcription factors”
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6
Q

what happens when RNA is recruited.

A
  • Neither prokaryotic nor eukaryotic RNA polymerases make stable contacts with DNA – they slide along the duplex without being able to efficiently recognise promoters
  • Once stably recruited to DNA, RNA polymerase is able to convert the DNA from a closed to an open complex
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7
Q

describe the prokaryotic promotors

A
  • Sigma factor recognises the -35 and -10 motifs common to prokaryotic promoters and enables RNA polymerase to make stable contacts with DNA.
  • The region at -10bp called the pribnow box, there is also a region at -35 base pairs.
  • The first nucleotide that is copied and transcribed into an RNA molecule will be +1. Nucleotides upstream of +1 will have a negative number.

– Binding of the sigma factor to the part of the promotor that will then recruit the RNA polymerase to the region of the promotor and start site of transcription.

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8
Q

what is a consensus sequence

A

the sequence that you are most likely to find if you are studying a new promotor. It is the calculated order of most frequent residues found at each position in a sequence alignment.

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9
Q

what is meant by the ability of the sigma factor and tfII to recruit RNA polymerase is generic

A
  • it occurs at every promotor

- it does not account for the ability to vary the level of transcription

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10
Q

what are regulatory transcription factors

A
  • regulatory changes are mediated by regulatory TFs.
  • •In both prokaryotes and eukaryotes they function to dramatically alter the level of recruitment of RNA polymerase and/or its ability to initiate transcription
    •Additionally, in eukaryotes they can influence local chromatin structure
  • they recognise and binds to specific DNA target sequences, and do not need to unwind the DNA to see their target.
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11
Q

what is a prokaryotic transcriptional switch

A

The lac operon

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12
Q

give 3 examples of a eukaryotic transcriptional switch

A

–Oestrogen-responsive transcription
–Tissue-specific transcription (b-globin)
–A complex regulatory circuit (cell cycle)

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13
Q

define an operon

A

clusters of genes that share the same promotor and are transcribed as a single large mRNA that contains multiple structural genes. a genetic regulatory system

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14
Q

what is the on/off switch in a lac operon and what tf binds to it

A

operator - repressor.

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15
Q

what is the lac operon in ecoli designed to do ?

A

breakdown lactose.

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16
Q

what is the function of the lac operon

A

In bacteria, when there is a glucose and lactose, they always prefer to utilise glucose as a source of energy, as it has more energy. so therefore, if cells are in the presence of both glucose and lactose, the lac operon would be silenced and will not utilise lactose.

17
Q

what happens if there are low levels of glucose

A

if there are low levels of glucose, bacteria will try to utilise lactose if it is present in the media. In response to the absence of glucose/ low glucose levels, the CAP protein becomes active and binds to the promotor of the lac operon.

18
Q

what happens in the absence of lactose and low glucose levels

A

The lac repressor is another transcription factor that binds to this DNA sequence in the promotor. This gene is not expressed because it would be a waste of energy to express these enzymes if there is no lactose available. It is silenced as the cap protein which intends to recruit the sigma factor and RNA pol II but cannot transcribe the RNA molecule because of the lap repressor.

19
Q

what happens in the presence of lactose

A

In the presence of lactose, the lactose can bind to the protein and as a result the lac repressor is released from binding the DNA. This allows the cap to recruit the RNA polymerase and express the genes which will utilise the lactose as a source of energy.

20
Q

when is the cap protein active

A

low glucose concentrations

21
Q

+ Glucose, +lactose –>

A

OPERON OFF because CAP not bound

22
Q

+glucose, -lactose –>

A

OPERON OFF both because lac repressor bound and because CAP not bound.

23
Q

-Glucose, -lactose –>

A

OPERON OFF because lac repressor bound.

24
Q

-Glucose, +lactose –>

A

operon on – RNA is transcribed.

25
Q

what are the properties of transcriptional switches in eukaryotes ?

A
  • Regulatory sequences recognise their target sequences by interacting with the DNA
  • They do not have to unwind the DNA double helix to see their target
  • Therefore, an intact DNA molecule can present information to the cell.
26
Q

what is the regulatory element

A

needed to regulate recruitment of RNA polymerase.

27
Q

how do regulatory transcription factors activate transcription ?

A

Eukaryotic regulatory transcription factors activate transcription by stimulating recruitment of general transcription factors and RNA polymerase.

