Enzymes Flashcards

1
Q

give some examples of enzyme functions

A

o Digestion : carbohydrates, fats, proteins
o Blood clotting: fibrin clot catalysed by thrombin
o Defence-immune system-activation of complement
o Movement: muscle actomyosin is in ATPase
o Nerve conduction: membrane pumps for Na+, K+, Ca++

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
2
Q

How do we usually categorise enzymes and give some examples

A
We usually categorise enzymes according to the particular type of reaction they catalyse eg:
o	Proteases( break down proteins), nucleases( nucleic acids), polymerases ( form polymers), Kinases ( transfer phosphate groups).
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
3
Q

enzyme defects cause disease. give three examples of inherited diseases involving an amino acid, a sugar and a complex lipid.

A

o Phenylketonuria: patient lacks a liver enzyme which converts Phe to Tyr. Therefore, levels of phenylalanine, if left untreated rise in the body and the breakdown products can poison and impair the development of the brain. Treatment: phenylalanine deficient diet – the levels can be contolled
o Glycogen storage disease- lacks an enzyme which mobilizes glucose from glycogen. It cannot stabilise glucose
o Tay-sachs disease-defect which prevents processing of a membrane ganglioside-neuronal damage and death

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
4
Q

give some examples of enzymes as drug targets.

A

o Antibiotics: eg penicillin inhibit cell wall synthesis
o Anti-inflammatory agents: aspirin blocks prostaglandin synthesis
o Anti-cancer drugs : methotrexate is a folate analogue : interferes with synthesis of DNA precursors required for DNA synthesis in cancer cells, blocking the replication of cancer cells.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
5
Q

outline the key properties of an enzyme

A

o Increase reaction rate by up to 10 billion fold.
o Show specificity
o Unchanged at end of reaction
o Do not alter equilibrium
o Facilitate reaction by decreasing the free energy of activation of the reaction.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
6
Q

How do enzymes speed up reactions by?

A

reducing delta G

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
7
Q

what is the free energy of activation delta G dagger?

A
  • The free energy of activation delta G is the difference in free energy between the substrate and the transition state.
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
8
Q

describe how enzymes speed up reactions by reducing delta G

A
  • Free energy of the substrate is higher than the free energy of the product. Therefore from substrate to product there is a release of free energy. This means that the reaction is thermodynamically favourable and can proceed.
  • However, just because its thermodynamically favourable does not mean it will take place. This is because from substrate to product, energy is required to go into the system.
  • In the uncatalyzed reaction, energy is required to push the system over the transition state (point of highest free energy) so that it can form the product. The free energy of activation is high
  • In the catalysed reaction, the enzyme can reduce this energy barrier so that the free activation is lower and therefore we can put less energy into the system for the reaction to occur.
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
9
Q

what is an active site

A
  • The active site is a 3-D cavity or cleft that binds substrate(s) with specificity through electrostatic, hydrophobic, hydrogen bonding and van der Waals interactions.
  • In the enzyme catalysed reaction, the Formation of an enzyme-substrate (ES) complex at the active site is the first step in enzyme catalysis. Not available in the uncatalyzed reaction
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
10
Q

where does evidence for active sites come from?

A
  • X-ray crystallography (usually done at synchrotrons-Diamond, Oxford) – used to determine the structures of enzymes and enzyme substrate complexes.
  • Kinetic studies of enzyme activity (simpler and quicker than crystallography).
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
11
Q

describe how structure of a protein is determined by x-ray crystallography

A
  • Technique where you purify a large amount of your enzyme or protein of interest.
  • You crystalise the protein and place the crystal in the path of a powerful x-ray beam
  • The molecules in the crystal diffract the x-ray beam, and you can record the diffraction pattern, which consists of a series of spots in various positions and have varying intensities.
  • Allows you to deduct the structure of the individual molecules in the crystal.
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
12
Q

describe the structure of the human RAS protein and include how we were able to observe this.

A
  • Ras is found in the inner face of the plasma membrane and acts as a switch between the membrane and the nucleus and signals the cell to grow.
  • Its structure is that of a protein made out of Beta sheets and alpha helices. It has GTP bound to its active site.
  • Therefore x ray crystallography enables us to see the structures of the enzyme substrate complexes.
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
13
Q

what has studying the structures of enzymes enabled us to distinguish?

A
  • Studying the structures of enzymes have enabled us to distinguish between the two alternative models of how a substrate binds to the active site on an enzyme
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
14
Q

describe the lock and key theory

A
  • The lock and key theory : the active site of the enzyme is directly complementary to the structure of the substrate and comes together to form the ES complex.
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
15
Q

describe the induced fit theory

A
  • The induced fit theory: the enzyme active site is not directly complementary to the structure of the substrate. As the substrate beings to bind to the active site, the enzyme changes its shape so that the active site does become complementary to that of the structure of the substrate.
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
16
Q

give an example of a protein that undergoes induced fit binding

A

the induced fit binding of glucose to hexokinase

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
17
Q

describe the binding of glucose to hexokinase

A

o Hexokinase is an enzyme involved in the early stages of glycolysis.
o The enzyme has a lobular structure
o Through x-ray crystallography, we can get the structure of the hexokinase enzyme alone, and we can also get the structure of the hexokinase-glucose ES complex. ( one of its substrates is glucose).So we can compare the two structures that we get from the x-ray crystallography. Ie the complex of the enzyme without the substrate bound to it, and the substrate after once it did.

