Power supplies Flashcards

1
Q

Batteries in series add voltages where batteries in parallel add currents.

A

true

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
2
Q

A dual-voltage power supply is also called a ? .

A

bipolar supply

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
3
Q

Which of the following is not one of the steps or processes involved in a complete power supply system?

A

Combining the outputs of the taps

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
4
Q

When connecting power supplies that convert AC to DC, note that the ? will determine the load polarity.

A

diode polarity

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
5
Q

If the waveform across a load resistor is observed to be half-wave pulsating direct current, the rectifier is classified as a ? rectifier.

A

half-wave

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
6
Q

Which of the following represents a half-wave rectifier for the positive input half cycle?

A

b

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
7
Q

Which of the following represents the waveform across RL?

A

a

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
8
Q

Find the effective (rms) voltage of the “AC source.“ Hint: This is a pure sine-wave calculation; do not deduct for the diode.

A

Vp = Vp - p/2

Veff = Vp/sq root 2

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
9
Q

The half-wave average voltage across load RL is ? . Hint: The deduction for the diode must be included in the calculation. Calculate your answer to two decimal places.

A

Vp(load) = Vp(xfmr) - Vd

Vl(avg) = Vp(load)/pi

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
10
Q

The peak current through load RL is ? . Calculate your answer to three decimal places.

A

Ip(load) = Vp(xmfr) - Vd/Rl

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
11
Q

A ? rectifier uses a center-tapped transformer secondary and two diodes.

A

full-wave

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
12
Q

A waveform across the load of a full-wave rectifier is pulsating direct current with half the peak voltage of the secondary because of the center-tap.

A

true

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
13
Q

The AC input cycle is divided into two parts: the positive alternation and the negative alternation.

A

true

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
14
Q

A full-wave rectifier that does not use a center-tapped transformer and utilizes four diodes to provide full-wave rectification is called a ? rectifier.

A

bridge

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
15
Q

Which of the following represents a full-wave rectifier with a center-tapped transformer and a connected load?

A

a

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
16
Q

Which of the following represents an output waveform that results from two input cycles on a full-wave rectifier?

A

B

full wave on top

17
Q

Which of the following represents a full-wave rectifier with lines and arrows to indicate direction of electron flow for the positive half of input cycle?

A

a

18
Q

Which of the following represents a full-wave rectifier with lines and arrows to indicate direction of electron flow for the negative half of input cycle?

A

b

19
Q

The image represents a ? with load RL.

A

full-wave bridge rectifier

20
Q

The peak voltage across RL is ? . Calculate your answer to one decimal space.

A

Vrl(peak) = Vp - (Vd + Vd)

21
Q

The rectifier converts AC to a(n) pulsating DC voltage.

A

true

22
Q

The average voltage across RL is ? . Calculate your answer to two decimal places.

A

Vave = 2 x Vp/pi

23
Q

Which of the following is a method used to measure rectified voltages in a half-wave rectifier?

A

Peak average

Peak-to-peak

Rms

24
Q

Which of the following formulas is used to find the peak voltage of an un-rectified sine wave?

A

Vp = Vp-p/2

25
Q

Which of the following formulas is used to find the rms value of a half-wave rectifier?

A

Vrms = Vp-p/pi