28
Q

explain how steroid hormone signalling can regulate transcription

A
  • Steroid hormones are lipophilic which means they can cross membranes and do not need a receptor
  • Inside cells, the receptor for the steroid hormone is located in the cytoplasm,
  • As a result of the steroid hormone binding to the receptor proteins, it changes the confirmation of the proteins and are competent to be translocated into the cell nucleus.
  • In the cell nucleus, the hormone receptor complexes will now bind to specific regions in the promoters of the genes that will be transcribed in response to their binding.
  • This results in the transcription into an Mrna molecule which is transported to the cytoplasm where the hormone receptor responsive genes are translated.
29
Q

what are the steps in oestrogen controlled portein synthesis

A

oestrogen crosses cell membranes and it will bind to the free oestrogen receptor complex in the cytoplasm, because of this binding the complex will translocate into the nucleus. The complex will start scanning all the genomic DNA for oestrogen responsive elements that are upstream of the oestrogen responsive genes.
As a result of this binding, it will recruit TFIID, TFIIB and this will recruit very efficiently RNA pol II.
All the genes that contain the sequences in their promoters will be transcribed.

30
Q

what is tamoxifen

A

drugs used in the treatment of breast cancer. It competes with oestrogen for binding to the oestrogen receptor. When it binds, it is unable to recruit RNA pol II to the oestrogen responsive genes and the expression of the gene will be silenced.

  • Breast cancer dependent on the presence of oestrogen for growth. This is because some of the oestrogen responsive genes code for proteins involved cell proliferation. Inhibiting this process in breast cancer, inhibits cell proliferation
31
Q

describe the tissue specific transcription of the beta globin gene.

A

Beta globin gene, in the promotor has binding sites for transcript factors GATA-1, (3x). In the enhancer sequence, located distally to the transcriptional unit, it also has a high concentration of sequences which can be recognised by GATA-1. (4x)
Gata-1 is only expressed in cells that will be differentiated into rbcs, therefore we have a high expression of Beta globin gene only in RBCs because they are expressing the GATA-1 transcription factor. It is not expressed in other tissues because they don’t express the GATA-1 transcription factor.

The promotor also binds to ubiquitous factors (CP1, NF1, SP1) which induce the expression of the beta globin gene when the blood cells start to differentiate to RBC, leading to a very high expression in rbc due to GATA-1

32
Q

how are the phases in the cell cycle regulated

A
  • G1 phase is regulated by the mitogenic signal- signal that tells the cell to start cell division.
  • In the cycle, s, g2, and m phase are insensitive to regulation by external signals/ Stimuli
33
Q

How is the G1 phase regulated at the level of transcription?

A

Transitions through the cell cycle are regulated by CDKs which target transcription factors by phosphorylation. Key event in G1/S transition is the transcriptional activation of genes that encode proteins involved in DNA replication.

34
Q

what are the genes required for entry to the s phase and how are they regulated.

A
  • The promotors for G1/S transition genes are activated by a factor called E2F.
  • Genes code for proteins that are required for the synthesis of DNA eg DNA polymerase, DHFR, ribonucleotide reductase, thymine kinase – enzymes that are responsible for producing enough nucleotides for dan synthesis. Only expressed in the s phase.

-tatabox and e2f sites

35
Q

how are the genes that are required for entry to the s phase repressed.

A
  • E2F activity is repressed in G0 and early G1 by the product of the retinoblastoma gene (pRB)
  • Retinoblastoma gene is a tumour suppressor gene. When mutated, it causes tumours.
  • Retinoblastoma binds to E2F, as a result it forms a complex at the promotor of the genes. This complex is not competent for binding and recruiting rna pol II, therefore the gens are not expressed.
  • If the cells receive mitogenic stimulus, it will activate the cdks. The kinases are enzymes that phosphorylate the substrate proteins, and one of the substrates of the ckds that’s stimulated by the mitogenic stimuli is retinoblastoma protein.
  • The cdks phosphorylate the retinoblastoma protein, which can now no longer bind to E2F and is released from the E2F.
  • E2F WILL BE ABLE TO RECRUIT RNA PL II TO ACTIVATE THE EXPRESSION OF THE GENES.
36
Q

what is retinoblastoma and why is it a common target in cancer.

A
  • Retinoblastoma inhibits E2F expression of genes that will allow the cells to proceed from the G1 to S phase. Therefore cells not dividing
  • If received mitogens, the retinoblastoma is phosphorylated and it will detach from EF2 allowing the cells to progress through the cell cycle.
  • Retinoblastoma protein is either not expressed or is actually mutated  it cannot bind to E2F  e2F is constantly active so the cells are always undergoing G2 specialisation and dividing  tumours
  • Viral infection can transform the cells – the cells become cancerous. Viruses express viral proteins that compete for binding to the retinoblastoma protein. – rb unable to bind to E2F because it cannot be supressed.
37
Q

The recognition of promoters is mediated by initiation factors. What are these factors in prokaryotes?

A

→It is the sigma factor, which recognises the -35 and -10 motifs common to prokaryotic promoters.

38
Q

The recognition of promoters is mediated by initiation factors.

What are these factors in eukaryotes?

A

It is the TF2 basal transcriptional machinery (TF2A, TF2B, etc.).