surds and indices Flashcards

1
Q

x^0

A

1

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2
Q

x^n ÷ x^m

A

x^n-m

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3
Q

(x^n)^m

A

x^n*m

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4
Q

x^n * x^m

A

x^n + m

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5
Q

x^-n

A

1/x^n

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6
Q

x^n/m

A

m√ x^n

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7
Q

what is a surd

A

number that cant be square rooted put into a square root

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8
Q

How to solve non equation surds

A

Multiply all the denominators to remove the fractions
Then divide again to make a collective fraction

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9
Q

what is the exponential form

A

the form with a power

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10
Q

what are these properties to simplify surds
1. √ a x √ b = ?
2. √ a / √ b = ?
3. √ a x √ a = ?

A
  1. √ ab
  2. √ a/b
  3. a
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11
Q

how to simplify a surd √ using 2.
for example √ 27

A

first u pull out a squarable or cubable(Depending on ur √ ) out from the number
√ 27 = √ 9 x √ 3
u pull 9, this is cuz 9 can be squared
= 3 x √ 3
= 3√ 3

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12
Q

what about rly lengthy questions how do i solve them for surds

A

u can combo the 3 properties,
1. √ a x √ b = √ ab
2. √ a / √ b = √ a/b
3. √ a x √ a = a

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13
Q

what is a conjugate surd

A

it js means a surd of opposite signs
The conjugate of √ 2 would be its opposite, which is -√ 2

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14
Q

whnat do conjugate surds always result in

A

the product of conjugate surds is always a rational number

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15
Q

All real value positive qns

A

Make into cts form
a(x-h)^2 +k
a(x-h)^2 >= 0 cuz its squared and all squared no. R positive
Hence
a(x-h)^2 +k >= k

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16
Q

Show that roots r real
x^2 + (p-2)x = 2p

A

there r 2 negatives aka discriminant qn
When solving DONT put discriminant > 0
Cuz u DONT KNOW THAT YET
Js put
Discriminant
Solve until p^2+ 4p + 4
Then now u can square it as an algebraic identity
(p+2)^2
Since it’s a square it’s positive and positive means real

17
Q

How to make life easier and see solutions in lengthy questions with seemingly common factors

A

Use substitution
Let _/x-2 be y

18
Q

Find 2 unknown in 3 unknowns where one is x and u have 2 x values
y = p - (x - q)^2
x =1 or x = 3

A

Sub in 1 and 3 into the equation twice to get 2 simultaneous equations
Eventually getting
(1-q)^2=p and (3-q)^2=p
Then u sub and can get q which is 2
Then y sub 1 into the equation with one of the x values subbed in to solve for p which is 1