Prok & Euk Part 2: Control Flashcards

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1
Q

What is heterochromatin?

A

It is a highly compacted DNA where DNA winds more tightly around histones, this results in the silencing of genes as it limits access of RNA polymerase and general transcription factors to promoters of genes and thus prevent formation of transcription initiation complex

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2
Q

What is euchromatin?

A

It is a less compacted DNA where DNA winds less tightly around histones. it allows access of RNA polymerase and general transcription factors to promoters of genes, allowing formation of transcription initiation complex.

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3
Q

What is the chromatin remodeling complex?

A

They are protein complexes that alter structure of nucleosomes temporarily, resulting in either DNA being less tightly bound to histones or DNA being more tightly coiled around histones.

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4
Q

What is DNA Methylation

A

DNA methylation involves the addition of methyl group to nucleotides in CG sequences.

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5
Q

How does DNA Methylation prevent transcription?

A
  • It blocks the binding of general transcription factors and thus assembly of transcription initiation complex at promoter
  • It recruits DNA-binding proteins to the methylated DNA to condense chromatin, resulting in gene silencing
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6
Q

What is histone acetylation or disacetylation?

A

Acetylation and disacetylation of histones allows chromatin to decondense and condense respectively, alternating between loose and tightly condensed states.

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7
Q

What enzyme catalyses histone acetylation?

A

Histone Acetyl Transferase

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8
Q

Describe the process of histone acetylation.

A

Addition of acetyl groups to lysine residues removes positive charges on histones. Tight binding between DNA and histones is loosened making promoter region more accessible to RNA polymerase and general transcription factors. This works in concert with chromatin remodeling complex, allowing formation of the transcription initiation complex

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9
Q

What enzyme catalyses histone deacetylation?

A

Histone Deacetylase

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10
Q

Describe the process of histone deacetylation.

A

it involves the removal of the acetyl groups, restoring a tighter interaction between DNA and histones, inhibiting transcription

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11
Q

Describe gene amplification.

A

It refers to the replication of a specific gene multiple times to create more copies of that gene. Thus, during transcription and translation, more copies of mRNA and required proteins will be obtained.

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12
Q

Describe the initiation of transcription.

A

The general transcription factors assemble at the TATA box in the promoter region. Transcription factors recruits RNA polymerase and positions it correctly at the promoter. Whole complex of GTFs and RNA polymerase is called a transcription initiation complex.

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13
Q

What can control elements be divided into?

A

Proximal control elements (e.g. promoters) and distal control elements (e.g. enhancers and silencers)

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14
Q

How does activators binding to enhancers increase frequency of transcription?

A
  • Upon binding of activators to enhancers, spacer DNA (regions of non-transcribed DNA between genes) bends. Bending of spacer DNA allows direct interaction of activators with RNA polymerase and general transcription factors at the promoter, promoting assembly of transcription initiation complex.
  • Bound activator may recruit histone acetyl transferase and chromtin remodeling complex to decondense chromatin, allowing greater accessibility of general transcription factors and RNA polymerase to the promoter
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15
Q

How does repressors binding to silencers decrease frequency of transcription?

A
  • Interferance with action of activators by masking DNA activation site, competitive DNA binding or direct interaction with general transcription factors.
  • Bound repressors may recruit histone disacetylase and repressible chromatin remodeling complex to condense chromatin, reducing accessibility of general transcription factors and RNA polymerase to the promoter
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16
Q

What enzyme is involved in the splicing of pre-mRNA?

A

Spliceosome or a snRNA (small nuclear RNA) -protein complex

17
Q

What is the importance of poly-A tail at the 3’ end of mRNA

A
  • Enhances half-life/stability of mRNA by slowing down its degradation by ribonucleases
  • serves as a signal to direct export of mature mRNA from nucleus to cytoplasm
  • interacts with initiation factors to form translation initiation complex
18
Q

Describe the initiation of translation

A

Small ribosomal subunit, eukarotic translation initiation factors and initiator-tRNA form a complex. The complex binds to the 5’ cap and poly-A tail causing the mRNA to circularise. The complex then moves in the 5’ to 3’ direction along the mRNA to scan for and locate the start codon, AUG. Bind of the large ribosomal subunit completes the translation initiation complex.

19
Q

What are the controls at translational level?

A
  • mRNA stabilty/half-life
  • Anti-sense RNAs
  • Binding of translation repressors
  • Initiation factors
20
Q

What are the controls at transcriptional level?

A
  • Promoter
  • Enhancers and silencers
21
Q

What are the controls at genomic level?

A
  • Chromatin remodeling complex
  • DNA methylation
  • Histone acetylation/disacetylation
22
Q

What are the controls at post-transcriptional level?

A
  • Capping at 5’ end of mRNA
  • Splicing of pre-mRNA
  • Adding of poly-A tail to 3’ end
23
Q

What are the controls at the post-translational level?

A
  • Covalent modifiations to form functional proteins
  • Phosphorylation - dephosphorylation to regulate protein activity
  • Protein degradation
24
Q

Describe the function of anti-sense RNA.

A

Under certain conditions, anti-sense RNA which is complementary to part of the mRNA to be degraded will be synthesised. It will complementary base pair with mRNA to form double stranded RNA. The double stranded RNA will be targeted for degradation by ribonucleases and will block translation of the mRNA

25
Q

Describe the function of translation repressors.

A

Translation initiation can be blocked by preventing formation of translation initiation complex. This can be achieved when small ribosomal subunit cannot bind and is blocked by a translational repressor protein that bind to:
(a) 5’ cap and/or its vicinity
(b) 3’ untranslated region to interfere with interaction between 3’ poly-A tail, initiation factors and 5’ cap needed for translation

26
Q

How does covalent modifications control proteins?

A

Covalent modifications in the form of glycosylation, disulfide bond formation and attachment of prosthetic groups may be necessary for protein activation.

27
Q

How does phosphorylation and dephosphorylation regulate protein activity?

A

Addition of phosphate group to protein can render it active or inactive, while dephosphorylation has the opposite effects.

28
Q

Describe the process of protein degradation.

A

Ubiquitin ligase tags a protein for degradation by catalysing the addition of protein, ubiquitin to target protein. The ubiquitin-tagged protein is then recognised by a proteasome which cleaves this protein into smaller peptides which can be further degraded by enzymes in cytoplasm.