When glucose binds to it, the two lobes undergo a conformational change and envelopes the glucose. This is evidence that the binding of glucose to hexokinase occurs by an induced fit mechanism.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
18
Q

How do enzymes speed up their reactions?

A

They use the enzyme substrate binding energy when making the enzyme substrate complex. They use this energy to reduce the free energy of activation.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
19
Q

describe in detail the mechanisms through which enzymes speed up the reaction by using the enzyme substrate binding energy

A

1) To bring molecules together in the active site.
2) By constraining substrate movement in a way that they are ideally placed to undergo a reaction.
2) A particular bond in the substrate has to be broken to make the product. So the enzyme strains particular bonds in the substrate making breakage easier in the transition state. Therefore it needs less free energy to reach the transition state when the bond is already strained.
3) Some reactions require the change in the positive and negative charges in the substrate as they are converted to product. An enzyme uses the binding energy to stabilise the positive and negative charges in the transition state.
4) The enzyme can envelope the substrate to exclude water from the active site- make reaction go faster e.g hexokinase
5) To provide an alternative reaction pathway of lower energy e.g., this can be achieved by the enzyme taking place directly in the chemistry of the reaction eg through the formation of the covalent enzyme-substrate intermediate.
6) Use cofactors: bring new chemistry to the active site with NAD(H), FAD(H2), metal ions such as Mg2+. Enzymes can bind cofactors to its active site in addition to the substrate, providing an alternative chemical pathway with a lower free energy of activation.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
20
Q

give an example of how strain is used by an enzyme to speed up its catalytic reaction.

A

Lysozyme uses strain to cleave its bacterial substrate.

  • Lysozyme recognises a component of the bacterial cell wall which is a polysaccharide. It can cleave this polysaccharide and weaken the cell wall of the bacterium such that the strong osmotic pressure inside the bacterium causes its rupture.
  • Lysozyme binds to a portion of the polysaccharide, and in its active site it combines 6 sugars which are present in the polysaccharide. It strains abond between the fourth sugar D and the fifth sugar E. it makes it much easier to hydrolyse the bonds between Sugar D and E and cause a break in the polysaccharide chain and thus weaken the bacterial cell walls.
21
Q

what do enzyme kinetics provide evidence for ?

A

active sites

22
Q

describe the KM

A

substrate concentration at ½ the max rate ( ie ½ vmax).

Km is a measure of the substrate binding affinity.

23
Q

if Km is small, how does the substrate bind?

A

tightly/efficently

24
Q

what is Vmax

A

Vmax: Vmax is the reaction rate when the enzyme is fully saturated by substrate, indicating that all the binding sites are being constantly reoccupied. It is at a point of saturation, which is evidence for active sites.

25
Q

what does Km measure

A

substrate binding affinity

26
Q

what process occurs in enzyme kinetics that provides evidence that enzymes have active sites/

A
  • You take a series of tubes, you put the same amount of enzymes into the tubes, and add increasing amounts of substrates. Measure the initial rate by which the substrate is converted to the product(reaction velocity V) and plot it against the substrate concentrate.
  • The experimental points will fit a curve. Initially the rate increases and then plateus due to saturation, and it tends towards an asymptote. This is V max. this means that in enzyme reactions something is limiting.
  • Limiting at a high substrate concentration means that all enzyme active sites must be filled. Thus you don’t get an increase in rate when you put more substrates. This is evidence that enzymes have active sites.
27
Q

what are used as kinetic parameters ?

A

Vmax and Km

28
Q

what is Vmax/enzyme concentration

A

Turnover number

29
Q

what is the turnover number.

A

Turnover number – max no of substrate molecules handled per active
site per second.

30
Q

values for Km are usually in what range ?

A

Values for Km are usually in the µM to mM range

31
Q

what is the average Kcat for most enzymes ?

A

The

average kcat for most enzymes is ~10 s -1.

32
Q

enzyme kinetics provide evidence for enzyme active sites. But what else can enzyme kinetics be used for?

A

measurements of Km and Vmax can establish whether enzyme inhibitors are competitive or non-competitive.

33
Q

what is turnover number units ?

A

Kcat

34
Q

what are the three types on enzyme inhibition?

A

competitive, non-competitive , allosteric.

