Rules to Remember Flashcards

1
Q

If you are solving for x in an equation that typically have a denominators look like this (x-4 or x+3x+9) and the question is telling you “if there is more than one solution, sepearate them with commas. If there is no solution click No solution” What steps should you take?

A

Find the LCD and then EXCLUDE the values, so if we get them in the answe, we don dont type them

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2
Q

When solving for an equation such as (10x-1)^3/4 what two rules should you rember (hint: x^2=c)

A

Rule 1: Both will be raised to an even number which means you must check the answer in case there are other solutions.
Rule 2 : If the number is negative click on “No solution” and if it positive there will be two solutions + and -

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3
Q

If you get in you answer 0=3 or any number, what does that mean?

A

No solution

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4
Q

If you get in you answer 0=0 or any number, what does that mean?

A

All real numbers are solutions

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5
Q

When you get an equation looks like this (-35=-7/5 w) and it is asking you to solve for w what should you do?

A

Multiply the reciprocal of -7/5 which is -5/7, on both sides

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6
Q

-3-5i conjugate is

A

-3+5

You will need to multiply it with the denominator.

Use it when solving proplems such as 1-3i/-3-5i. to multiply both with the conjugate -3+5

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7
Q

When you get an equation such as y+2/7 = 5/4 what method can you use to solve it?

A

Method of cross product 4(y+2) = 5.7

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8
Q

When you are asked to find the Discriminant and the Number of real number with an equation looks like this 9x^2-6x+1, what should you do?

A

Use the equation under the square root of the quadratic formula which is b^2 - 4(a)(c) and start solving. If the answe was a positive number, the number of real numbers is 2, if the answer is negative the number of real numbers is 0, if the answer is 0 then the number of real numbers is 1

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9
Q

How to solve i^59

A

The factor 2 cannot give us a 59 product, so in this case we will do the following i^58 i then (i)^29 because 2x28=58. Then we will use the fact i = -1 and do the following (-1)^29 i ,we cancel the 29 and get the following (-1) i which give us the following answer -i

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10
Q

What should you do when you face a shape that gave you the perimeter and asking you to find the value of x

A

add all the equations that is shown on the shape sides and solve the equation

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11
Q

How to solve D= 4/7(F+G) Which have only one denominator

A

Since it have the numenator and denominator as real numbers4/7 Ww will multiply it in both sides (when multiplying we convert the numenator with the denominator) and solve we will get 7/4 D-G = F

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12
Q

ALWAYS REMEMBER WHEN SOLVING A RATIIONAL EQUATION TOOO:

A

Find the LCD and exclude the valuse, so if I got the exluded value when answerimng the equation, then I should select “No answer” or not write it down.

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13
Q

If a equation asks you to find how much a (something) will be produce in a set of time (such as 45min) if it is usually produces 240 in 25 min. What should you do?

A

Divide the quantity (240) with the time (25) 240/25 = 9.6. Then I will multiply the answer (9.6) with th time (45 min) which gives me 432

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14
Q

How to multiply (-6+5i)(-3+3i)?

A

We use the FOIL method (18-33i+15i^2) and then we convert the last number which has i^2 (since i^2 is -1, 15i^2 is -15, and so on) and then we subtract the first and last numbers (the 18 and -15 which give us a 3) The final answer will be 3-33i which is a complex number

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15
Q

-3 square root will be

A

i with 3 as a square root (the i should be behind the square root not after)

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16
Q

What should be the first step to solve this quation (w-3)^2=2w^2-15w+27
(EQUATION)^2= EQUATION

A

The first step should be to move the (EQUATION)^2 to the other side WITH SIGNS if it was positive than it should be negative. It should look like this 0= EQUATION(EQUATION)^2 and then you use the FOIL method to solve the (EQUATION)^2 and then you continue to solve the equation.

17
Q

What steps should you take to find the area of a rectangle? (e.q area 52 and length is 5 less than double the width)

REVIEW THIS

Solving a word problem using a quadratic equation with rational roots

A

First write the equation for the length which in this case will be L=2w-5, convert the L to W with will be (2w-5)w= 52 and start to solve for the width. To solve for the length you need to solve using L=2w-5. Take the answer you got from the width which will be 6.5 and solve it.

18
Q

How to solve the following -4 |w| = 12

A

We have to move the -4 to the other side (the 12) and we will doing this be dividing 12/-4 which will give us |w| = -3 since it is negative the answer will be “No solution but if it was positive the answer will be w= 3,-3

19
Q

How to solve the following -3+square root of w+3 = 6

A

First we move the -3 to the other side and it will give us 9. To cancel the square root we have to square both sides to a power of 2, and we will get the following w+3=9^2 then w+3=81. To solve w we have to move the 3 to the other side and the final answer will be w = 78

20
Q

FOUCUS ON SIGNS

A

ok

21
Q

Always let the number with i in the last such as

A

8i + 4 should be 4 + 8i

22
Q

How to solve the following problem 5u^2+15u=0

A

Sinc ther is a u in both sides we will simplify it to 5u(u+3). Then the equation will only be true if one of them is equal to 0. So, 5u= 0 and u= -3. Our answer will be u= 0, -3** (WRITE THE 0)**

23
Q

How to solve the following equation |5u - 6| = |9u + 2|

A

We have to solve this equation using** two diffrent types of soultions. The first we will take of the vertical | and start to solve, in this euation we will get -2 (some time it could be false and does not have any solution)** The second one we will take off the vertical |, but this time** the equation on the right side will be multiplyed with negative one -** {e.q - (9u + 2)} and you include both answers in the final answer.

24
Q

How to solve the following equation -6 |x| = -36

A

If the -6 was in the other side e.q |x| -6 we will use the opposite signel and move it to the other side of the equation. But, because it is -6 |x| we will divide it with the -36 so it will be -6|x|/-6 (which will cancel it and let the |x| alone) and -36/-6 and that will give us 6. So the final answer will be |x| = 6, -6

25
Q

Rule to remeber with eqations that have a variable on it denominator or numinator and a number on it* denominator or numinator *

A

In this case we multiply each number in the equation with the denomiantor whether it is a number or variable. If all were varibales or numbers e.q 2/3 then in this case we will multiply the sides of the equation with 3/2. Which is the opposite of 2/3