Rotational Motion Flashcards
Condition for rigid body dynamics
Relative distance between two points should not change
Moment of inertia of discrete particle system
Σmiri^2, where mi is the total mass of the body and ri is the perpendicular distance of the body from the axis of rotation
Moment of inertia of a continuous body
∫miri^2, because we are adding small-small particles forming the body
M.O.I of rod when the axis is the passing from one end
ML^2/3, where m= mass of the body and L = length of the body from the axis
M.O.I of rod when the axis is the passing through the centre of mass
ML^2/12, where m= mass of the body and L = length of the body from the axis
M.O.I of ring when the axis is the passing through the centre of mass, perpendicular to the plane of the ring
MR^2, where m = mass of the body and r = radius of the body
M.O.I of disc when the axis is the passing through the centre of mass, perpendicular to the plane of the ring
MR^2/2, where m = mass of the body and r = radius of the body
M.O.I of hollow cylinder, when the axis is the passing through the centre of mass, perpendicular to the plane of the ring
MR^2, where m = mass of the body and r = radius of the body
M.O.I of solid cylinder, when the axis is the passing through the centre of mass, perpendicular to the plane of the ring
MR^2/2, where m = mass of the body and r = radius of the body
M.O.I of solid sphere, when the axis is the passing through the centre of mass, perpendicular to the plane of the ring
2/5MR^2, where m = mass of the body and r = radius of the body
M.O.I of hollow sphere, when the axis is the passing through the centre of mass, perpendicular to the plane of the ring
2/3MR^2, where m = mass of the body and r = radius of the body
Parallel Axis Theorem
I = Ic +md^2, where Ic = moment of inertia from the centre of the body and d = perpendicular distance.
This theorem should only be applied on a axis parallel to Ic
Calculate the MOI of a solid sphere with axis on the tangent of the sphere.
MOI = 2/5Mr^2 + M(R)^2
Perpendicular Axis Theorem
Iz = Ix + Iy, where all the three are perpendicular to each
Iz is perpendicular to the plane of the body, whereas Ix and Iy are parallel to the body
Calculate MOI of ring when the axis is perpendicular to the surface.
Iz = MR^2+Mr^2 = 2MR^2