PSCI Quiz 4 Flashcards

1
Q

What is the average temperature of healthy humans on the Celsius scale?

A

37º

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2
Q

Molecules in a solid

A

are held in nearly fixed positions by strong attractive forces.

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3
Q

The averge kinetic energy of a gas is proportional to

A

the temperature of the gas.

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4
Q

When water vapor condenses to a liquid

A

it transfers heat to the surroundings.

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5
Q

The water in a swimming pool is cooler than the surrounding sidewalk because it

A

has a higher specific heat.

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6
Q

The heat needed to warm one gram of water one Celsius degree is called a

A

calorie

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7
Q

The Fahrenheit temperature reading on a cold winter day in Montana is -28 °F. What is this reading on the Kelvin scale?

A

240

Convert from Tf to TC then to TK.

Tc = 5/9 * ( TF - 32)

TK = TC + 273

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8
Q

A 1.09 kg metal head of a hammer strikes a solid rock with a velocity of 5.98 m/s. Assuming all the kinetic energy of the hammer is retained by the hammer head and converted into thermal energy, how much will the hammer head increase in temperature? Hint: watch your conversion of units!

c head = 0.147 kcal / kg°C

A

0.029

KE –> Heat

KE = 1/2 (mass [kg]) * (velocity [m/s])2 =Joules

Convert Joules to calories

KE * 1 cal/ 4.184 J = heat in calories

Find delta T

Q (cal.) / (m (kg) * C8 (kcal/kg ºC))

then divide by 1000 because 1kcal = 1000 calories.

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9
Q

How many minutes would be required for a 253 W immersion heater to heat 293 g of water from 17 °C to 85 °C? The specific heat capacity of liquid water is 1.00 cal/(g C).

A

5.49

heat required = Q = m Cs (Tf - Ti) *4.184 J/cal = heat or energy in Joules

P = Work / time

time = Work / Power * 1min / 60 sec

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10
Q

A 2.74 kg block of ice at 0.0°C is added to a picnic cooler. How much heat will the ice remove from the cooler as it melts to water at 0.0°C? The latent heat of fusion of ice is 80.0 cal/g. Provide your answer in kcal (kilocalories or Calories).

A

219.2

Q (Heat) = mass * latent heat of fusion = m * Lv

Q = mass (kg) * (1000 g / 1 kg) * 80.0 cal / g * (1 kcal / 1000 cal) =

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