survey Flashcards

Question 1

Q

If h is the difference in level between end points separated by l, then the slope correction is h^2 /2L +h^4 /8L^3. The second term may be neglected if the value of h in a 20 m distance is less than

[A]. 0.5 m
[B]. 1 m
[C]. 2 m
[D]. 3 m @

Answer

A

** If h is the difference in level between endpoints separated by l, then the slope correction is c=(h^2/2l)+{h^4/8(l^3)}.

** If h is less than 3m in a length often the 20 m, then the quantity h^4/8(l^3) can be neglected. Hence c = h^2/2l.

Source. Dr. B.C. Punmia.

Question 2

Q

An ideal vertical curve to join two gradients, is

[A].	circular
[B].	parabolic	@
[C].	elliptical
[D].	hyperbolic
[E].	none of these.

Answer

A

A cubic spiral is suitable to cubic parabola but latter is used mostly because of its ease in setting out. Vertical curves are provided to negotiate the gradient of the two straights. Parabola is most suitable shape for vertical curves since it provides a uniform rate of change of gradient and smooth riding condition.

Question 3

Q

Pick up the correct statement from the following :

[A]. the eyepiece plays no part in defining the line of sight @
[B]. the diaphragm plays no part in defining the line of sight
[C]. the optical centre of the objective plays no part in defining the line of sight
[D]. none of these.

Answer

A

Line of Sight: It is line passing through the cross hair and optical centre of objective lens. However Eyepiece only clarifies the cross hair in diaphragm. Thus Eye piece plays no important role in defining the line of sight.

Question 4

Q

The radius of curvature of the arc of the bubble tube is generally kept

[A]. 10 m
[B]. 25 m
[C]. 50 m
[D]. 100 m @

Answer

A

The radius of curvature of the arc of the bubble tube is generally kept

[A]. 10 m
[B]. 25 m
[C]. 50 m
[D]. 100 m @

Question 5

Q

The real image of an object formed by the objective, must lie

[A]. in the plane of cross hairs @
[B]. at the centre of the telescope
[C]. at the optical centre of the eye-piece
[D]. anywhere inside the telescope.

Answer

A

Eye piece used to clear vision of cross hair.

Question 6

Q

In chain surveying tie lines are primarily provided

[A]. to check the accuracy of the survey
[B]. to take offsets for detail survey
[C]. to avoid long offsets from chain lines @
[D]. to increase the number of chain lines.

Answer

A

Check line: check the accuracy of work.

Tie line is the line used to join survey line to features to avoid long offsets. It is used to check for accuracy on chain lines.

Question 7

Q

One of the Lehmann’s rules of plane tabling, is

[A]. location of the instrument station is always distant from each of the three rays from the known points in proportion to their distances @
[B]. when looking in the direction of each of the given points, the instrument station will be on the right side of one and left side of the other ray
[C]. when the instrument station is outside the circumscribing circle its location is always on the opposite side of the ray to the most distant point as the inter-section of the other two rays
[D]. none of these.

Answer

A

Lehmann’s rules

If the position of plane table station is inside the great triangle, its plotted position should be chosen inside the triangle of error.
If the position of the plane table station is outside the great triangle, its plotted position should be chosen outside the triangle of error.
The plotted position of the plane table should be so chosen that its distance from the resistors is proportional to the distance of the plane table station from the field positions of the considered objects.
The plotted position of the plane table should be so chosen that it is to the same side of all the three rays.

4(a). If the position of the plane table station is outside the great circle, its plotted position should be so chosen that
It lies on the same side of the ray to the most distant point as the intersection k of the other two rays.

The intersection of two rays to the nearer points, is midway between the plotted position of the station and the ray to the most distant point.
lehmann+rule+plane+table+survey.

4(b). If the position of plane table station is outside the great triangle but inside the great circle, the plotted position of the station is so chosen that the ray to the middle point lies between plotted station position and the intersection of the rays to the two extreme points.

Question 8

Q

The accuracy of measurement in chain surveying, does not depend upon

[A]. length of the offset
[B]. scale of the plotting
[C]. importance of the features
[D]. general layout of the chain lines. @

Answer

A

Length, Scale and Features are important.

General layout is because it doesn’t matter how we deal with the plan or layout. Measured distance should be accurate.

Question 9

Q

Diopter is the power of a lens having a focal length of

[A].	25 cm
[B].	50 cm
[C].	75 cm
[D].	100 cm	@
[E].	125 cm

Answer

A

1D = 1/f, where f = 100 cm or 1 m.

Question 10

Q

The ‘fix’ of a plane table station with three known points, is bad if the plane table station lies

[A]. in the great triangle
[B]. outside the great triangle
[C]. on the circumference of the circumscribing circle @
[D]. none of these.

Answer

A

We draw lines to the three points and draw circle joining these three points.

So if the station is on the circumference then it maybe difficult to calculate area and degree.

Question 11

Q

If R is the radius of the main curve, θ the angle of deflection, S the shift and L the length of the transition curve, then, total tangent length of the curve, is

[A].	(R - S) tan θ/2 - L/2
[B].	(R + S) tan θ/2 - L/2
[C].	(R + S) tan θ/2 + L/2	@
[D].	(R - S) tan θ/2 + L/2
[E].	(R - S) cos θ/2 + L/2

Answer

A

If R is the radius of the main curve, θ the angle of deflection, S the shift and L the length of the transition curve, then, total tangent length of the curve, is

[A].	(R - S) tan θ/2 - L/2
[B].	(R + S) tan θ/2 - L/2
[C].	(R + S) tan θ/2 + L/2	@
[D].	(R - S) tan θ/2 + L/2
[E].	(R - S) cos θ/2 + L/2

Question 12

Q

In chain surveying field work is limited to

[A]. linear measurements only @
[B]. angular measurements only
[C]. both linear and angular measurements
[D]. all the above.

Answer

A

In chain surveying field work is limited to

[A]. linear measurements only @
[B]. angular measurements only
[C]. both linear and angular measurements
[D]. all the above.

Question 13

Q

While viewing through a level telescope and moving the eye slightly, a relative movement occurs between the image of the levelling staff and the cross hairs. The instrument is

[A]. correctly focussed
[B]. not correctly focussed
[C]. said to have parallax @
[D]. free from parallax.

Answer

A

Parallax is a displacement or difference in the apparent position of an object viewed along two different lines of sight and it is measured by the angle or semi-angle of inclination between those two lines.

