Molecular Formulae Flashcards

1
Q

what is the molecular formula of a compound

A

the actual numbers of atoms of each element in a compound

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2
Q

what is the molecular formula of butane if its empirical formula is C2H5

A

C4H10

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3
Q

what do you need in order to determine the molecular formula of a compound

A
  • the empirical formula

- the molecular mass

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4
Q

if the empirical formula of a compound was HO and you know the relative molecular mass of it is 34, how would you calculate its molecular formula

A
  • you would add up the atomic masses of the elements composing the empirical formula
  • in this case it is 1 + 16 = 17
  • you would then divide the total molecular mass of 34 by this number
  • giving you 34 /17 = 2
  • meaning you are multiplying the empirical formula by 2
  • H2O2
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5
Q

what is the disadvantage that comes with using relative molecular masses when calculating molecular formulae

A
  • it cant be used for ionic compounds
  • as the atoms dont have covelant bonds between them
  • therefore it is not a molecule nor does it contain any
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6
Q

what do we use rather than relative molecular mass when we want to work with both covelant and ionic compounds

A
  • relative formula mass

- every compound has a mass that is made up of all the element composing it

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7
Q

what is molar mass and what is its unit

A
  • the mass per mole of any substance
  • it had the units gmol-1
  • its symbol is M
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8
Q

what formula would you use to calculate the amount in moles of a substance

A
  • amount in mol = mass of substance (g) / molar mass (gmol-1)
  • n = m / M
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9
Q

what would be the amount in moles of CH4 if 4g of it was available

A
  • 1 mole of CH4 is 12 + 4 = 16g
  • so the molar mass (mass per mole) is 16g
  • using the formula n = m / M
  • you would have n = 4 / 16
  • = 0.25
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10
Q

a compound contains the composition by mass: Na = 34.3%, C = 17.9%, O = 47.8% and has a molar mass of 134gmol-1. how would you calculate the empirical formula of the compound

A
  • you firstly need to calculate the empirical formula of the compound
  • Ar of Na = 23, C = 12, O = 16
  • you divide the percentage by the Ar
  • 34.3 / 23 = 1.5, 17.9 / 12 = 1.5, 47.8 / 16 = 3
  • simplify those into ratios of 1:1:2
  • giving you the empirical formula NaCO2
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11
Q

using the empirical formula, how would you calculate the relative formula mass of the compound

A
  • the Mr of NaCO2: 23 + 12 + (16 x 2) = 67g
  • of the molar mass = 134gmol-1
  • 134 / 67 = 2
  • 2 x (NaCO2) = Na2C2O4
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12
Q

what is the ideal gas equation (which can also be used for volatile liquids above their boiling temperature)

A

pV = nRT

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13
Q

what is the ideal gas equation used for

A

finding the amount of a substance in moles

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14
Q

what are the SI units you should be using for pV = nRT

A
  • p = pressure (Pa)
  • V = volume (m^3)
  • n = amount in moles (mol)
  • R = the gas constant (8.31Jmol-1K-1)
  • T = temperature (K)
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15
Q

what do you do to convert kPa to Pa

A

multiply by 10^3

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16
Q

what do you do convert cm^3 to m^3

A

multiply by 10^-6 or divide by 10^6

17
Q

what do you do to convert dm^3 to m^3

A

divide by 10^3 or multiply by 10^-3

18
Q

what do you do to convert C to K

A

add 273

19
Q

a 0.280g sample of a gas has a volume of 58.5cm^3 measured at a pressure pf 120kPa and a temperature of 70C. calculate the molar mass of the gas

A
  • pV = nRT rearranged to n = pV / RT
  • p = 120kPA = 120,000Pa
  • V = 58.5 x 10^-6
  • R = 8.31
  • T = 70 + 273 = 343K
  • 120,000 x 58.5 x 10^-6 / 8.31 x 343 = 0.00246
  • n = 0.00246
  • n = m / M
  • M (molar mass) = m / n
  • 0.280 / 0.00246 = 114 gmol-1