Theoretical Test 2 Flashcards
Lipschitz Continous
Let f : S->R be a function such that there exists a number K such that for all x and y in S we have |f(x)
Uniform Continuity
Let S ⇢ R. Let f : S -> R be a function. Suppose that for any e > 0 there exists a delta>0 such that whenever x,c in S and |x-c|<delta then |f(x)-f(c)|<e
Derivative Definition
Let I be an interval, let f : I->R be a function, and let c be in I. Suppose that the limit L := lim [f(x)-f(c)]/(x-c) exists. Then we say that f is differentiable at c and we say that L is the derivative of f at c and we write f’(c) := L.
Relative Max and Min
Let S ⇢ R be a set and let f : S->R be a function. The function f is said to have a relative maximum at c in S if there exists a delta>0 such that for all x in S such that |x-
Partition Definition
A partition P of the interval [a,b] is a finite set of numbers {x0,x1,x2,…,xn} such that a=xo<xn=b. We write delta(xi)=xi-x(i-1)
Darboux Sums
(lower integral from b to a)f(x) dx := sup{L(P, f) : P a partition of [a,b]}
(upper integral from b to a) f(x) dx := inf{U(P, f) : P a partition of [a,b]}.
Continuity and Integrable functions
Let f : [a,b] -> R be a continuous function. Then f in R[a,b]
Linearity of Integrable Functions
Let f and g be integrable and a be in R.
Then a*f(x) is integrable and you can pull the constant out of the integral.
f+g is integrable and you can split the integrals
Taylor’s Theorem
Suppose f : [a, b] -> R is a function with n continuous derivatives on [a, b] such that f(n+1) exists on (a, b). Given distinct points x0 and x in [a, b], we can find a point c between x0 and x such that f(x)=Pn(x)+f^(n+1)(c)/(n+1)!^n+1
Mean Value Theorem
Let f : [a, b]->R be a continuous function differentiable on (a, b). Then there exists a point c in (a, b) such that
f(b)
Rolle’s Theorem
Let f : [a, b]->R be continuous function differentiable on (a, b) such that f(a) = f(b) = 0. Then there exists a c in (a,b) such that f’(c) = 0
Inverse Function
Let f be a strictly monotone continuous function on an interval I which is differentiable at x0 in I with f’(x0) not = 0. Then the inverse function g is differentiable at y0 = f(x0) and
g’(y0)= 1/f’(x0)
Chain Rule
Let I1,I2 be intervals, let g: I1->I2 be differentiable at c in I2, and
f : I2->R be differentiable at g(c). If h: I1->R is defined by h(x) := (f of g)(x) = f(�g(x))�,
then h is differentiable at c and h’(c)=f’(g(c))g’(c)
cauchy criterion
let f:[a,b]->R be bounded. It is integrable if and only if for all e>0, there exists a partition such that U(P,f)-L(P,f)<e
- choose subinterval size by (b-a)/n
- to solve, take sum from k=1 to n of infimum-supremums
Integrable Definition
f:[a,b]->R be bounded such that lower integral = upper integral. Then it’s Riemann integrable