Question 14

Q

Accuracy of ‘fix’ by two point problem, is

[A]. bad
[B]. good
[C]. not reliable @
[D]. unique.

Answer

A

Two point problem consists of locating the position of plane table station (fix) on the drawing sheet by observation of two well-defined points. Whos positions have already been plotted on the plan.

Question 15

Q

A bearing of a line is also known as

[A]. magnetic bearing
[B]. true bearing @
[C]. azimuth
[D]. reduced bearing

Answer

A

Magnetic bearing is also called “bearing” & true bearing is also known as “azimuth”.

Question 16

Q

If θ is the slope of the ground and l is the measured distance, the correction is
[A].	2l sin2 θ/2	@
[B].	2l cos2 θ/2
[C].	2l tan2 θ/2
[D].	2l cot2 θ/2.

Answer

A

If θ is the slope of the ground and l is the measured distance, the correction is
[A].	2l sin2 θ/2	@
[B].	2l cos2 θ/2
[C].	2l tan2 θ/2
[D].	2l cot2 θ/2.

Question 17

Q

The most reliable method of plotting a theodolite traverse, is

[A]. by consecutive co-ordinates of each station
[B]. by independent co-ordinates of each station @
[C]. by plotting included angles and scaling off each traverse leg
[D]. by the tangent method of plotting.

Answer

A

By independent coordinate method, the latitudes and departure are located by common origin and the error will not be cumulative which occurs in depended or consecutive coordinate method of traversing.

Question 18

Q

The difference of level between a point below the plane of sight and one above, is the sum of two staff readings and an error would be produced equal to

[A]. the distance between the zero of gradient and the foot of the staff
[B]. twice the distance between the zero of graduation and the foot of the staff @
[C]. thrice the distance between the zero of graduation and the foot of the staff
[D]. none of the above.

Answer

A

The difference of level between a point below the plane of sight and one above, is the sum of two staff readings and an error would be produced equal to

[A]. the distance between the zero of gradient and the foot of the staff
[B]. twice the distance between the zero of graduation and the foot of the staff @
[C]. thrice the distance between the zero of graduation and the foot of the staff
[D]. none of the above.

Question 19

Q

The difference of level between a point below the plane of sight and one above, is the sum of two staff readings and an error would be produced equal to

[A]. the distance between the zero of gradient and the foot of the staff
[B]. twice the distance between the zero of graduation and the foot of the staff @
[C]. thrice the distance between the zero of graduation and the foot of the staff
[D]. none of the above.

Answer

A

The displacement due to angular error =Lsin.
and it should be equal to displacement due to Linear error = L/r.
Corresponding displacement on paper=√2(L/r)(1/S)= √2(Lsin-/S).
Corresponding if a limit of accuracy in plotting is 0.05cm then,
√2(L/r)(1/S)=.05,
L= (.05x40x20)/√2.
= 28.28.
Where S=1 in accuracy.
r=1 in scale.

Question 20

Q

The probable error of the adjusted bearing at the middle is

[A]. 0.5 r√n @
[B]. rn
[C]. rn
[D]. rn.

Answer

A

Its just like error at nth station =n*e/N in link traverse.

Here, a probable error at initial=0, similarly at the end is r√(n).

At middle would be averagei .e=r* √(n)/2.

Question 21

Q

If the radius of a simple curve is R, the length of the chord for calculating offsets by the method of chords produced, should not exceed.

[A]. R/10
[B]. R/15
[C]. R/20 @
[D]. R/25.

Answer

A

Offset can be more than 15 is called as long offset, but it should not be greater than 20. That’s why c is the correct answer.

Question 22

Q

Pick up the correct statement from the following :

[A]. Box sextant is used for the measurement of horizontal angles
[B]. Cross staff is used for setting out right angles
[C]. Gradiometer is used for setting out any required gradient
[D]. Line ranger is used for locating intermediate stations on a survey line
[E]. All the above. @

Answer

A

Pick up the correct statement from the following :

[A]. Box sextant is used for the measurement of horizontal angles
[B]. Cross staff is used for setting out right angles
[C]. Gradiometer is used for setting out any required gradient
[D]. Line ranger is used for locating intermediate stations on a survey line
[E]. All the above. @

Question 23

Q

Pick up the correct statement from the following :

[A]. in astronomical telescope, the rays from the object after refraction at the objective are brought to a focus before entering the eyepiece to produce a real inverted image in front of the eye piece
[B]. in Galileo’s telescope, the rays from the object get refracted at the objective and are intercepted by the eyepiece before a real image is formed
[C]. a line passing through the optical centre of the objective traversing through the eyepiece, is called line of sight
[D]. the line of sight which passes through the intersection of cross-lines marked on a diaphragm fixed in front of the eyepiece in a plane at right-angles to the axis, is called the line of collimation
[E]. all the above. @

Answer

A

Pick up the correct statement from the following :

[A]. in astronomical telescope, the rays from the object after refraction at the objective are brought to a focus before entering the eyepiece to produce a real inverted image in front of the eye piece
[B]. in Galileo’s telescope, the rays from the object get refracted at the objective and are intercepted by the eyepiece before a real image is formed
[C]. a line passing through the optical centre of the objective traversing through the eyepiece, is called line of sight
[D]. the line of sight which passes through the intersection of cross-lines marked on a diaphragm fixed in front of the eyepiece in a plane at right-angles to the axis, is called the line of collimation
[E]. all the above. @

Question 24

Q

Orientation of a plane table by solving two point problem is only adopted when

[A]. saving of time is a main factor
[B]. better accuracy is a main factor
[C]. given points are inaccessible @
[D]. none of these.

Answer

A

Orientation of a plane table by solving two point problem is only adopted when

[A]. saving of time is a main factor
[B]. better accuracy is a main factor
[C]. given points are inaccessible @
[D]. none of these.

Question 25

Q

The sum of the interior angles of a geometrical figure laid on the surface of the earth differs from that of the corresponding plane figure only to the extent of one second for every

[A]. 100 sq. km of area
[B]. 150 sq. km of area
[C]. 200 sq. km of area @
[D]. none of these.

Answer

A

The sum of the interior angles of a geometrical figure laid on the surface of the earth differs from that of the corresponding plane figure only to the extent of one second for every

[A]. 100 sq. km of area
[B]. 150 sq. km of area
[C]. 200 sq. km of area @
[D]. none of these.

Question 26

Q

The best method of interpolation of contours, is by

[A]. estimation
[B]. graphical means
[C]. computation @
[D]. all of these.

Answer

A

Computation means arithmetical calculation.

