Topic 5: Alkenes pt 2 Flashcards

1
Q

The Structure of Alkenes

A

Rotation breaks the π bond

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2
Q

Cis-Trans Isomerism

A

In alkenes,
If they are pointing the same direction then they are cis to one another.

If you have 2 substituents on the opposite directions, they are trans to each other.

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3
Q

The E, Z System of Nomenclature

A

Using cis & trans to name alkenes only works if you have one hydrogen on each of the alkene carbons… if you dont then you have to use a system called the E/Z naming convention.

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4
Q

The E, Z System of Nomeclature

A

High priority on the same side= Z (zusammen… together)

High and Low priority across from one another = E (entgegen…across)

How do you determine a substituent priority?

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5
Q

CAHN, INGOLD, PRELOG SEQUENCE RULES FOR E& Z NOMECLATURE (Step 1)

A

Step 1: First prioritize the groups bonded to the 2 sp2 carbons.
(Relative properties depend first on the atomic # of the atom… not the formula weight of the group) bonded to sp2.

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6
Q

CAHN, INGOLD, PRELOG SEQUENCE RULES FOR E& Z NOMECLATURE (Step 2)

A

Step 2: In the case of a tie, the atomic # of the atoms bonded to the tied atoms are considered next

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7
Q

CAHN, INGOLD, PRELOG SEQUENCE RULES FOR E& Z NOMECLATURE (Step 3)

A

Step 3: If an atom is doubly bonded to another atom, the system creates if it were bonded to 2 such atoms

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8
Q

CAHN, INGOLD, PRELOG SEQUENCE RULES FOR E& Z NOMECLATURE (Step 4)

A

Step 4: In the case of isotopes, the isotope with the greater mass # has the higher priority.

Step 5: If the groups of the highest priority are on the same side of the double bond, name the isomer Z (Zusammen)

Step 6: if the groups of highest priority are on the opposite side of the double bond, name the isomer E (Entgegen)

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