T-2: Enthalpy Flashcards
Energy required to break a chemical bond
Bond Energy
Standard states
Phase at 25ºC, 1 atm for gases and 1 M for solutions.
Energy change that occurs when you make one mole of a compound from its constituent elements at standard states
Standard Enthalpy of Formation
The equation to find ΔHº from standard enthalpies of formation
ΔHº = Σ(nΔHºf,prod) - Σ(nΔHºf, react)
The equation to find ΔH from bond energies.
ΔH = Σ(nB.E.broken) - Σ(nB.E.formed)
The amount of energy required to break a chemical bond.
Bond energy
Bond Energy
Energy required to break a chemical bond
Phase at 25ºC, 1 atm for gases and 1 M for solutions.
Standard states
Standard Enthalpy of Formation
Energy change that occurs when you make one mole of a compound from its constituent elements at standard states
ΔHº = Σ(nΔHºf,prod) - Σ(nΔHºf, react)
The equation to find ΔHº from standard enthalpies of formation
ΔH = Σ(nB.E.broken) - Σ(nB.E.formed)
The equation to find ΔH from bond energies.
Bond energy
The amount of energy required to break a chemical bond.
Exothermic or Endothermic
Breaking a covalent bond
Endothermic
Exothermic or Endothermic
Making a covalent bond
exothermic
Exothermic or Endothermic
F2(g) → 2F(g)
endothermic - breaking a bond
Exothermic or Endothermic
2Br(g) → Br2(g)
exothermic - making a bond
Exothermic or Endothermic
Li+(g) + Cl-(g) → LiCl(s)
exothermic - making a bond
Exothermic or Endothermic
NaF(s) → Na+(g) + F-(g)
endothermic - breaking a bond
Write out reaction equation for standard enthalpy of formation for HCl.
1/2H2(g) + 1/2Cl2(g) → HCl(g)
Write out reaction equation for standard enthalpy of formation for CO2.
C(s) + O2(g) → CO2(g)
S8(s) + 8 O2(g) →8 SO2 (g)
Write this reaction as a enthalpy of formation for SO2
1/8 S8(s) + O2(g) → SO2(g)
The ΔHº for the following reaction is…
1/2H2(g) + 1/2Cl2(g) → HCl(g) ΔHº = -92 kJ/mol
What is the ΔHº for this reaction?
H2(g) + Cl2(g) → 2 HCl(g)
ΔHº = - 184 kJ/mol
- multiply reaction by 2 so multiple value by 2
The ΔHº for the following reaction is…
1/2H2(g) + 1/2Cl2(g) → HCl(g) ΔHº = -92 kJ/mol
What is the ΔHº for this reaction?
HCl(g) → 1/2H2(g) + 1/2Cl2(g)
ΔHº = 92 kJ/mol
- reverse reaction so reverse sign
The ΔHº for the following reaction is…
1/2H2(g) + 1/2Cl2(g) → HCl(g) ΔHº = -92 kJ/mol
What is the ΔHº for this reaction?
2 HCl(g) → H2(g) + Cl2(g)
ΔHº = 184 kJ/mol
- reversed the reaction so reverse the sign
- multiplied reaction by 2 so multiple value by 2
The bond energy for O2 (O=O) is 498 kJ/mol. What does that mean?
It takes 498 kJ of energy to break 1 mole of O2 molecules into individual oxygen atoms.
The bond energy for C-H is 439 kJ/mol. How much energy is released when 4 moles of hydrogen atoms bind to 1 mole of carbon atoms?
(439)4 = 1756 kJ are liberated for each mole of CH4 produced in this way.
It takes 872 kJ to break apart 2 moles of H2 molecules to form 4 moles of H atoms. 1756 kJ of energy are liberated when 4 moles of hydrogen atoms bind to 1 mole of carbon atoms. How much energy is liberated/absorbed when 2 mole of H2 molucules combine with 1 mole of C atoms?
ΔH = sum of bonds broken - sum of bonds formed so ΔH = 872 kJ - 1756 kJ = - 884 kJ - Exothermic