Transcription in Prokaryotes Flashcards

1
Q

RNA polymerase reads and synthesizes in..

A

reads template in 3’ to 5’ direction and synthesizes from 5’ to 3’

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2
Q

RNA polymerases uses…

A

ribonycleoside triphosphate (atp, gtp) and releases put-phosphate

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3
Q

RNA polymerase does not require a _____ and has no _____

A

primer and no nuclease activity (no proofreading)

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4
Q

RNAP subunits

A
  1. core enzyme

2. Sigma factor

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5
Q

RNAP subunits- Core enzyme structure

A

formed of 5 subunits
2 identical alpha subunits
2 similar beta subunits
1 omega subunit

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6
Q

RNAP subunits- core enzyme activity

A

responsible for 5’ -> 3’ RNA polymerase activity and can’t recognize promotor

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7
Q

RNAP subunits- sigma factor

A

enables RNAP to recognize and bind to promotor by increases the affinity of the enzyme to the promotor

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8
Q

holoenzyme complex

A

core enzyme + sigma factor

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9
Q

sequence of prokaryotic promotor

A

consensus sequence

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10
Q

consensus sequence

A

stable; specific sequence of nucleotides that play same role in different locations in genome

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11
Q

how are consensus sequences recognized

A

RNAP-alpha complex

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12
Q

consensus sequence include:

A
  1. -35 sequence

2. TATA (pribnow) box

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13
Q

consensus sequence; -35 Sequence and location

A

located 35 nucleotides upstream from start point

contains the sequence 5’ TTGACA 3’

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14
Q

consensus sequence; TATA (pribnow) box sequence and location

A

located 10 nucleotides upstream start point

contains sequence 5’ TATAAT 3’

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15
Q

mutation of consensus sequences : -35 sequence and TATA box effects

A

can affect transcription of gene because gene is controlled by mutant promoter

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16
Q

steps of transcription in prokaryotes

A
  1. template binding and formation of preinitation complex
  2. initiation
  3. elongation
  4. termination
  5. Rho (p) dependent termination
  6. rho (p) indépendant termination (intrinsic termination)