nmr 4 Flashcards
whats the problem with the most abundant carbon - C12
such high abundance but it has a spin quantum umber of i = 0
which means its invisible in nmr
what carbon can we use then
we can use the less abundant carbon - 13C
bc it has an i = 1/2
whats the problem with the 13C carbon that is nmr active bc it has i=1/2
its abundance = 1%
what is receptivity
sensitivity of the nucleus regardless of its abundance
is 13C more or less receptive than 1H
receptivity of 13C is much less than that of 1H
less detectedddd
less sensitive than 1H
overall sensitivity equation
receptivity x abundance
is the precession frequency of 13C less than 1H
yess the precession frequency is lesssss
is 13C nmr run alongside 1H nmr
yessss
similarites between 13C and 1H nmr
the same solvents are used
deuterated solvents are used (ones with Deuterium instead of H - although impurities are still seen).
deuterated solvent examples
C6D6
CDCl3
the C in these solvents is detected
does 13C couple to deuterium
yesss
they couple and coupling pattern can be seen using 2ni+1
if most of the deuterated solvent is deuterium,, the 13C signal will be in the
deutero solvent and not the protio solvent
when 13C couples to deuterium in CDCl3 where will the coupling signal be and what will it be
triplet at 77ppm.
when 13C couples to deuterium in CD2Cl2,, what type of peak will it be
13C couples to the 2 D
so we use 2 for n
so 2 x 2 x 1 + 1
which gives 5,, so theres a quintet
diff between 13C and 1H nmr spectra
13C has a larger range of chemical shift values
between 0 - 220 ppm
can be outside of this range tho.
what reference / standard is used for 13C
tetramethylsilane
TMS
a chem shift of 0
baseline of a spectra that is less sensitive
fuzzy,, kinda zigzag like
what do we expect 13C to be coupled to generally
1H
theyre normally bonded together in molecules
1H is very abundant
1H = i = 1/2
what spin system is C in a methyl group + explain
AX3
a = C
bonded to 3 H’s
gives a quartet (2ni+1)
this range is rlly big so we want to supress coupling for it to look nicer
what do we affect when we want to decouple smt
either change the population difference
make i less than 0 or make it 0 .
what coupling do we want to decouple
the non 13C nucleus by saturating it with ITS resonance frequency
normally saturating the 1H nucleus to supress 13C-1H coupling
if we want to saturate H,, what frequency must be supress it using
H,, we must use its resonance frequency.
if the nuclei is in an excited state,, it cannot couple to other things. this prevents coupling
what is proton decoupled spectra // nmr
where we irradiate the 1H to prevent stuff from coupling to it.
this removes X-H peaks
also called X[1H] nmrrrr
typical chem shift range 0-50
aliphatic
C-C=O
C-N
C- halogen
still heavily shielded