Question 27

Q

Pick up the correct specification of Ramsden eyepiece from the following :

[A]. it consists of two equal piano convex lenses
[B]. the curved surfaces of plano-convex lenses face each other
[C]. the two lenses are separated by a distance equal to 2/3 of the focal length of either lens.
[D]. the distance between the diaphragm and the front lens of the eyepiece is kept equal to 1/4 th of the focal length of a lens so that rays from a point on the diaphragm enter the eye as a parallel beam
[E]. all the above. @

Answer

A

Pick up the correct specification of Ramsden eyepiece from the following :

[A]. it consists of two equal piano convex lenses
[B]. the curved surfaces of plano-convex lenses face each other
[C]. the two lenses are separated by a distance equal to 2/3 of the focal length of either lens.
[D]. the distance between the diaphragm and the front lens of the eyepiece is kept equal to 1/4 th of the focal length of a lens so that rays from a point on the diaphragm enter the eye as a parallel beam
[E]. all the above. @

Question 28

Q

Deviation of the actual road gradient from the proposed contou’r gradient up hill side, involves

[A]. embankment on the centre line
[B]. excavation on the centre line @
[C]. earth work on the centre line
[D]. none of these.

Answer

A

Deviation of the actual road gradient from the proposed contou’r gradient up hill side, involves

[A]. embankment on the centre line
[B]. excavation on the centre line @
[C]. earth work on the centre line
[D]. none of these.

Question 29

Q

When the bubble of the level tube of a level, remains central

[A]. line of sight is horizontal @
[B]. axis of the telescope is horizontal
[C]. line of collimation is horizontal
[D]. geometrical axis of the telescope is horizontal.

Answer

A

couldnt understand

Question 30

Q

Cross hairs in surveying telescopes, are fitted

[A]. in the objective glass
[B]. at the centre of the telescope
[C]. at the optical centre of the eye piece
[D]. in front of the eye piece. @

Answer

A

Crosshair is placed on an optical center of the diaphragm which is in front of an eyepiece.

Question 31

Q

Plotting of inaccessible points on a plane table, is done by

[A]. intersection @
[B]. traversing
[C]. radiation
[D]. none of these.

Answer

A

Radiation method is used for detailed plotting of accessible point and used in plain area.

Intersection method is used for detailed plotting of inaccessible point used in a hilly area.

Question 32

Q

Probable systematic error in precise levelling as recommended by International Geodetic Association should not exceed
(where k is in kilometers.)

[A]. ± 0.1 k mm
[B]. ± 0.2 k mm
[C]. ± 0.1 k
[D]. 0.2 k mm. @

Answer

A

+/- 0.2√km is the right answer. K is in km.

Question 33

Q

For setting out a simple curve, using two theodolites.

[A]. offsets from tangents are required
[B]. offsets from chord produced are required
[C]. offsets from long chord are required
[D]. deflection angles from Rankine’s formula are required
[E]. none of these. @

Answer

A

In two theodolite method, curves are staked out by angular measurements only. Accuracy attained in this method is quite high. Thus, the method is used when higher accuracy is required and when the topography is rough or field condition is difficult.

Under “Fundamental Geometry of Circular Curve”;

The underlying principle of this method is that the deflection angle between a tangent (at any point on a circle) and a chord is equal to the angle which the chord subtends in the alternate segment.

Question 34

Q

The desired sensitivity of a bubble tube with 2 mm divisions is 30”. The radius of the bubble tube should be

[A]. 13.75 m @
[B]. 3.44 m
[C]. 1375 m
[D]. none of these.

Answer

A

The desired sensitivity of a bubble tube with 2 mm divisions is 30”. The radius of the bubble tube should be

[A]. 13.75 m @
[B]. 3.44 m
[C]. 1375 m
[D]. none of these.

Question 35

Q

True meridian of different places

[A]. converge from the south pole to the north pole
[B]. converge from the north pole to the south pole
[C]. converge from the equator to the poles @
[D]. run parallel to each other.

Answer

A

True meridian of different places

[A]. converge from the south pole to the north pole
[B]. converge from the north pole to the south pole
[C]. converge from the equator to the poles @
[D]. run parallel to each other.

Question 36

Q

Centering error of a theodolite produces an error

[A]. in all angles equally
[B]. which does not vary with the direction or pointing
[C]. which varies with the direction of pointing and inversely with the length of sight @
[D]. none of these.

Answer

A

Centering error of a theodolite produces an error

[A]. in all angles equally
[B]. which does not vary with the direction or pointing
[C]. which varies with the direction of pointing and inversely with the length of sight @
[D]. none of these.

Question 37

Q

An ideal transition curve is

[A]. cubic parabola
[B]. cubic spiral
[C]. clothoid spiral @
[D]. true spiral.

Answer

A

IRC recommends Spiral or clothoid as the ideal transition curve due to following reasons.

It satisfies that rate of change of centrifugal acceleration is constant i.e., Ls.R = constant. Where Ls = length of transition curve R = radius of the curve.
The calculation and field implementation of the spiral curve is simple and easy.
It enhances aesthetics also.

A. Cubic parabola - Railway.
B. Cubic spiral - Road.
C. Clothoid spiral - Ideal.

Question 38

Q

Pantagraph is used for

[A]. measuring distances
[B]. measuring areas
[C]. enlarging or reducing plans @
[D]. setting out right angles

Answer

A

It is a minor instrument, and also it is working on the principle if similar triangles, by that way from the basis of similar triangles it will enlarge or reduce the maps.

Question 39

Q

For a curve of radius 100 m and normal chord 10 m, the Rankine’s deflection angle, is

[A].	0°25'.95
[B].	0°35'.95
[C].	1°25'.53
[D].	1°35'.95
[E].	2°51'.53.	@

Answer

A

Deflection = (180xc)/2x3.14R.

= 180X10/2X3.14X100.

= 2dree51’.

Question 40

Q

In optical reading instruments

[A]. the vertical circle is usually continuous from 0° to 359°
[B]. the readings increase when the telescope is elevated in the face left position
[C]. the readings decrease when the telescope is elevated in the face right position
[D]. all the above. @

Answer

A

In optical reading instruments

[A]. the vertical circle is usually continuous from 0° to 359°
[B]. the readings increase when the telescope is elevated in the face left position
[C]. the readings decrease when the telescope is elevated in the face right position
[D]. all the above. @

Question 41

Q

Prismatic compass is considered more accurate than a surveyor’s compass, because

[A]. it is provided with a better magnetic needle
[B]. it is provided with a sliding glass in the object vane
[C]. its graduations are in whole circle bearings
[D]. it is provided with a prism to facilitate reading of its graduated circle @
[E]. both (c) and (d).

