S13 Flashcards
The least-squares solution of Ax = b is the point in the column space of A that is closest to b.
True
It is the point such that ∥Ax − b∥ is minimal, and this is exactly the distance from the point b to the column space of A.
The least-squares solution of Ax = b is given by x^ = (AT A)−1ATb.
False
This is only true if the columns of A are linearly independent.
(Although the question is a bit ambiguous, because you could take the fact that we have written (ATA)−1 to mean that ATA is invertible, in which case the columns of A are linearly independent, and so the statement is true.
We will avoid this kind of confusion on the exam.)
If the columns of A are linearly independent, then Ax = b has a unique least- squares solution.
True
The formula from from the previous question in this series gives the unique solution in this case.
If A = QR is a QR factorization of A, then the least-squares solution of Ax = b is x^ = R−1QTb.
False
Again, only true if the columns of A are linearly independent.
(As before, this is a bit ambiguous. In fact, we only defined QR factorization when A has independent columns.)
If a matrix is orthogonal, then it is symmetric.
False
If an n × n matrix is symmetric, then it has n distinct eigenvalues.
False
A matrix is orthogonally diagonalizable if and only if it is nonsingular and symmetric.
False
A is orthogonally diagonalizable, but singular.