things clocked during workshop Flashcards

1
Q

AX
explain signal

A

a is coupled 1 thing

so u get one split

so u get a doublet

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2
Q

AX2
explain signal

A

a is coupled to 2 things

so u split twice

but theyre the same
so they have the same cc which means they will overlap and give a high intensity where they do so.

triplet

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3
Q

AMX

explain signal

A

A is coupled to 2 diff things

2 splits
diff things so diff cc so they dont overlap

doublet of doublets

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4
Q

AMX2

explain signal

A

A is coupled to 3 diff things
one is the same,, 2 are the same

3 things but 2 diff coupling constants

3 splits
1/3 splits will overlap

doublet of triplets

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5
Q

same cc

A

they overlap and itensify the signal

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6
Q

different cc

A

they dont overlap and are separate

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7
Q

how to find the chemical shift

A

the middle of the peaks

use ppm

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8
Q

how to find the cc in hz

A

multipy the ppm difference by the strength of the nmr magnet

ppm x mhz will give the units in hz

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9
Q

if the signals arent symmetric what do we not find

A

we dont find the cc between them bc theyre not coupled together,, theyre 2 different signals

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10
Q

see the signal then what

A

draw the splitting tree
then figure out what split system it is by looking what things overlap etccc

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11
Q

room temp : averaged peaks,, due to what

A

ring flips: axial and equitoril swap

bond rotations

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12
Q

cold temp : more peaks

A

no morw averaging, ring flips and bond rotations slow down

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13
Q

finding coupling constants between multiplet peaks

A
  • draw tree diagram briefly
  • follow the tree diagram peaks and look at the corresponding actul multiplet peaks to find J vlues.
  • look at the first split and follow it down both sides,, following the peaks that correspond to eachother and find the J value that way.

from the first split for J1
from the 2nd splits for J2 and for the last splits for J3 etc!!1

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14
Q

cyclohexane and finding whether we’re looking at a multiplet for a H that is axial or equitorial

A

1H : axial oor equiitorial.

multiplet has 15Hz J, 14.5 Hz J and a 4Hz, J.

u have 2 big J’s (2J and axial axial)
1 small J (axial equitorial)

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15
Q

big j values are due to

A

close proximity: bonds between the 2 things

being both axial // being 180 to eachother.

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