Topic 3 & 4 - Second Order PDEs Flashcards

1
Q

What makes a PDE linear?

A

A PDE is linear when it contains no product of dependent-variable terms.

e.g. y(dy/dx) is a non-linear term, as the derivative tells us that ‘y’ is a dependent variable.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
2
Q

How can non-linear PDEs be solved?

A

Non-linear PDEs cannot be solved analytically, however, they can be solved with numerical methods.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
3
Q

What does a PDE need to be homogeneous?

A

If every term in the equation for a PDE contains the dependent variable in some form, it is homogenous.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
4
Q

Homogeneous or inhomogeneous?

A

Inhomogeneous as not all terms contain the dependent variable.

The constant 1 is what makes the equation inhomogeneous.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
5
Q

Why is a curly d used for PDEs over a regular dx?

A

A curly d is used to communicate that a multivariable function is involved.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
6
Q

What is the significance of this function?

A

Instead of having one variable changing the other, and this being graphed, for this equation every point on the plane is an input.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
7
Q

Does separation of variables work on non-linear PDEs?

A

No, it doesn’t.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
8
Q

What would this non-linear PDE look like if you plugged in u(x,y) = f(x)*g(y)

A

The middle term is not the same as d2u/dx2.

This middle term has two lots of u.

Which is significant as you have to insert u twice. So you end up with one more f(x) and g(y) compared to d2u/dx2.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
9
Q

If the discriminant is positive, what sort of PDE is it?

A

Hyperbolic

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
10
Q

If the discriminant is 0, what sort of PDE is it?

A

parabolic

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
11
Q

If the discriminant is less than 0, what sort of PDE is it?

A

Elliptic

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
12
Q

What sort of PDE is laplace’s equation?

A

Elliptic

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
13
Q

What sort of PDE is the heat equation?

A

Parabolic

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
14
Q

What sort of PDE is the wave equation?

A

Hyperbolic

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
15
Q

What is the general form of a 2nd order Linear PDE?

What is the discriminant function of this equation?

A
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
16
Q

How do you perform partial fraction decomposition?

A
17
Q

What are the equations for the three different cases to solve linear ODEs?

A
18
Q

What do you need to remember about the values found for coefficents (i.e. for A and B) in cases and different BC for linear ODEs?

A

Between cases coefficient values determined are not the kept.

However, within a case for a BC you can use a coeffcient value obtained from a previous/another BC.

19
Q

Could you use partial fraction decomposition directly for this fraction?

A

No you cannot. Partial fraction decomposition only works for ‘proper’ fractions, i.e. the numerators degree is not larger than the denominators degree.

Instead you need to use long division to obtain a new fraction which you can perform partial fraction decomposition on.

20
Q

How do you solve a partial fraction that has a factor in the denominator that occurs more than once?

A

Start solving as you normally would. Plug in values of x to solve coefficients.

For the remaining coefficients that you can’t solve, plug the values you do know in to get an equation of the remaining unknown values.

Depending on the number of unknowns, plug any other x value into the equation to get a system of equations to solve for the unkown coefficients.

21
Q

When you’ve separated your variables solving a linear PDE, how do you decide which equation to solve for first?

A

Go for the one with the simpler boundary conditions.

Boundary conditions equal to zero are easier to solve than ones equal to constants, so start with those.

22
Q

What do you need to remember about admissable values when determining the solution to a separation of variable ODE after already solving the other one?

A

The values of K determined for the general solution of the ODE that has been solved limits the other ODE to those values.

E.g. if kn = (nπ/b)2 for the h(y) general solution, then the solution of g(x) will be limited to those values.

In other words, with K already determined, the other ODE is also equal to this value.

23
Q

What are the relationships between the hyperbolic functions sinh, cosh and tanh to exponentials?

A
24
Q

If you reach this during the solving a PDE, what can you do?

A