Reactions And Conditions (Organic II) Flashcards

1
Q

If a reaction takes place by SN1, is the mixture optically active?

A

No. Since the carbocation intermediate is planar, the nucleophile can “attack” either side of the molecule, meaning both enantiomers are produced in equal measure, thus a racemic mixture is formed which isn’t optically active

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2
Q

If a reaction takes place by SN2, is the product optically active?

A

Yes! Since the nucleophile can only attack the molecule from one side to form the transition state, only one enantiomer is formed so the plane of polarised light is rotated

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3
Q

Conditions and product for reduction of carbonyls

A

-LiAlH4 in dry ether
-forms an alcohol
-reducing reagent represented as [H]

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4
Q

How is an oxidising agent represented

A

[O]

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5
Q

What is Tollens reagent and what does it show

A

-Ag+ complex
-when an aldehyde is present, it undergoes redox with it to be reduced to Ag, forming a silver mirror out of colourless solution
-this is a test for aldehydes only, since ketones can’t be oxidised

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6
Q

What is Fehlings solution and what does it show

A

-Cu2+ complex
-when an aldehyde is present, it undergoes redox with it by being reduced to Cu+ forming a red precipitate out of blue solution
-since ketones can’t be oxidised, this acts as a test for aldehydes
-this is the same for Benedict’s solution

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7
Q

What does acidified potassium dichromate test for

A

-presence of aldehyde (colour change from orange solution to green solution)
-will remain orange for ketones since they can’t be oxidised

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8
Q

Describe the iodofrom/ triiodomethane test (Test for what, positive result, conditions)

A

-tests for the CH3CO group (thus only working for ethanol and methyl ketones)
-positive result is the formation of a yellow precipitate out of colourless solution with a medicinal smell
-conditions=an alkaline solution of I2 that’s heated before being cooled
Reaction with ethanol looks like:

CH3CHO + 2I2 + 2NaOH-> CHI3 + NaI + H2O + CHO-Na+

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9
Q

Conditions and product of nucleophilic addition of CN to carbonyls

A

-HCN dissolved in an aqueous, alkaline solution of KCN (HCN in KCN)
-produces a hydroxynitrile
-depending on conditions given, the H+ ion may come from either the HCN or an acidic/aqueous work up
-this is an SN1 mechanism, forming a racemic mixture

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10
Q

What does 2,4-DNPH test for? What is a positive result how can the product of this test be used to determine the exact compound present?

A

-Test for the carbonyl group (so aldehydes and ketones)
-positive result is the formation of a bright red/orange precipitate out of colourless solution
-To determine the exact compound, take the melting point of the derivative by filtering and recrystallising it, then compare to a data book value to find the exact compound

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11
Q

What are the 3 ways of preparing a carboxylic acid?

A

-oxidising a primary alcohol (with warm acidified potassium dichromate under reflux)
-oxidising an aldehyde (as above)
-hydrolysis of a nitrile (heat under flux with dilute acid or aqueous alkali—acid hydrolysis will straight up produce an acid but base hydrolysis produces a carboxylate salt that can become an acid by adding dilute acid)

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12
Q

Conditions and product of carboxylic acid reduction

A

-same as carbonyls
-LiAlH4 in dry ether
-forms a primary alcohol

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13
Q

Conditions and product of carboxylic acid neutralisation

A

-react with aqueous alkali
-forms a carboxylate salt

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14
Q

Conditions and product of carboxylic acid halogenation

A

-PCl5 in anhydrous conditions (because both the reagent and the acyl chloride are reactive in water)
-forms an acyl chloride (COCl group)
-since HCl is also formed, you may observe steamy fumes, and the POCl3 formed can be separated by fractional distillation

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15
Q

Conditions and reduction of carboxylic acid esterification

A

-react with an alcohol
-acid catalyst (usually conc. sulphuric)
-reversible reaction
-forms an ester (COO)

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16
Q

How do you name an ester

A

Alcohol first, acid second

17
Q

Product of acyl chloride reaction with water (and example reaction)

A

-forms an carboxylic acid

CH3COCl + H2O —> CH3COOH + HCl

18
Q

Product of acyl chrloide reatcion with alcohol (and example)

A

-forms an ester

CH3COCl + CH3CH2OH —> CH3COOCH3CH2 + HCl

19
Q

Product of acyl chloride reaction with concentrated ammonia (plus the overall reaction AND the two steps)

A

-forms a primary amine
Overall reaction:
CH3COCl + 2NH3 —> NH4Cl + CH3CONH2
First step:
CH3COCl + NH3 —> CH3CONH2 + HCl
Second step (occurs since HCl is acidic and NH3 is basic so they react to form a salt):
NH3 + HCl —> NH4Cl

20
Q

Product of acyl chloride reaction with an amide (an example equation for both primary and secondary)

A

-forms another amide (N-substituted)
With a a primary amide:
CH3COCl + CH3NH2 —> CH3CONHCH3 + HCl (forms an N-substituted amide AKA secondary)
With a secondary amide:
CH3COCl + (CH3)2NH —> CH3CON(CH3)2 + HCl (forms an N-N-substituted amide AKA tertiary amide)

N substituted basically just means there are alkyl group surrounding the nitrogen instead of just hydrogen

21
Q

What are the products of ester hydrolysis

A

It’s basically reverse esterification, so you form a carboxylic acid and an alcohol

22
Q

What’s the difference between acid ester hydrolysis and base ester hydrolysis (2):

A

-acid hydrolysis is reversible and base hydrolysis isn’t
-base hydrolysis forms a carboxylate salt instead of a carboxylic acid (the acid can be easily made by adding acid)

23
Q

Which type of ester hydrolysis is preferable and why?

A

Base hydrolysis is preferable to acid because the reaction is not reversible and so doesn’t not reach an equilibrium, meaning the reaction is able to go to completion

24
Q

Reactants and products of condensation of polymerisation of carbonyls

A

-diol and dicarboxylic acids react to form a polyester
-in the presence of an acid
-a small molecule (water is also formed) for each bond made, unlike addition polymerisation