Practice Exam Questions Week 4 Flashcards
In a population of Mendel’s garden peas, the frequency of the dominant A (yellow flower) allele is 80%. Let p represent the frequency of the A allele and q represent the frequency of the a allele. Assuming that the population is in Hardy-Weinberg equilibrium, what are the genotype frequencies?
64% AA, 32% Aa, 4% aa
16% AA, 40% Aa, 44% aa
80% AA, 10% Aa, 10% aa
75% AA, 15% Aa, 10% aa
50% AA, 25% Aa, 25% aa
64% AA, 32% Aa, 4% aa
Why:
If a population is not in Hardy-Weinberg equilibrium, we can conclude that:
natural selection has occurred.
All of these choices are correct.
nonrandom mating has occurred.
evolution has occurred because one or more of the assumptions of the Hardy-Weinberg equilibrium has been violated.
evolution has occurred because one or more of the assumptions of the Hardy-Weinberg equilibrium has been violated.
Why:
For reciprocal altruism to work, individuals must be able to:
recognize one another, remember previous interactions, and calculate the fitness value of individual interactions.
recognize one another and remember previous interactions.
calculate the fitness value of individual interactions.
remember previous interactions.
recognize one another.
recognize one another and remember previous interactions.
Why:
Imagine the following genotype frequencies in a population: p2 = 0.49, 2pq = 0.42, q2 = 0.09. Now assume that there is nonrandom mating where individuals with one genotype will only mate with individuals that also have their genotype. Assume this pattern of mating goes on until the frequency of heterozygotes is effectively zero. In addition, there is also inbreeding depression such that individuals with the genotype represented by p2 die before they can reproduce. What will be the frequency of allele q?
- 91
- 7
- 0
- 49
- 3
1.0
Why:
Imagine the following genotype frequencies in a population: p2 = 0.49, 2pq = 0.42, q2 = 0.09. Now assume that there is nonrandom mating where individuals with one genotype will only mate with individuals that also have their genotype. Assume this pattern of mating goes on until the frequency of heterozygotes is effectively zero. What will the frequency of allele p be in the population?
- 0
- 91
- 3
- 7
- 49
0.7
Why:
Imagine the following genotype frequencies in a population: p2 = 0.49, 2pq = 0.42, q2 = 0.09. Now assume that there is nonrandom mating where individuals with one genotype will only mate with individuals that also have their genotype. Assume this pattern of mating goes on until the frequency of heterozygotes is effectively zero. Is this population in Hardy-Weinberg equilibrium?
No, because allele frequencies changed.
No, because there is nonrandom mating.
Yes, because there is not inbreeding depression.
Yes, because allele frequencies did not change.
No, because there is nonrandom mating.
Why: Violates the assumptions of Hardy-Weinburg equilibrium
Suppose that kin selection is acting upon a group of rodents. The average female typically has four offspring in her lifetime. If, instead of raising her own offspring, a female helps her sister raise her offspring (i.e. her own nieces and nephews). How many offspring would her sister have to have in order for her to experience no net loss in fitness?
4
12
8
10
8
Why:
Inbreeding depression is a serious concern in small populations of endangered organisms. Why is inbreeding depression a concern for such populations?
Related individuals will not mate with one another, and this increases the probability that two deleterious alleles will be present when unrelated individuals mate.
Related individuals are more likely to mate with one another and this will increase the frequency of heterozyous genotypes.
Related individuals are more likely to mate with one another and this increases the probability that two deleterious alleles will be present in the offspring.
Related individuals will not mate with one another, therefore population number will decline.
Related individuals are more likely to mate with one another and this increases the probability that two deleterious alleles will be present in the offspring.
Why:
In a population of Mendel’s garden peas, the frequency of green-flowered plants (genotype aa) is 49%. The population is in Hardy-Weinberg equilibrium. What are the frequencies of the AA and Aa genotypes?
9% AA, 42% Aa
33% AA, 18% Aa
49% AA, 2% Aa
42% AA, 9% Aa
The frequencies cannot be determined from the information provided.
9% AA, 42% Aa
Why:
