Quiz 8 Flashcards by Corey Beltran

The equation that defines the voltage drop across loads in a series circuit is E = I x R.

True or False?

True.

DC Theory 3rd Ed. Textbook, Chap. 1, Pg. 24

How well did you know this?

Not at all

Perfectly

The current in a series circuit will decrease as it passes through each resistor.

True or False?

False.

DC Theory 3rd Ed. Textbook, Chap. 4, Pg. 95

How well did you know this?

Not at all

Perfectly

A voltage ? can be used to break down a supply voltage into two or more smaller voltages.

a. converter
b. divider
c. multiplier
d. reducer

b. divider

DC Theory 3rd Ed. Textbook, Chap. 7, Pg. 157

How well did you know this?

Not at all

Perfectly

The amount of voltage drop across the resistor will be directly proportional to its resistance and the circuit current.

True or False?

True.

DC Theory 3rd Ed. Textbook, Chap. 7, Pg. 157

How well did you know this?

Not at all

Perfectly

In a series circuit, the total voltage dropped across all of the loads is equal to the ? .

a. electromotive force
b. resistance
c. source voltage
d. total current

c. resistance

DC Theory 3rd Ed. Textbook, Chap. 7, Pg. 158

How well did you know this?

Not at all

Perfectly

When two batteries are connected as a series additive power source, they produce a voltage that is greater than either of the batteries connected separately.

True or False?

Do two batteries produce more voltage than one?

True.

V in Series Circuits, “Power Sources in Series,” Paragraph 2, Sentence 3

How well did you know this?

Not at all

Perfectly

In a series additive power source, the ? is equal to the sum of the individual voltages.

a. current
b. resistance
c. total current
d. total voltage

d. total voltage

V in Series Circuits, “Power Sources in Series,” Paragraph 2, Sentence 4

How well did you know this?

Not at all

Perfectly

When two batteries are connected as a series adding power source, the positive terminal of one battery is connected to the positive terminal of the other battery.

True or False?

False.

V in Series Circuits, “Power Sources in Series,” Paragraph 2, Sentence 1

How well did you know this?

Not at all

Perfectly

An increase in current through a resistor will result in a decrease in voltage drop across the resistor.

True or False?

False.

DC Theory 3rd Ed. Textbook, Chap. 4, Pg. 98

How well did you know this?

Not at all

Perfectly

The resistor in the circuit that will have a voltage drop of eight volts is ? .

Eₜ = x V
R₁ = x Ω
R₂ = x Ω
R₃ = x Ω
R₄ = x Ω

a. R₁
b. R₂
c. R₃
d. R₄

b. R₂

DC Theory 3rd Ed. Textbook, Chap. 7, Pg. 158

Rₜ = R₁ + R₂ + R₃ + R₄ = 2 + 4 + 6 + 3
= 15 Ω

Iₜ = Eₜ / Rₜ
= 30 / 15
=2 A

Eᴿ¹ = Iᴿ¹ × R₁ = 2 × 2 = 4 V
Eᴿ² = Iᴿ² × R₂ = 2 × 4 = 8 V
Eᴿ³ = Iᴿ³ × R₃ = 2 × 6 = 12 V
Eᴿ⁴ = Iᴿ⁴ × R₄ = 2 × 3 = 6 V

How well did you know this?

Not at all

Perfectly

In a series circuit, loads that have the same ? will have the same resistance values.

a. source voltage
b. total current
c. voltage drop across them
d. wattage consumed

c. voltage drop across them

DC Theory 3rd Ed. Textbook, Chap. 7, Pg. 157

How well did you know this?

Not at all

Perfectly

Use the resistance value of the lamps and the ammeter reading to find the voltage measured across the battery terminals.

Eₜ = x V
R₁ = 3 Ω
R₂ = 4 Ω
R₃ = 5 Ω
Iₜ = 2.5 A

a. 12 V
b. 18 V
c. 24 V
d. 30 V

d. 30 V

Rₜ = R₁ + R₂ + R₃
= 3 + 4 + 5
= 12 Ω

Eₜ = Rₜ × Iₜ
= 12 × 2.5
= 30 V

How well did you know this?