Answer

A

E is correct one.

Prismatic Compass

Graduation circle is fixed to broad type needle. Hence, it will not rotate with the line of sight.
There is a prism at viewing end.
Sighting and reading can be done simultaneously.
The magnetic needle do not act as an index.
The graduations are in whole circle bearing.
Graduations are marked inverted since its reflection is read through prism.
The reading is taken through a prism.
Tripod may or may not be used. It can be held on a stretched hand also.
Surveyors Compass

Graduation circle is fixed to the box. Hence, it rotates with the line of sight.
At viewing end there is no prism. There is only a slit.
Sighting and viewing cannot be done simultaneously.
Magnetic needle acts as index while reading.
The graduations are in quadrantal system.
Graduations are marked directly. They are not inverted.
The reading is taken by directly viewing from top glass.
Tripod is essential for using it.

Question 42

Q

Removal of parallax, may be achieved by focussing

[A]. the objective
[B]. the eye-piece
[C]. the objective and the eye-piece @
[D]. none of these.

Answer

A

The effect whereby the position or direction of an object appears to differ when viewed from different positions.

Question 43

Q

In an internal focusing telescope

[A]. the objective is at a fixed distance from the diaphragm
[B]. the focusing is done by the sliding of a divergent lens.
[C]. the focusing divergent lens is situated at about the middle of the tube
[D]. all the above. @

Answer

A

In an internal focusing telescope

[A]. the objective is at a fixed distance from the diaphragm
[B]. the focusing is done by the sliding of a divergent lens.
[C]. the focusing divergent lens is situated at about the middle of the tube
[D]. all the above. @

Question 44

Q

Imaginary line passing through points having equal magnetic declination is termed as

[A]. isogon @
[B]. agonic line
[C]. isoclinic line
[D]. none of these.

Answer

A

ISOGONIC—–> same declination.
AGONIC——–> zero declination.
ISOCLINIC——> same dip.
ACLINIC———> zero dip.

Question 45

Q

While measuring a chain line between two stations A and B intervened by a raised ground

[A]. vision gets obstructed @
[B]. chaining gets obstructed
[C]. both vision and chaining get obstructed
[D]. all the above.

Answer

A

While measuring a chain line between two stations A and B intervened by a raised ground

[A]. vision gets obstructed @
[B]. chaining gets obstructed
[C]. both vision and chaining get obstructed
[D]. all the above.

Question 46

Q

The true meridian of a place is the line in which earth’s surface is intersected by a plane through

[A]. east and west points
[B]. zenith and nadir points
[C]. north and south geographical poles @
[D]. north and south magnetic poles.

Answer

A

The true meridian passing through a station on surface on earth is the line of intersection of a plane passing through the geographical north and south poles of the earth with its actual surface.

Question 47

Q

The least count of a vernier scale is

[A]. sum of the smallest divisions of main and vernier scales
[B]. value of one division of the primary scale divided by total number of divisions of vernier scale @
[C]. value of one division of vernier scale divided by total number of divisions of primary scale
[D]. none of these.

Answer

A

The least count of a vernier scale is

[A]. sum of the smallest divisions of main and vernier scales
[B]. value of one division of the primary scale divided by total number of divisions of vernier scale @
[C]. value of one division of vernier scale divided by total number of divisions of primary scale
[D]. none of these.

Question 48

Q

Which one of the following procedures for getting accurate orientation is the most distinctive feature of the art of plane tabling

[A]. radiation
[B]. intersection
[C]. traversing
[D]. resection. @

Answer

A

All options are method of plan tabling.

Resection: This method is used for establishing the instrument station only. After mixing the stations, the details either located by radiation or intersection.

Question 49

Q

Diurnal variation of magnetic declination is

[A]. greater at equator than nearer the poles
[B]. less at equator than nearer the poles @
[C]. less in summer than in winter
[D]. same at all latitudes and during different months.

Answer

A

The daily variation of magnetic declination is as much as 10^2. This variation is also known as Dirunal Variation. The following factors influence its magnitude:

(a) It is more in the day and less in the night.
(b) It is more in summer and less in winter.
(c) A number of variation changes from year to year.
(d) It is more near magnetic poles and less near the equator.

Question 50

Q

The ‘fix’ of a plane table from three known points, is good, if

[A]. middle station is nearest @
[B]. middle station is farthest
[C]. either the right or left station is nearest
[D]. none of these.

Answer

A

The ‘fix’ of a plane table from three known points, is good, if

[A]. middle station is nearest @
[B]. middle station is farthest
[C]. either the right or left station is nearest
[D]. none of these.

Question 51

Q

If the smallest division of a vernier is longer than the smallest division of its primary scale, the vernier is known as

[A]. direct vernier
[B]. double vernier
[C]. retrograde vernier @
[D]. simple vernier.

Answer

A

If the smallest division of a vernier is longer than the smallest division of its primary scale, the vernier is known as

[A]. direct vernier
[B]. double vernier
[C]. retrograde vernier @
[D]. simple vernier.

Question 52

Q

The ‘point of curve’ of a simple circular curve, is

[A]. point of tangency
[B]. point of commencement @
[C]. point of intersection
[D]. mid-point of the curve

Answer

A

The ‘point of curve’ of a simple circular curve, is

[A]. point of tangency
[B]. point of commencement @
[C]. point of intersection
[D]. mid-point of the curve

Question 53

Q

For orientation of a plane table with three points A, B and C, Bessel’s drill is

[A]. Align b through a and draw a ray towards c, align a through b and draw a ray towards c, finally align c through the point of intersection of the previously drawn rays
[B]. Align c through a and draw a ray towards b, align a through c and draw a ray towards b, finally align b through the point of intersection of the previously drawn rays
[C]. Align c through b and draw a ray towards a, align b through c and draw a ray towards a, finally align a, through the point of intersection of the previously, drawn rays
[D]. In the first two steps any two of the points may be used and a ray drawn towards the third point, which is sighted through the point of intersection of previously drawn rays in the final step. @

Answer

A

For orientation of a plane table with three points A, B and C, Bessel’s drill is

[A]. Align b through a and draw a ray towards c, align a through b and draw a ray towards c, finally align c through the point of intersection of the previously drawn rays
[B]. Align c through a and draw a ray towards b, align a through c and draw a ray towards b, finally align b through the point of intersection of the previously drawn rays
[C]. Align c through b and draw a ray towards a, align b through c and draw a ray towards a, finally align a, through the point of intersection of the previously, drawn rays
[D]. In the first two steps any two of the points may be used and a ray drawn towards the third point, which is sighted through the point of intersection of previously drawn rays in the final step. @

Question 54

Q

The minimum range for sliding the focusing lens in the internal focusing telescope for focusing at all distances beyond 4 m is

[A]. 5 mm
[B]. 10 mm
[C]. 15 mm
[D]. 20 mm. @

Answer

A

Focusing lence is in multiple.

So, multiple of 4 is only 20 in options.

Question 55

Q

Pick up the correct statement from the following :

[A]. If the slope of the curve of a mass diagram in the direction of increasing abscissa is downward, it indicates an embankment
[B]. The vertical distance between a maximum ordinate and the next forward maximum ordinate represents the whole volume of the embankment
[C]. The vertical distance between a minimum ordinate and the next forward maximum ordinate represents the whole volume of a cutting
[D]. The area enclosed by a loop of the curve and balancing line, measures the haul in that direction.
[E]. all the above. @

Answer

A

Pick up the correct statement from the following :

[A]. If the slope of the curve of a mass diagram in the direction of increasing abscissa is downward, it indicates an embankment
[B]. The vertical distance between a maximum ordinate and the next forward maximum ordinate represents the whole volume of the embankment
[C]. The vertical distance between a minimum ordinate and the next forward maximum ordinate represents the whole volume of a cutting
[D]. The area enclosed by a loop of the curve and balancing line, measures the haul in that direction.
[E]. all the above. @

Question 56

Q

The slope correction may be ignored if

[A]. the slope of the ground is less than 3°
[B]. to slope of the ground is say 1 in 19
[C]. both (a) and (b) @
[D]. neither (a) nor (b)

Answer

A

The slope correction may be ignored if

[A]. the slope of the ground is less than 3°
[B]. to slope of the ground is say 1 in 19
[C]. both (a) and (b) @
[D]. neither (a) nor (b)

Question 57

Q

The orthographical projection of a traverse leg upon the reference meridian, is known as

[A]. departure of leg
[B]. latitude to the leg @
[C]. co-ordinate of the leg
[D]. bearing of the leg.

Answer

A

From the reference, meridian (N-pole) is = departure of the leg.

Upon the reference, the meridian is = latitude to the leg.

Question 58

Q

A transit is oriented by setting its vernier A to read the back azimuth of the preceding line. A back sight on the preceding transit station taken and transit is rotated about its vertical axis. The vernier A reads

[A]. azimuth of the forward line @
[B]. bearing of the. forward line
[C]. back bearing of the forward line
[D]. equal to 360°-azimuth of the forward line.

Answer

A

A transit is oriented by setting its vernier A to read the back azimuth of the preceding line. A back sight on the preceding transit station taken and transit is rotated about its vertical axis. The vernier A reads

[A]. azimuth of the forward line @
[B]. bearing of the. forward line
[C]. back bearing of the forward line
[D]. equal to 360°-azimuth of the forward line.

Question 59

Q

Correction per chain length of 100 links along a slope of α radians, is

[A]. 100 α2
[B]. 100 α @
[C]. 100 α3
[D]. 100 α-1

Answer

A

Correction per chain length of 100 links along a slope of α radians, is

[A]. 100 α2
[B]. 100 α @
[C]. 100 α3
[D]. 100 α-1

Question 60

Q

While working on a plane table, the correct rule is :

[A]. Draw continuous lines from all instrument stations
[B]. Draw short rays sufficient to contain the points sought @
[C]. Intersection should be obtained by actually drawing second rays
[D]. Take maximum number of sights as possible from each station to distant objects.

Answer

A

While working on a plane table, the correct rule is :

[A]. Draw continuous lines from all instrument stations
[B]. Draw short rays sufficient to contain the points sought @
[C]. Intersection should be obtained by actually drawing second rays
[D]. Take maximum number of sights as possible from each station to distant objects.

Question 61

Q

The representation of general topography of a very flat terrain is possible only

[A]. by drawing contours at large interval
[B]. by drawing contours at small interval
[C]. by giving spot levels at large interval
[D]. by giving spot levels to salient features at close interval. @

Answer

A

The representation of general topography of a very flat terrain is possible only

[A]. by drawing contours at large interval
[B]. by drawing contours at small interval
[C]. by giving spot levels at large interval
[D]. by giving spot levels to salient features at close interval. @

Question 62

Q

Permanent adjustments of a level are

[A]. 2 in number @
[B]. 3 in number
[C]. 4 in number
[D]. 6 in number

Answer

A

The two adjustments are.

1) To make the axis of the bubble tube perpendicular to the vertical axis.
2) To make the line of collimation parallel to the axis of the bubble tube.

Question 63

Q

The surface of zero elevation around the earth, which is slightly irregular and curved, is known as

[A]. mean sea level
[B]. geoid surface @
[C]. level surface
[D]. horizontal surface.

Answer

A

The surface of zero elevation around the earth, which is slightly irregular and curved, is known as

[A]. mean sea level
[B]. geoid surface @
[C]. level surface
[D]. horizontal surface.

Question 64

Q

Surveys which are carried out to depict mountains, rivers, water bodies, wooded areas and other cultural details, are known as

[A].	cadastral surveys
[B].	city surveys
[C].	topographical surveys	@
[D].	guide map surveys
[E].	plane surveys.

Answer

A

A topographical survey is used to determine the external features of the earth.
Cadastral survey is used to determine property line.
Guide map: navigation.

Answer 65

A

Grid lines are parallel to

[A]. magnetic meridian of the central point of the grid
[B]. line representing the central true meridian of the grid @
[C]. geographical equator
[D]. none of these.

Answer 66

A

The apparent error on reversal is

[A]. equal to the actual error
[B]. twice the actual error @
[C]. thrice the actual error
[D]. none of these.

Answer 67

A

Correction for curvature, CC = 0.07849 L^2.
Where L is in meters. and CC in meter.
CC = 0.07849L^210^3 mm.
= 78.49*L^2 mm.

Answer 68

A

Yes, the correct answer is B. Because 180’ at back sight means 0’ in the prolongation line so that measured angle will directly give the value.

