Practice Test 2 Flashcards

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D. Disulfide bonds [69%]
Process of Elimination
Option A. Hydrogen bonds – This option is incorrect because hydrogen bonds are a form of intermolecular force, which results when hydrogen is either bonded to nitrogen, oxygen, or fluorine. Hydrogen bonding is observed between complementary nitrogenous bases (adenine — thymine and cytosine — guanine). Since hydrogen bonding is present in DNA, this option is incorrect.

Option B. Phosphodiester bonds – This option is incorrect because phosphodiester bonds are the result of a condensation reaction between the 3’ OH group of one nucleotide and the 5’ phosphate group of a separate nucleotide. This results in a linkage between adjacent nucleotides. These reactions form the negatively charged backbone of DNA molecules.

Option C. Covalent bonds – This option is incorrect. Covalent bonds form when two atoms share their electrons with each other. Phosphodiester bonds are considered covalent bonds and since phosphodiester bonds are seen within DNA, this option is incorrect.

Option E. Van der Waals forces – This option is incorrect. Van der Waals forces, also known as London dispersion forces, are present between all molecules, including DNA. Van der Waals forces result from a temporary and weak dipole-dipole interaction between two molecules in close proximity. Van der Waals forces can be observed between adjacent nucleotides in the DNA strand, therefore, this option is incorrect.

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C. Vasopressin [74%]

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C. Genetic equilibrium requires a lack of evolution [77%]

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B. Neutrophils [74

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D. Intermediate filaments [86%]

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E. Neural tube [86%]

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