The Yield of a Reaction Flashcards
what are the three reasons why the mass of a reaction product may be less than the maximum to be possibly obtained
- the reaction may be reversible and so may not be complete
- there are side reactions that lead to unwanted products
- the product may need to be purified which leads to a loss of product
what are the three main factors that the yield of a reaction of a reaction is referring to
- theoretical yield
- actual yield
- percentage yield
what is the difference between how yield is measured in labs and in industry
- in labs, grams would be used as smaller portions are being used
- but in industry, kilograms or tonnes would be used
- as they are reacting substances in very large quantities
how do you calculate theoretical yield
- using the equation
- you calculate the mass of the desired product using some maths
- assuming there is no loss and the reaction is complete
magnesium phosphate is prepared in the reaction 3Mg + 2H3PO4 = Mg3(PO4)2 + 3H2. what is the theoratical yield of magnesium phosphate obtainable from 5.62g of magnesium, given that the Mr of 3Mg = 72 and Mg3(PO4)2 = 262
- you need to find the moles of 3Mg youre working with
- Mr of 3Mg = 72gmol-1
- moles = mass /Mr
- so 5.62 / 72 = 0.078 mols
- Mr of the other one = 262g
- so 262 x 0.078 = 20.4g
this reaction is used to obtain methanol from carbon monoxide and hydrogen: CO + 2H2 = CH3OH. given that he obtains 4.07 tonnes of methanol starting from 4.32 tonnes of CO, what is the percentage yield
- ideally you should convert the tonnes into grams but cba
- Mr of CO = 28g
- moles = mass / Mr
- 4.32 / 28 = 0.154 mols
- Mr of CH3OH = 32g
- 32 x 0.154 = 4.982g
- (4.07 / 4.982) x 100 = 82.4%