Not at all

Perfectly

The formula for finding the voltage applied to a series circuit when using two series-opposing power sources is ? .

a. Eₜ = Eᴸᵃʳᵍᵉʳ - Rₜ
b. Eₜ = Eᴸᵃʳᵍᵉʳ - Eˢᵐᵃˡˡᵉʳ
c. Eₜ = Eᴸᵃʳᵍᵉʳ + Eˢᵐᵃˡˡᵉʳ
d. Eₜ = Eᴸᵃʳᵍᵉʳ + Rₜ - Cₜ

b. Eₜ = Eᴸᵃʳᵍᵉʳ - Eˢᵐᵃˡˡᵉʳ

V in Series Circ, “Placing P Sources in Series,” Paragraph 2, Sentence 4

How well did you know this?

Not at all

Perfectly

In a voltage divider, the sum of the ? across all of the resistors must equal the applied voltage.

a. applied power
b. resistance
c. total current
d. voltage drops

d. voltage drops

DC Theory 3rd Ed. Textbook, Chap. 7, Pg. 157

How well did you know this?

Not at all

Perfectly

In this circuit, the voltmeter is measuring the voltage dropped across the R4 lamp. The reading is ? .

Eₜ = 24 V
R₁ = 2 Ω
R₂ = 3 Ω
R₃ = 3 Ω
R₄ = 4 Ω
R₅ = 4 Ω

a. 6 V
b. 8 V
c. 10 V
d. 12 V

a. 6 V

Rₜ = R₁ + R₂ + R₃ + R₄ + R₅
= 2 + 3 + 3 + 4 + 4
= 16 Ω

Iₜ = Eₜ / Rₜ
= 24 / 16
= 1.5 A

Eᴿ⁴ = Iᴿ⁴ × R₄
= 1.5 × 4
= 6 V

How well did you know this?

Not at all

Perfectly

The selector is in the 150 DCV position. Indicate the correct voltage value.

a. 60 VDC
b. 70 VDC
c. 120 VDC
d. 220 VDC

a. 60 VDC

The selector is in the 30 DCV position. Indicate the correct voltage value.

a. 2 VDC
b. 5 VDC
c. 10 VDC
d. 20 VDC

a. 2 VDC

Voltage in Series Circuits, “Using a Voltmeter,” Paragraph 4, Sentence 2

The selector is in the 600 DCV position. Indicate the correct voltage value.

a. 120 VDC
b. 125 VDC
c. 250 VDC
d. 500 VDC

d. 500 VDC

Voltage in Series Circuits, “Using a Voltmeter,” Paragraph 4, Sentence 2

The selector is in the 200 mDCV position. Indicate the correct voltage value.

a. 0.015 mVDC
b. 0.15 mVDC
c. 1.5 mVDC
d. 15 m VDC

c. 1.5 mVDC

Voltage in Series Circuits, “Using a Voltmeter,” Paragraph 9, Sentence 3

The selector is in the 1,000 DCV position. Indicate the correct voltage value.

a. 0.277 VDC
b. 2.77 VDC
c. 27.7 VDC
d. 277 VDC

d. 277 VDC

Voltage in Series Circuits, “Using a Voltmeter,” Paragraph 9, Sentence 3

The selector is in the 20 DCV position. Indicate the correct voltage value.

a. -17.26 mVDC
b. -17.26 VDC
c. -172.6 VDC
d. -1,726 VDC

b. -17.26 VDC

Voltage in Series Circuits, “Using a Voltmeter,” Paragraph 9, Sentence 3

In the following circuit, the voltmeter is measuring the voltage drop across the R3 lamp. The voltmeter reading is ? .

Eₜ = x V
E₁ = x V
E₂ = x V
R₁ = 4 Ω
R₂ = 6 Ω
R₃ = 5 Ω
Iₜ = 4 A

a. 12 V
b. 16 V
c. 20 V
d. 24 V

c. 20 V

DC Theory 3rd Ed. Textbook, Chap. 7, Pg. 158

Eᴿ³ = Iᴿ³ × R₃
= 4 × 5
= 20 V

First, find the total circuit resistance. Next, with the given voltage drop across R1 and using proportionality laws, find the total source voltage. The DC battery delivers ? to the circuit.

Eₜ = 24 V
Rₜ = x Ω
R₁ = 12 Ω
R₂ = 9 Ω
R₃ = 3 Ω
Eᴿ¹ = 6 V

a. 6 V
b. 12 V
c. 18 V
d. 24 V

b. 12 V

DC Theory 3rd Ed. Textbook, Chap. 7, Pg. 158

Rₜ = R₁ + R₂ + R₃
= 12 + 9 + 3
= 24 Ω

Set up and work the equation:

Eᴿ¹ / R₁ = Eₛ / Rₜ
6 V / 12 Ω = Eₛ / 24 Ω
= 6(24) = Eₛ(12)
= 144 = Eₛ(12)
= 144 / 12 = Eₛ
= 12 V

Solve for the voltage drop across R1 by using the given voltage and resistance values. The R1 voltmeter reads ? .