Answer 69

A

Transition curves are introduced at either end of a circular curve, to obtain

[A]. gradually decrease of curvature from zero at the tangent point to the specified quantity at the junction of the transition curve with main curve
[B]. gradual increase of super-elevation from zero at the tangent point to the specified amount at the junction of the transition curve with main curve @
[C]. gradual change of gradient from zero at the tangent point to the specified amount at the junction of the transition curve with main curve
[D]. none of these.

Answer 70

A

Magnetic bearing of a survey line at any place

[A]. remains constant
[B]. changes systematically
[C]. varies differently in different months of the year @
[D]. is always greater than true bearing.

Answer 71

A

If the length of offset;

L < = 16m then called short offset.
L > = 16m then called long offset.

Answer 72

A

Back bearing of AB =180 + 52°45’=232°45’

So angle = 232°45’ - 34°30’=198°15’.

Deflection angle= 180 - 198°15’= - 18°15’ so -ve sign show the left.

Answer 73

A

A lemniscate curve will not be transitional throughout, if its deflection angle, is

[A].	45°	@
[B].	60°
[C].	90°
[D].	120°
[E].	180°

Answer 74

A

In a lemniscate curve the ratio of the angle between the tangent at the end of the polar ray and the straight, and the angle between the polar ray and the straight, is

[A].	2
[B].	3
[C].	4
[D].	5
[E].	3/2	@

Answer 75

A

Ranging in chain survey means

[A]. looking at an isolated point not on the line
[B]. establishing an intermediate point on the line @
[C]. determining the distance between end points
[D]. determining the offset distance
[E]. none of these

Answer 76

A

Greater accuracy in linear measurements, is obtained by

[A]. tacheometry
[B]. direct chaining
[C]. direct taping @
[D]. all the above.

Answer 77

A

From any point on the surface with a given inclination

[A]. only one contour gradient is possible
[B]. two contour gradients are possible
[C]. indefinite contour gradients are possible @
[D]. all the above.

Answer 78

A

While measuring with a metallic tape of 30 m length pull should be applied

[A]. 1 kg
[B]. 2 kg
[C]. 3 kg @
[D]. 4 kg

Answer 79

A

Chord length for curve setting is derived from the formula of errors. The greater chord length we take, the greater be the chances of error in measurement because while using the method ‘OFFSET FROM CHORD PRODUCED’ we take the chord distances whereas we consider them as straight lines. You will see while taking the first chord in the method, we mention that Chord length~arc length. Now, if we use R/10, the error is 1 in 2500, which is pretty significant. But if we use R/20, the error is 1 in 10, 10000 which is considerably low and cannot be seen or detected from a human perspective. Hence R/20 is the correct value.

Answer 80

A

For preparation of a contour plan for a route survey

[A]. method of squares is used
[B]. method of trace contour is used
[C]. method of cross profile is used @
[D]. indirect method of contouring is used.

Answer 81

A

Flint glass

[A]. has slightly the greater refracting power than crown glass
[B]. has roughly double refracting power than that of crown
[C]. and crown glass proportions yield the required focal length and neutralise the dispersion produced by the convex lens at the emergence from the concave
[D]. all the above. @

Answer 82

A

Contour lines of different elevations can unite to form one line, only in the case of

[A]. a vertical cliff @
[B]. a saddle
[C]. a water shed line
[D]. a hill top.

Answer 83

A

Shimmering shine with a soft, slightly wavering light.

Answer 84

A

True bearing = Azimuth.
Magnetic bearing = Bearing.

So, the Correct answer is option C.

Answer 85

A

The distance between terminal points computed from a subsidiary traverse run between them, is generally known, as

[A]. traverse leg
[B]. a base
[C]. traverse base @
[D]. all the above.

Answer 86

A

Here Each sub division = 5mm,
1m = 1000mm,
So, 1000/5 = 200.

Answer 87

A

Delta/6 @

Answer 88

A

Pick up the correct statement from the following :

[A]. the diaphragm is placed between eyepiece and the objective but nearer to the former
[B]. the diaphragm is placed between the eyepiece and objective but nearer to the later
[C]. the outer component of the objective is a double-convex lens of crown glass
[D]. the inner component of the objective is a flint glass, convexo-concave
[E]. all the above. @

Answer 89

A

The chain never measured in angular measurement. So D is incorrect.

Answer 90

A

While measuring the distance between two points along upgrade with the help of a 20 m chain, the forward end of the chain is shifted forward through a distance

[A]. 20 (sin θ - 1)
[B]. 20 (cos θ - 1)
[C]. 20 (sec θ - 1) @
[D]. 20 (cosec θ - 1).

Answer 91

A

Subtense tacheometry is generally preferred to if ground is

[A]. flat
[B]. undulating @
[C]. mountaineous
[D]. deserts.

Answer 92

A

The chain is used for measuring and layout of survey lines. Cloth and the metallic tape are used for measuring short offset distance while former for more accuracy. The steel tape is used for checking chain length and invar tape is used for very accurate measurements such as the base line.

Answer 93

A

If a linear traverse follows a sharp curve round a large lake where it is difficult to have long legs, the accuracy of the traverse may be improved by

[A]. taking short legs
[B]. making repeated observations of angular and linear measurements
[C]. making a subsidiary traverse to determine the length of a long leg @
[D]. all the above.

Answer 94

A

Rankine’s deflection angle in minutes is obtained by multiplying the length of the chord by

[A]. degree of the curve @
[B]. square of the degree of the curve
[C]. inverse of the degree of the curve
[D]. none of these.

Answer 95

A

The line of collimation method of reduction of levels, does not provide a check on

[A]. intermediate sights @
[B]. fore sights
[C]. back sights
[D]. reduced levels.

Answer 96

A

The method of reversal

[A]. is usually directed to examine whether a certain part is truly parallel or perpendicular to another
[B]. makes the erroneous relationship between parts evident
[C]. both (a) and (b) @
[D]. neither (a) nor (b).

Answer 97

A

Fiducial edge is the edge of alidade over which the scale is provided

Answer 98

A

Length of Unit Chord = Beg interval. Standard Unit curve (peg interval 30m for plate curve. And for Flat Curve =20m and for very flat =10m. So now if chord measure is less than standard Chord (peg interval or unit Chord) is called Sub -Chord, peg interval or Unit chord have constant value 30m, 20 and 10m.

Answer 99

A

The operation of resection involves the following steps
rough orientation of the plane table
the three lines form a triangle of error
drawing lines back through the three control points
select a point in the triangle of error such that each ray is equally rotated either clockwise or anti clockwise
the points obtained by three rays is the correct location.

