Real Transformer Flashcards
The real voltage ratio is almost the same as the ideal voltage ratio (at no load) and diverges due to voltage drops, increases in resistance, or decreases in current?
Voltage drops
The real current ratio is almost the same as the ideal current ratio (at no load) and diverges as the load decreases due to voltage drops, increase in resistance, or exciting current becoming more signnificant?
Exciting current becomes more significant.
Exciting current is located in ONLY the primary, ONLY the secondary, or BOTH windings?
Only the primary
Exciting current will be present and will not change (remain stable) because the system is energized and the system voltage is unstable. True or false?
False. As long as the system is energized and the system voltage is stable the exciting current will be present.
Exciting current is dependent of the load (True/False)
It is independent of the load.
What are the 4 things that can be done to reduce the exciting current?
- Increase permeability
- Reduce the air gaps
- Insulation on the lamination
- A lower flux density
With regards to reducing exciting current, increasing permeability results in what?
Higher quality core steel
With regards to reducing exciting current, reducing air gaps can be done in 2 ways. What are they?
- Better quality of construction
- Interleaving
Insulation on the lamination reduces eddy current or voltage in the core?
Eddy current
A lower flux density results in a higher exciting current. True/False?
False. It results in a lower exciting current.
Small transformers below 2000VA may have an Iex in the range of 25%, 5%, or 10%
10%
Small transformers between 2000VA and 100kVA may have an Iex in the range of 15%, 10%, or 5%?
5%
Larger transformers at 1000kVA, the Iex% is 1%, 100%, 50%, or 35%?
1%
For very large transformers that are oil filled what is the percentage Iex?
0.1%
A transformer with a 1:1 ratio is rated at 120V and 15A. What would the %Iex be?
S = V * I = 120 * 15 = 1800VA, therefore %IEX ≈ 10% (from above)
IEX = ( %IEX * IRated ) / 100 = 10 * 15 / 100 = 1.5A