Redox Flashcards

1
Q

What is oxidation in terms of oxygen?

A

The gain of oxygen

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2
Q

What is oxidation in terms of electrons?

A

The loss of electrons

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3
Q

What does an oxidising agent do?

A

Donate oxygen/accept electrons (it is reduced)

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4
Q

What is reduction in terms of oxygen?

A

The loss of oxygen

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5
Q

What is reduction in terms of electrons?

A

The gain of electrons

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6
Q

What does a reducing agent do?

A

Accept oxygen/donate electrons (it is oxidised)

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7
Q

What are redox reactions?

A

Reactions in which both oxidation and reduction occur

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8
Q

What is the oxidation state for an element ie Fe/Cl2

A

Zero

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9
Q

What is the oxidation state of a metal in its compound?

A

The charge on the ion that it forms

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10
Q

What is the oxidation state of an oxygen atom in a compound?

A

it is -2 unless it is in a peroxide (H2O2) when it is -1

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11
Q

What is the oxidation state of an hydrogen atom in a compound?

A

it is +1 unless in a hydride (NaI) when it is -1

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12
Q

What is the oxidation state of Cl in a compound?

A

it is -1 unless when bonded to F/O when it can have positive values

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13
Q

What is disproportionation?

A

A redox reaction in which the oxidation state of some atoms of a particular element increase in oxidation state and of others decrease in oxidation state

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14
Q

What is the oxidation state of chromium in the Cr²⁺ ion?

A

“+2”

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15
Q

What is the oxidation state of chromium in the CrCl₃?

A

“+3”

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16
Q

What is the oxidation number of iron in iron (III) oxide?

A

“+3”

17
Q

What is the oxidation state of K in K2MnO4?

A

“+1”

18
Q

What is the oxidation state of O in K2MnO4?

A

“-2”

19
Q

What is the oxidation state of Mn in K2MnO4?

A

+6

20
Q

Write a half equation to show a sodium atom forming a sodium ion

A

Na → Na+ + e-

21
Q

“Write a half equation for the following change: Cr2O72- → Cr3+

A

Cr2O7 2-+ 14H+ + 6 e- → 2 Cr3+ + 7 H+

22
Q

Write half equation for MnO4- → Mn2+ and Cl- →Cl2 then combine them

A

2x(MnO4- +5e- + 8H+ → Mn2+ + 4H2O) + 5x(2Cl- →Cl2 +2e-) = 2MnO4- + 16H+ + 10Cl- → 2Mn2+ + 8H2O + 5Cl2