Quant Flashcards
When I do smart numbers
I’ll avoid weird numbers like 0, 1 and fractions and the numbers in the problem
If I want to check divisibility by 9
I check to see if sum of digits is divisible by 9
What are the first 5 prime numbers?
2,3,5,7,11
What are the 6th to 10th prime numbers
13, 17, 19, 23 ,29
If I want to check divisibility by 8
I can divide by 2 three times
or
I can check if the last 3 digits are divisible by 8
If I want to check divisibility by 6
I need to make sure it’s divisible by 2 & 3
If I want to check divisibility by 4
I can divide by 2 twice
or
I can check if the last 2 digits are divisible by 4
If I want to know if a # is divisible by 3
I sum the digits of the number (Integers only) and check if it’s divisible
If N is a divisor of X & Y
Then N is a divisor of X + Y
When checking divisibility of a large number by another large number
I can check if it’s divisible by a factor pair of the divisor
ex 6750 div by 18
6750/2 works
and
6750/9 works
2*9=18 so it works
√ 2
approx 1.4
√ 3
Approx 1.7
11^2
121
13^2
169
14^2
196
15^2
225
16^2
256
25^2
625
4^3
64
5^3
125
10^3
1000
It is a zero per power
When do you Test Cases in Problem Solving?
You use it when the problem asks a must be or could be question
When do you Test Cases in Data sufficiency
Use it when several unknowns and it’s a Y/N question
x^2 - y^2=
(x+y) (x-y)
x^2 - 2xy + y^2 =
(x-y) (x-y) or (x-y)^2
x^2 + 2xy + y^2
(x+y) (x+y) or (x+y)^2
When should you use smart numbers?
Problem solving only for variable expressions, relative values in answers or the problem never gives a real #
When should you work backwards?
Problem solving only when answers are nice real numbers or if there is only 1 variable
If I see
x^2 - x < 0
or
x^2 < x
They both say that 0 < x < 1
If I see XY < 0
I know X and Y have opposing signs
If I see XY > 0
I know X and Y have the same sign
(a + b)/c =
a/c + b/c
If two denominators share a factor
It is faster to find the least common multiple instead of cross multiplying.
ex: 6&8 least common multiple of 24
-(3)^2=
-9
(-3)^2+
9
3^4=
81
x^2=16 x=
4^2 or -4^2
x^3 * x^4 =
x^7
always add the exponents for multiplication
x^3 + x^4=
Can only be changed through factoring
x^3(1+x)
(x^y)/ x^2 =
x^(y-2)
x^-2 =
1/x^2
(x^2)^4 =
x^8 you multiply with exponents
(ab)^3=
(a^3)(b^3)
(x/y)^2 =
(x^2)/(y^2)
Prime factorization of 18^3 is
(2^3)(3^6)
18= 29 =2(3^2)
(2*(3^2))^3= (2^3)(3^6)
(2^3)*(3^3)=
(6^3)
Only works if they have the same exponents
How do you estimate a root of a non perfect square ex:70?
Look for the perfect squares nearby and estimate
ex: 64^0.5 = 8 and 81^0.5= 9 so 70^0.5 is approx 8.5
What happens when you square root a number between 0 & 1?
You get a larger number because division by a number less than 1 and larger than 0
What is the main difference in cube root vs root main in regards to negativity
You can cube root a negative number but not normal root one.
8^2/3 =
(8^1/3)^2 = (2)^2 = 4
√x * √y =
√xy
√x/√y =
√x/y