The correct sequence is
[A].	1, 3, 2, 4, 5	@
[B].	1, 2, 3, 4, 5
[C].	1, 4, 3, 2, 5
[D].	1, 4, 2, 3, 5

Answer 100

A

(1) Length of long chord = 2R sinD/2.
(2) Tangent length = R tanD/2.

Ratio =(1) / (2).
Ans. =2 cosD/2.

Answer 101

A

During secular variation of magnetic meridian at different places

[A]. range of oscillations is constant
[B]. period of oscillation is constant
[C]. range and period of oscillation both vary @
[D]. period of oscillation only varies.

Answer 102

A

If a linear traverse follows a sharp curve round a large lake where it is difficult to have long legs, the accuracy of the traverse may be improved by

[A]. taking short legs
[B]. making repeated observations of angular and linear measurements
[C]. making a subsidiary traverse to determine the length of a long leg @
[D]. all the above.

Answer 103

A

Perpendicular offset from a tangent to the junction of a transition curve and circular curve is equal to

[A]. shift
[B]. twice the shift
[C]. thrice the shift
[D]. four times the shift. @

Answer 104

A

To avoid large centering error with very short legs, observations are generally made

[A]. to chain pins
[B]. by using optical system for centering the theodolite
[C]. to a target fixed on theodolite tripod on which theodolite may be fitted easily @
[D]. all the above.

Answer 105

A

Resolving power is defined as the ability of a microscope or telescope to distinguish two close together images as being separate. An example of resolving power is how well a telescope can show two stars as being separate stars.

That means C option is right.

Answer 106

A

should be D

Answer 107

A

To orient a plane table at a point P roughly south of the mid-point of two inaccessible conical hill stations A and B in the plains, a point C is selected in line with AB and table is oriented at C by bringing ab in line with AB. A ray is then drawn towards P and at P the table is oriented by back ray method. The orientation so obtained, is

[A]. unique and correct
[B]. incorrect
[C]. manifold and correct @
[D]. not reliable.

Answer 108

A

Which one of the following statements is correct ?

[A]. when the axes of rotation of the graduated circle and the verniers are not coincident, the instrument possesses eccentricity
[B]. the mean of the readings of the two verniers gives correct reading free from the eccentricity
[C]. one vernier may be used if the readings of two verniers differ by a constant
[D]. all the above. @

Answer 109

A

Pick up the correct statement from the following

[A]. 1 second of arc corresponds to a displacement ratio of 1:206, 300
[B]. 1 degree of arc corresponds to a displacement ratio of 1:57
[C]. the angular errors tend to propagate themselves along a traverse as the square root of the number of stations
[D]. the errors arising from the linear measures tend to be roughly proportional to the lengths of the lines
[E]. all the above. @

Answer 110

A

The chaining on sloping ground is

[A]. easier along the falling gradient @
[B]. easier along the up gradient
[C]. equally convenient along falling as well as up gradient
[D]. all the above.

Answer 111

A

Profile levelling is usually done for determining

[A]. contours of an area
[B]. capacity of a reservoir
[C]. elevations along a straight line @
[D]. boundaries of property

Answer 112

A

For indirect ranging, number of ranging rods required, is

[A].	1
[B].	2
[C].	3
[D].	4	@
[E].	5

Answer 113

A

We know 100 links =20 m chain.
Son horizontal =1 unit
20 m horizontal =20/n
i.e. h=20/n
L=20m.

Slope correction = h^2/2l
So (20/n)^2/2*20
= 100/n^2(ans)

Answer 114

A

Option A is correct (L2/6RL) * 180/π.

Answer 115

A

Focussing is done by double concave lens in internal focussing type telescope whereas in external focusing type telescope it is achieved by external movement of objective tube.

Answer 116

A

For distance upto 18.2 km is 10 cm.
For distance upto 54.3 km is 30 cm.
For distance upto 91 km is 50 cm.

Ref: RS Khurmi(clause 5.1)

Answer 117

A

Diaphragm of a surveying telescope is held inside

[A]. eye-piece
[B]. objective
[C]. telescope tube at its mid point
[D]. telescope at the end nearer the eye-piece @
[E]. telescope at its end nearer the objective.

Answer 118

A

If vertical angles of inclined sights do not exceed 10° and non-verticality of the staff remains within 1°, stadia system of tacheometric observations are made on

[A]. staff normal @
[B]. staff vertical
[C]. staff normal as well as vertical
[D]. none of these.

Answer 119

A

The sag of 50 m tape weighing 4 kg under 5 kg tension is roughly

[A].	0.043 m
[B].	0.053 m
[C].	0.063 m
[D].	0.073 m
[E].	0.083 m	@

Answer 120

A

The angle of intersection of a contour and a ridge line, is

[A]. 30°
[B]. 45°
[C]. 60°
[D]. 90°. @

Answer 121

A

Pentagraph is used for enlarging maps
Planimeter is used for area calculation from plan
Pentagraph is used for map measurement.

An inclinometer or clinometer is an instrument used for measuring angles of slope, elevation, or depression of an object with respect to gravity.

Answer 122

A

According to textbooks of agor, khurmi -260km^2.

According to IES Master -195.5km^2.

Answer 123

A

Pick up the correct statement from the following :

[A]. to locate a gross error in bearing that may exist in controlled theodolite traverse, we may plot the traverse from each end. The traverse station having the same coordinates by each route is the one where the error lies
[B]. to locate a gross error in bearing, in a controlled traverse, we plot the traverse and the station through which perpendicular to sector of the closing line passes is the station at which the error was made
[C]. to locate a gross error due to taping in a controlled traverse, we plot the traverse to a convenient scale. The bearing of the closing error will be approximately the same as that of the leg in which the gross error consists
[D]. all the above. @

Answer 124

A

In a precision traverse, included angles are measured by setting the vernier

[A]. to read zero exactly on back station
[B]. to read 5° exactly on back station
[C]. some where near zero and reading both verniers on back station @
[D]. all the above.

Answer 125

A

Y = x^3/6RL.

For maximum perpendicular offset x = L = 90 m.

So Y = 90^3/650090 = 2.70 m.

Answer 126

A

An imaginary line lying throughout on the surface of the earth and preserving a constant inclination to the horizontal, is called

[A]. contour line
[B]. contour gradient @
[C]. level line
[D]. line of gentle scope.

Answer 127

A

An angles of 45° with a chain line may be set out with

[A]. optical square
[B]. open cross staff
[C]. Fench cross staff @
[D]. prismatic square.

