The periodic table (elements in period 3) Flashcards
Atomic radius
the distance between the nucleus and the outermost electron of an atom
Trends across the period
- atomic radii decreases
- ionic radius decreases
- general increase in m.p (increases from Na-Si and then decreases after)
- general decrease in electrical conductivity (increases from Na-Al) and then decreases for the other elements)
- period 3 chlorides and oxides become more covalent and their structure shifts from giant ionic to simple molecular + their reactions with water become more vigorous and as a result of this it becomes easier to hydrolyse the chlorides oxides
Across the period, the atomic radii decrease, because:
- number of protons (nuclear charge) and the number of electrons increases by 1 every time you go an element to the right
- shielding effect is the same as the elements in a period all have the same number of shells
- as you go across the period the nucleus attracts the electrons more strongly, pulling them closer to the nucleus
- therefore, atomic radius (and the size of the atom) decreases
Ionic radius
the distance between the nucleus and the outermost electron of an ion
Across the period, the ionic radius decreases, because:
- metals produce + cations, non-metals produce - anions
- cations have lost their valence electrons, therefore smaller than parent atoms as there are less electrons and less shielding of the outer electrons
- anions are larger than original parent atoms as they have gained an electron which increases repulsion between the electrons while the nuclear charge remains the same
Na+ - Si 4+= the ions get smaller due to increase in nuclear charge attracting the outer electrons in the 2nd principal quantum shell
P3- - Cl- = ionic radius decreases as the nuclear charge increases + fewer electrons are gained
Trend in m.p.
general increase in m.p. for the period 3 elements up to silicon (has the highest m.p.) and after silicon the m.p. decreases significantly
Why melting point increases from Na-Al (refer to bonding and sea of electrons)
- Na, Mg, Al are metallic elements which form positive ions arranged in a giant lattice in which ions are held together by a sea of delocalised electrons around them
- Na will donate 1 electron into the sea, Mg 2 and Al 3 and as a result of this the metallic bonding in Al is stronger than in Na
- it is stronger, because the electrostatic forces between the 3+ ion and the larger number of negatively charged delocalised electrons is much larger
Why Si has the highest melting point
due to its giant molecular structure in which each Si atom is held to its neighbouring Si atoms by strong covalent bonds
Why the melting point decreases from P-Ar
- P, S, CI, Ai are non-metallic elements and exist as simple molecules
- the covalent bonds within the molecules (intramolecular forces) are strong, but between the molecules (intermolecular forces) are weak instantaneous dipole-induced dipole forces and it therefore doesn’t take much energy to break them
Melting point from highest to lowest
S8 > P4 > CI2 > Ar
- sulfur has a larger electron density therefore it has a stronger instantaneous dipole-induced dipole forces
Trend in electrical conductivity
- general trend is that it decreases significantly
- increases from Na-Al and then decreases for the other elements
Na-Al
- there is an increase in the number of valence electrons that are donated to the sea of delocalised electrons
- because of this, in Al there are more electrons available to move around and conduct electricity which makes Al a better conductor than Na
Why Si and P are not good conductors
- Si is a giant molecular structure and therefore has no delocalised electrons that can move freely within the structure
- classed as a semi-metal
- P and S cant conduct electricity due to the lack of delocalised electrons
Period 3 elements with oxygen
metal/non-metal + oxygen = metal/non-metal oxide
*all produce a solid except for sulfur (g)
With chlorine
metal + chlorine = metal chloride (vigorous)
non-metal + chlorine = non-metal chloride (slow + forms a liquid product)
Phosphorus forms a mixture of chlorides
* P4 + 6CI2 = 4PCI3
* P4 + 10CI2 = 4PCI5