Reactions And Mechanisms 2 Flashcards
In terms of reactivity with nucleophiles, order the carbonyl functional groups
Acid chloride Acid anhydride Aldehyde/ketone Ester Amide
Which carbonyl groups can be reduced by NaBH4
Acid chloride
Acid anhydride
Aldehyde/ketone
Which reducing agent is required to reduce an ester to an alcohol?
What is the intermediate functional group?
What can not be used in reactions of LiAlH4?
LiAlH4
Aldehyde
Alcoholic solvents
Which reducing agent is requires to reduce carboxylic acids to alcohols?
What are the reactions steps?
Borane (BH3)
RCOOH -(BH3, -3x H2)-> B(OOCR)3 (triacylborate) -(BH3)-> RCOH
What is the product of an amide being reduced?
Which hydride is used to reduce an amide?
What is formed in one of the intermediate steps?
Why is the mechanism different to when reducing other carbonyl derivatives?
Amine
LiAlH4
Iminium ion
Tetrahedral intermediate does not have such a good leaving group
Does NaBH4 reduce the carbonyl derivates? (Y/N/slow)
Acid chloride - Y Acid anhydride - Y Aldehyde/ketone - Y Ester - slow Amide - N Carboxylic acid - N
Does LiBH4 reduce the carbonyl derivatives? (Y/N/slow)
Acid chloride - Y Acid anhydride - Y Aldehyde/ketone - Y Ester - Y Amide - N Carboxylic acid - N
Does LiAlH4 reduce the carbonyl derivatives? (Y/N/slow)
Acid chloride - Y Acid anhydride - Y Aldehyde/ketone - Y Ester - Y Amide - Y Carboxylic acid - slow (use BH3)
When organometallic reagents react with acid anhydrides/halides, what is the product?
When organometallic reagents react with esters, what is the product?
What causes this difference?
Ketones
Alcohols
Acid anhydride/halide are more reactive than ketone product with reducing agent
With esters, the ketone intermediate is more reactive so 2x reagent needed
How can a carboxylic acid be formed from an organometallic reagent?
- CO2
2. HCl, H2O