35
Q

describe competitive inhibition

A

Inhibitor I competes with substrate S for binding to the enzyme active site forming an inactive EI complex.
In the presence of a competitive inhibitor: Km is increased (it takes more substrate to achieve Vmax/2). However, Vmax is unaltered as the effects of the inhibitor can be competed out at high substrate concentrations.

36
Q

describe non-competitive inhibition

A

Inhibitor I binds at a different site to the active site called the allosteric site and does not compete with substrate S for binding at the active site. Therefore, in the presence of a non-competitive inhibitor, the substrate Km is unaltered; but the Vmax is reduced.
Here the inhibitor does affect the rate of the enzyme reaction.

37
Q

How is enzyme activity regulated in cells?

A
  • Control of gene expression – by regulating the enzyme amount made in the cell e.g lac operon in e.coli where the proteins in the lac operon are only expressed when lactose is present in the medium .
  • Compartmentation: By targeting enzymes to the organelle where they are needed. sequences in enzyme polypeptide chain target enzyme to ER, mitochondrion, nucleus etc
  • Allosteric regulation: a regulatory molecule (acting at a pocket distinct from the active site) changes the enzyme conformation to influence the active site and decrease (or in some cases, increase) enzyme activity. Controls the flux of material through a metabolic pathway.
  • Covalent modification of enzyme: A phosphate group is covalently linked onto a residue on the enzyme . this Changes enzyme shape and activity-phosphorylation
38
Q

In a graph plotted with the lineweave-burk equation what does the Y intercept and X intercept represent?

A

Y intercept= 1/Vmax

x intercept =-1/km

39
Q

How do we control metabolic pathways

A

feedback inhibition

40
Q

describe how feedback inhibition controls metabolic pathway

A

a metabolic pathway starts off with a molecule A and in a series of enzyme reactions, A is converted to an end product Z. It is possible for the end product Z to feedback and inhibit the first enzyme in the metabolic pathway. This forms a feedback inhibition, whereby the end product is regulating its own production.
If there is a suffient number of enzyme reactions, the structure of the end product Z can be very different to the structure of the starting material A. therefore when Z feeds back to inhibit the enzyme that ultilises A, Z will not be able to bind to the active site because its structurally different to A. so Z works by binding to a separate site called the allosteric site.

41
Q

describe in detail an example of allosteric inhibition

A
  • This is an enzyme that takes carbamyl phosphate and aspartic acid and in a series of reactions involving many enzymes are converted to Cytidine Triphosphate, CTP.
  • CTP doesn’t look like the substrates for aspartate transcarbamolyase but CTP is able to inhibit the enzyme and regulate its own production.
  • CTP is an allosteric regulator of this pathway by inhibiting the aspartate transcarbamoylase.
  • Asparatate transcarbamoylase is a multisubunit enzyme complex.
  • The catalytic sites are on the six catalytic subunits, and the regulatory sites are on the regulatory subunits.
  • The complex : 2 hemispheres each of which is made up of three catalytic subunits. The hemispheres are held together by regulatory subunits which carry the allosteric inhibitor sites for CTP.
  • The active sites for the catalytic subunits are on the inside of this complex.
  • The way CTP regulates the activity of the complex is that it binds to the allosteric inhibitor sites on the regulatory subunits and it changes their shape, such that the two hemispheres are brought together and the substrates are prevented from getting to the active sites inside.
  • This shows how the allosteric inhibitor can inhibit the enzyme activity by changing the conformation of the complex
42
Q

outline key properties of allosteric enzymes

A

Multisubunit complexes
Regulatory sites and catalytic sites on
different subunits
Regulation occurs via conformational changes
Exhibit non-Michaelis-Menten kinetics:
V vs S plots are sigmoidal
Involved in feedback inhibition of metabolic pathways

43
Q

describe the two groups of drugs that inhibit the enzyme DNA gyrase

A

Antibiotic novobicin inhibits gyrase
- It competitively blocks the binding of atp to gyrase
- Example of a competitive inhibitor
Fluoroquinolones inhibit DNA resealing by gyrase/topo IV
- Inhibit gyrase and topo IV by a different mechanism to novobiocin
- It binds at the site of DNA breakage by these enzymes and they intercalate into the DNA, preventing the resealing of the DNA.
- Results in the killing of the bacterial cell

44
Q

What is aspartate transcarbamolyase an example of ?

A

allosteric inhibition

45
Q

In non-competitive inhibition, why does increasing substrate conc have no effect?

A

because the inhibitors are not directly competing with the substrates for the active sites.

46
Q

what does a high km mean?

A

a lot of substrate is needed to bind to the active site (high concentration) so the affinity for the substrate is low

47
Q

what happens to Vmax and Km during non-competitive inhibition

A

→the inhibitor binds to the allosteric site.

→V max is decreased but km remains unchanged.

→Less active sites available but the affinity has not changed.

48
Q

what happens to Km and Vmax during competitive inhibition?

A

→V max is the same but Km is increased,

→the reaction can still achieve maximum velocity but you need a lot more substrate to achieve that value.