Answer 128

A

Pick up the correct statement from the following :

[A]. spherical aberration may be reduced by diminishing the aperture
[B]. spherical aberration may be minimised by replacing the single lens by a combination of the lenses.
[C]. in telescope objectives, a combination of convex lens and concave lens is used.
[D]. in eyepieces, two plano-convex lenses placed at a certain distance apart are used
[E]. all the above. @

Answer 129

A

Line of collimation : Imaginary line passing through the intersection of the cross-hairs of the diaphragm and the optical centre of the objective lens.

Axis of telescope : line joining the optical center of the objective to the center of the eyepiece.

Answer 130

A

For mid point station { 1.56-1.32=.24} for second station {1.39-1.11=.28}.
The difference in reading shows collimation error , which is .28-.24=.04,
.04 is collimation error in 80 m.therefore in 90m = (.04/80)*90=.045,
Now correct reading at B = 1.39 - .045 = 1.345.

Answer 131

A

The instrument which is used in plane tabling for obtaining horizontal and vertical distances directly without resorting to chaining, is known as

[A]. Plane alidade
[B]. telescopic alidade @
[C]. clinometer
[D]. tacheometer.

Answer 132

A

Horizontal distances obtained tacheometerically are corrected for

[A]. slope correction
[B]. temperature correction
[C]. refraction and curvature correction @
[D]. all the above.

Answer 133

A

Long chord = 2*Rsinθ/2,
Tangent = Rtanθ/2.
Equating both, we get,
θ/2 = 60.
θ =120.

Answer 134

A

Ranging is an operation of

[A]. reconnaissance
[B]. judging the distance
[C]. determination of slope
[D]. establishing intermediate points between terminals. @

Answer 135

A

Surveys which are carried out to provide a national grid of control for preparation of accurate maps of large areas, are known

[A]. plane surveys
[B]. geodetic surveys @
[C]. geographical surveys
[D]. topographical surveys.

Answer 136

A

Answer saddle down the hill is right because saddle means lower point between two summits and contour gradient mean the horizontal contour or horizontal gradient in the contour. This road we can show in North India.

Answer 137

A

If h1 and h2 are the differences in level between ground and the formation levels, m is the slope of the sloping sides. D is the distance between the cross sections then, prismoidal correction for a level section is

[A].	D/2m(h1 - h2)
[B].	D/3m(h1 - h2)
[C].	D/6m(h1 - h2)2	@
[D].	D/6m(h1 - h2)3
[E].	D/6m(h1 + h2)2

Answer 138

A

I/f = 1/ f1 + 1/f2.
= 1/14 +1/16.50.

1/f = 0.314.
F = 7.24.

Answer 139

A

The gravitational force is always directed towards the centre of the earth and the plumb line is known as vertical line. The line perpendicular to vertical is horizontal line.

Answer 140

A

In a perfect prismatic compass

[A]. magnetic axis and geometric axis of the needle coincide
[B]. ends of the needle and pivot are in same vertical and horizontal planes
[C]. pivot is vertically over the centre of the graduated circle
[D]. needle is always kept sensitive
[E]. all the above. @

Answer 141

A

If deflection angles are measured in a closed traverse, the difference between the sum of the right-hand and that of the left hand angles should be equal to

[A]. 0°
[B]. 90°
[C]. 180°
[D]. 360° @

Answer 142

A

If the chain line which runs along N-S direction is horizontal and the ground in E-W direction is sloping

[A]. it is possible to set offsets correctly on east side
[B]. it is possible to set offsets correctly on east side
[C]. it is not possible to set offsets correctly on west side
[D]. it is possible to set offsets correctly on both sides. @

Answer 143

A

By keeping the instrument in our left hand we can take the readings for the right side and left hand can be used to giving the directions for the person who is holding the ranging rod.

And also optical square is always kept with direction upward.

Answer 144

A

A lens or combination of lenses in which the following defect is completely eliminated is called aplanatic

[A]. spherical aberration @
[B]. chromatic aberration
[C]. coma
[D]. astigmatism

Answer 145

A

1cm=2cm given.

So 30*2= 60cm,
60/4000=0.15.

Answer 146

A

In precision theodolite traverse if included angles are read twice and the mean reading accepted using both verniers having a least count of 30”. Assuming the instrument to be in perfect adjustment, linear measurements correct to 6 mm per 30 metre tape duly corrected for temperature, slope and sag, the angular error of closure not to exceed (where n is the number of traverse legs)

[A]. 50” n @
[B]. 30” n
[C]. 60” n.

Answer 147

A

The theodolites used for making tacheometric observations by optical wedge system, are

[A]. provided with stadia hairs in front of eye piece
[B]. not provided with stadia hairs at all
[C]. fitted with a glass wedge inside the telescope
[D]. fitted with a glass wedge in front of telescope. @

Answer 148

A

Pick up the correct statement from the following :

[A]. with both handles in his left hand, the chain man throws out the chain with his right hand and the second chain man assists him to free it from knots
[B]. the follower of the chaining operation should be more experienced than the leader
[C]. at the end of the tenth chain length, the two chain men meet and the ten arrows are handed over to the leader
[D]. all the above. @

Answer 149

A

Pick up the correct statement from the following :

[A]. with both handles in his left hand, the chain man throws out the chain with his right hand and the second chain man assists him to free it from knots
[B]. the follower of the chaining operation should be more experienced than the leader
[C]. at the end of the tenth chain length, the two chain men meet and the ten arrows are handed over to the leader
[D]. all the above. @

Answer 150

A

Under ordinary conditions, the precision of a theodolite traverse is affected by

[A]. systematic angular errors
[B]. accidental linear errors
[C]. systematic linear errors @
[D]. accidental angular errors.

Answer 151

A

Stadia techeometry was discovered by James Watt in the year.

[A]. 1670
[B]. 1770 @
[C]. 1870
[D]. 1900.

Answer 152

A

The properties of autogenous curve for automobiles are given by

[A]. true spiral
[B]. cubic parabola
[C]. Bernoulli’s Lemniscate @
[D]. clothoid spiral.

Answer 153

A

The included angles of a theodolite traverse, are generally measured

[A]. clockwise from the forward station
[B]. anti-clockwise from the back station
[C]. anti-clockwise from the forward station
[D]. clockwise from the back station. @

Answer 154

A

The method generally preferred to for contouring an undulating area, is

[A]. chain surveying
[B]. plane table surveying
[C]. tacheometrical surveying @
[D]. compass surveying.

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