Eˢ¹ = 18 V
Eˢ² = 16 V
R₁ = 8 Ω
R₂ = 24 Ω
R₃ = 18 Ω
R₄ = 18 Ω
Eᴿ¹ = x V
Eᴿ² = 12 V
Eᴿ³ = x V
Eᴿ⁴ = 9 V

a. 4 V
b. 8 V
c. 12 V
d. 16 V

a. 4 V

DC Theory 3rd Ed. Textbook, Chap. 7, Pg. 158

Eₜ = Eˢ¹ + Eˢ²
= 18 + 16
= 34 V

Eₜ = Eᴿ¹ + Eᴿ² + Eᴿ³ + Eᴿ⁴
34 = Eᴿ¹ + 12 + 9 + 9
34 = Eᴿ¹ + 30
Eᴿ¹ = 4 V

Because the resistance values of R3 and R4 are equal, the voltage dropped across these resistors is also equal.

Current outside of the power source in a series circuit always flows from negative to positive. True or False?

True. | DC Theory 3rd Ed. Textbook, Chap. 1, Pg. 4

Voltage is a difference of ? between two points in a circuit. a. current and resistance b. potential c. resistance d. voltage drop

b. potential | DC Theory 3rd Ed. Textbook, Chap. 1, Pg. 12

This circuit has a series additive power source. One battery is rated at 12 volts. The voltage of the other is unknown. The voltmeter measuring across the battery with the unknown potential reads ? . Eˢ¹ = 12 V Eˢ² = x V R₁ = 6 Ω R₂ = 6 Ω R₃ = 6 Ω R₄ = 6 Ω Iₜ = 1.5 A a. 6 V b. 12 V c. 24 V d. 30 V

c. 24 V ## Footnote Rₜ = R₁ + R₂ + R₃ + R₄ = 6 + 6 + 6 + 6 = 24 Ω Eₜ = Rₜ × Iₜ = 24 Ω × 1.5 A = 36 V Eˢ² = Eₜ - Eˢ¹ = 36 - 12 = 24 V

The total of the ? across the loads of a series circuit can never exceed the total of the source voltages applied to that circuit. a. current b. resistance c. resistors d. voltage drops

d. voltage drops | DC Theory 3rd Ed. Textbook, Chap. 4, Pg. 95

When two or more sources are connected series-opposing, the applied voltage may be less than the largest source. True or False?

True. | V in Series Circ “Placing P. Sources in Series,” Paragraph 2, Sentence 1

The voltage drop across R4 is ? . Eₜ = 110 V Eᴿ¹ = 15 V Eᴿ² = 25 V Eᴿ³ = 30 V Eᴿ⁴ = x V a. 40 V b. 55 V c. 70 V d. 95 V

a. 40 V | DC Theory 3rd Ed. Textbook, Chap. 7, Pg. 157 ## Footnote Eₜ = Eᴿ¹ + Eᴿ² + Eᴿ³ + Eᴿ⁴ 110 = 15 + 25 + 30 + Eᴿ⁴ 110 = 70 V + Eᴿ⁴ 40 V = Eᴿ⁴

Find the total resistance and circuit current to solve for the voltage drop across R2. The potential difference across the R2 resistor is ? . Eₜ = 100 V R₁ = 50 Ω R₂ = 10 Ω R₃ = 20 Ω Eᴿ² = x V

b. 12.5 V | DC Theory 3rd Ed. Textbook, Chap. 4, Pgs. 99-100 ## Footnote Rₜ = R₁ + R₂ + R₃ = 50 + 10 + 20 = 80 Ω Iₜ = Eₜ / Rₜ = 100 / 80 = 1.25 A Eᴿ² = R₂ × Iᴿ² = 10 × 1.25 = 12.5 V

In this circuit, the voltmeter reading is ? . Eˢ¹ = 30 V Eˢ² = 30 V R₁ = 5 Ω (R₂ = 5 Ω, R₃ = 5 Ω, R₄ = 5 Ω)

c. 45 V | DC Theory 3rd Ed. Textbook, Chap. 4, Pg. 99 ## Footnote Eₜ = Eˢ¹ + Eˢ² = 30 + 30 = 60 V 60 V / 4 equal resistances = 15 V each 15 V × 3 resisantances being tested = 45 V