T 9 REDOX Flashcards
Define oxidation (all)
Loss of electrons (think Zn—>Zn2+ ZnCu voltaic)
Increase in oxidation number
Gain oxygen//loss of hydrogen
Define reduction (all)
Gain of electrons (think Cu2+ —> Cu ZnCu voltaic cell)
Decrease in oxidation number
(Loss oxygen//gain hydrogen)
Why do REDOX reactions occur (in pair always oxidation and reduction)?
Electrons are never lost freely; if a species is oxidized, a species is also reduced
How do you know if a reaction is a redox reaction?
If oxidation states change = redox
If no change of oxidation states = not redox
Oxidation number = Roman numerals
Oxidation state = sign in front of number
All elements in their elemental state have an oxidation state of
ZERO!!
Simple ions have oxidation state equal to
THEIR CHARGE
Oxygen within a compound always has an oxidation state of
-2 (EXCEPT in PEROXIDES, ex H2O2; when it is -1)
Hydrogen within a compound always has an oxidation state of
+1 (EXCEPT in HYDRIDES, ex NaH, when it is -1)
The algebraic sum of all the oxidation states in a compound is
ZERO
The algebraic sum of all the oxidation states in an ion (complex ion)
= the CHARGE OF THE ION
What does the position of a metal/element relative to HYDROGEN in an activity series tell you?
Species/metals ABOVE HYDROGEN REACT W ACIDS —> H2(g)
Those BELOW hydrogen DO NOT FORM H GAS IN REACTION W ACID
What does the position of a metal/element relative to CARBON in an activity series tell you?
Whether it can be reduced by carbon.
If the species/metal is BELOW C it CAN BE REDUCED (ion—>atom) BY CARBON
If it is above, it cannot (eg hydrolysis required)
For this and hydrogen: think in thirds; the particular property (forming H2 when w acid // reduces by carbon) is for those in the 2/3 part.
Oxidation numbers/states are used for:
Naming of compounds
Determining whether a reaction is a redox reaction + what is oxidized/reduced
(To balance redox reactions)
How do you balance/find equation of redox reactions?
Use HALF-EQUATION METHOD
Write the two half-equations
BALANCE CHARGE=ELECTRONS. OXYGEN=WATER. HYDROGEN=H+
Ensure that you have the same amount of electrons in both half equations, if not MULTIPLY THE ENTIRE HALF EQUATION to get same amount electrons
Then add the two half equations together and simplify