Topic 18 Flashcards

1
Q

Bromination of benzene

A
Reactants: benzene, bromine
Reagents: FeBr3 or AlCl3 catalyst
Conditions:
Products: bromobenzene, HBr
Observations: orange to colourless
                         HBr + ammonia = white solid
Reaction: Electrophilic substitution
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2
Q

Nitration of benzene

A
Reactants: benzene, nitric acid
Reagents: concentrated sulfuric acid
Conditions: 50°C
Products: nitrobenzene, water
Observations: nitrobenzene is yellow and oily
Reaction: Electrophilic substitution
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3
Q

Friedel-Crafts alkylation of benzene

A
Reactants: benzene, halogenoalkane
Reagents: AlCl3 catalyst
Conditions: anhydrous, heat under reflux
Products: eg. methyl benzene, HCl
Observations: HCl = misty fumes
Reaction: Electrophilic substitution
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4
Q

Friedel-Crafts acylation of benzene

A
Reactants: benzene, acyl chloride
Reagents: AlCl3 catalyst
Conditions: anhydrous, heat under reflux
Products: phenyl ketone, HCl
Observations: HCl = misty fumes
Reaction: Electrophilic substitution
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5
Q

Phenol + sodium hydroxide

A

Sodium phenoxide and water

Acting as an acid

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6
Q

Bromination of phenol

A
Reactants: phenol, bromine
Reagents: no catalyst needed
Conditions: room temp
Products: 2,4,6 tribromophenol, HBr
Observations: orange to colourless, white ppt, misty fumes
Reaction: Electrophilic substitution
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7
Q

Making amines from halogenoalkanes

A
Reactants: halogenoalkane, ammonia
Reagents: 
Conditions: heat in a sealed tube
Products: 1° amine, HCl
Observations: HCl = misty fumes
Reaction: Nucleophilic substitution

Note: 1° amine reacts with halogenoalkane forming 2° amine and HCl etc.

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8
Q

Making amines from nitriles

A
Reactants: eg. ethanenitrile
Reagents: LiAlH4
Conditions: mix in dry ether
Products: 1° amine
Observations:
Reaction: reduction of nitrile
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9
Q

Making aromatic amines

A
Reactants: nitrobenzene
Reagents: tin metal mixed with conc. hydrochloric acid (reducing agent, 6Hs)
Conditions: heat under reflux
Products: phenylamine and 2 water
Observations: 
Reaction: reduction of nitrobenzene
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10
Q

Making amides

A

Reactants: acyl chloride or carboxylic acid, amine
Reagents:
Conditions:
Products: N-substituted amide, HCl or water
Observations: amine also reacts with HCl formed = white smoke
Reaction: condensation

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11
Q

Order of basicity of amines

A

Least basic
Aromatic amines- The lone pair on the N atom in phenylamine merges with the delocalised electrons in the pi bond, making them less available for donating.
Ammonia
1°/2°/3° amines- The ethyl group is electron releasing, so the N atom has a higher electron density, so the lone pair is more available.

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12
Q

Reaction of 1° amine with water

A

RNH₂ + H₂O ⇌ RNH₃⁺+ OH‾

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13
Q

Reaction of 1° amine with acid

A

RNH₂ + HCl ⇌ RNH₃⁺Cl‾ (white smoke)

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14
Q

Reaction of 1° amine with acid

A

RNH₂ + HCl (g) ⇌ RNH₃⁺Cl‾ (white smoke)

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15
Q

Reaction of 1° amine with copper (II) ions

A

2RNH₂ + [Cu(H₂O)₆]²⁺ ⇌ [Cu(H₂O)₄(OH)₂] + 2 RNH₃⁺
Pale blue precipitate
4RNH₂ + [Cu(H₂O)₄(OH)₂] ⇌ [Cu(RNH₂)₄(H₂O)₂]²⁺ + 2H₂O + 2OH‾
Deep blue solution

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16
Q

Reaction of 1° amine with acyl chloride

A

Acyl chloride + primary amine → N-substituted amide + HCl

then HCl + RNH₂ (primary amine) → RNH₃⁺Cl‾ (salt)

17
Q

Reaction of 1° amine with halogenoalkane

A

1° amine + halogenoalkane → 2° amine + HCl
2° amine + halogenoalkane → 3° amine + HCl
3° amine + halogenoalkane → 4° amine⁺ Cl‾

18
Q

Why are amino acids soluble?

A

They form zwitter ions, which interact with the water

19
Q

Why do solid amino acids have a high melting point?

A

They form zwitter ions with strong ionic bonds

20
Q

Why is phenol more reactive than benzene with bromine?

A

The lone pair of electrons on the oxygen merges with the delocalised system
Increases the electron density of the ring
Increases the susceptibility to attack by the electrophile

21
Q

Why heat under reflux

A

Speed up rate of reaction

Prevent loss of volatile reactants and products

22
Q

What do alcohols, phenols and carboxylic acids react with as acids?

A

Alcohol- metal
Phenol- metal and hydroxides
Carboxylic acid- metal, hydroxides and carbonates

23
Q

Describe the structure of benzene and compare it to the kekule structure.

A

P orbitals overlap sideways forming a pi bond above and below the plane of C atoms.
The pi bond electrons are delocalised around the ring.
Bonding more stable.

24
Q

What is the trend in boiling points of primary to tertiary amines?

A

1- highest
2- lower, N atom in middle of chain, dipole attractions less
3- no H atoms bonded to N atoms, no H bonds!

25
Q

Define zwitterion

A

A molecule containing positive and negative charges but has no overall charge

26
Q

What is the isoelectronic point?

A

The pH of a an aqueous solution at which it is electrically neutral.

27
Q

Hydrolysis of dipeptides

A

Reactants: Dipeptide and water
Conditions: Heat with conc. HCl
Products: 2 amino acids
Observations: forms protonated version of amino acids