SL - Cross Aldol & Conjugate Addition Flashcards

1
Q

What is a cross-aldol reaction?

A

Reaction between 2 different carbonyl compounds
* One must form an electrophile the other must capable of enolization

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2
Q

What 2 conditons must be met for cross aldol to occur?

A
  1. One partner must be capable of enolization
  2. The other partner must be incapable of enolization and be more electrophilic that the other partner
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3
Q

How does the conjugate addition mechanism work?

A
  1. Nucleophile attatcks 𝛼,𝛽-unsaturated carbonyl compound at C=C bond (Carboxyl breaks)
  2. Double bond reformed at adjacent carbon and carboxyl reforms via protonation
  3. Double bond protonated to form C-C bond
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4
Q

How does the conjugated addition reaction occur with amines?

A
  1. The lone pair electrons from nitrogen attacks the conjugate double bond
  2. We trap the H+ of the N with the enolate (double bond) to form the final compound
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5
Q

Does conjugate addition work with tertiary amines?

A

Deprotonation cannot occur to produce the final product

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6
Q

Why do alcohols require catalysis to undergo conjugate additions?

A

They are poor nucleophiles

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7
Q

How does base-catalysed conjugate addition work? (2)

A
  1. Deprotonated alcohol attacks C-4 double bond whilst double bond reforms and carbonyl breaks
  2. Another molecule of the alcohol is deprotonated by the new double bond and the carbonyl reforms
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8
Q

How does acid-catalysed conjugate addition work? (3)

A
  1. Carbonyl gets protonated making it a strong enough electrophile to recieve nucleophilic attack
  2. Alcohol attacks C4, double bond reforms on adjacent carbon, C=O bond breaks
  3. H+ of the O is trapped by the enol where H+ is eventually regenerated to form the final product
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9
Q

Do thiols require catalysis to undergo conjugate addition?

A

No- Increased shielding of Sulfurs lone pair (stronger nucleophile)

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10
Q

What are the 3 main steps that occur (at the same time) with most conjugate addition reactions?

A
  1. Lone pair of nucleophile attacks (C4) C=C bond
  2. C=C bond moves to C2-C3 location
  3. (C2) C=O bond breaks to C-O bond
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