RP 8 - Measuring EMF of an Electrochemical Cell Flashcards
What’s an electrochemical cell?
- 2 different half-cells connected by a salt bridge, with their electrodes connected to a voltmeter (measures EMF). This allows the flow of electrons
- The electrical energy generated is from chemical redox reactions
What does an electrochemical cell look like as a diagram?
There are 2 beakers next to each other with solutions in both, both labelled ‘ion inside THAT solution* solution’. There’s also an electrode in both beakers, both labelled ‘element that THAT electrode is made of electrode’. The left-hand side electrode has a wire which is connected to a ‘voltmeter’ which is connected to the other electrode by wire. There’s also a ‘salt bridge’ connected the solutions of both beakers*
What does a half-cell consist of?
- Half-cell are usually metal/metal ion (metal electrode in the metal ion solution) or ion/ion (ions that are the same element but with different oxidation states, in solution)
- Each half-cell will contain the chemical species from one half of a redox reaction (redox half-equation)
What’s a salt bridge?
- A salt bridge allows the transfer of ions
- It’s typically a concentrated solution of an electrolyte i.e. KNO3 (aq) that doesn’t react with either half-cell solution
Why may a graphite or platinum electrode be used?
They’re very unreactive i.e. won’t react with half-cell solutions and won’t affect the voltmeter readings. Usually used in ion/ion half cells
How do you measure comparative electrode potentials of different metals?
- File a piece of copper using emery paper and connect it to the positive voltmeter terminal
- Cut a piece of filter paper, saturate with KNO3 solution and place on top of the copper
- Connect the voltmeter to another piece of metal
- Hold the metal against the filter paper and record the voltmeter value
- Repeat with different metals and record the results in a table
Why do you need to file/sand away the outer layer of the metal when measuring comparative electrode potentials of different metals?
It removes the oxide layer on the outside of the metal