Population Genetics 2 Flashcards

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1
Q

Fitness differential NS can act one

A

Natural Selection can work on any fitness differential in the absence of other evolutionary forces

IMAGE – The curves all have different fitness differentials –> all of teh curves still show that b1 will increase in frequencey through time
- rate = function of the strength of selection
- Weaker selection takes longer BUT B1 will still increase
- regardless of the strength of selection – if you have a fitness differential = you wikll incerase the frequncey of the higher fitness allelel –> WIlLL LEAD TO FIXATION

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2
Q

Fitness differential NS can act one

A

Natural Selection can work on any fitness differential in the absence of other evolutionary forces

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3
Q

Weaker fitness differences

A

Weaker fitness diffreences lead to slower rates of change

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4
Q

Rate of change

A

Rate of change is a function of the strength of selection

  • Weaker selection = takes long

STILL IN DIRECTIONAL SELECTION IT WILL END WITH FIXATING FOR HIGHER FITNESS ALLELE

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5
Q

When is the rate of chnage the fastest

A

The rate of chnage is the fatstest when the genetic varaition in fitness is highest (P=0.5)
- Place where the rate of evolution (rate of alelle frequcney change) is fatstest = in the steepest part of teh curve – always at the same place – alwats when p=0.5

IMAGE – even though all differentc urves (different fitness differential) – the rate of chnage is fasttest when P=0.5

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6
Q

Fisher’s Fundamental Theorem of Natural Selection

A

Change in popultion fitness is proportional to varaition in fitness
- Fastest rate of chnage in fitness from one generation to the next when variation is highest
- More varaition = more NS can sort through the variation = fatser evolution

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7
Q

Effects of NS

A

NS is determinanistic when acting by itself
- If we know the starting point = we can know the end + all of the intermeduary steps

 - If we know what the conditions are we know what the outcomes will be 
 - NS selection by itself is driven by straight foward mathematics towards a predictable outcome
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8
Q

Dominance Vs. recessive in Directional selections

A

Whether an alelle is domineant or recssive – NS will still push the alelle to increase in frequncey – will get fixation for higher fitness alele in populations over time (for dominant or recessive)
- the end point is still the same (for domiannet vs. recssive) – still goong to fixation

DIFFERENCE = the rate at which coming to fixation occurs

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9
Q

Directional Selections

A

One allele is beneficial and one allele is deletrious

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10
Q

Model of Purley Domeinnet Fitness Vs. Model of purley recessive fitness

A

IF start with p = 0.9 (Start with the dominent in high frequncey)

Selection against dominent – dp = -0.0038

Selection Against a purley recssive –
dP = 0.032

Against Dom –> Agaisnt recssive – X8 diffreence in the rate change
- Selection agsinst the recssive = stronger than the selection agsint the dominant

UNDER THESE CONDITIONS – ALLELE FREQINCEIES ARE CHNAGING MUCH MORE RPAIDLY IN THE PURLEY RECSSIVE CASE (SELECTION AGAINST THE RECESSIVE)

IF we changed allele frequency (NOW the A is in low frequncey) w

P = 0.1 s = 0.3

Selection against the dominant –
w/ = 0.943
dp = -0.026

Selection against the recessive allele –
w/ = .997
dp = -0.0027

NOW – Have bog difference BUT the alelle frequcney is changing much more rapdily in selection against the dominant alllel
-0.026 –> -0.0027 – pattern is now the opposite (selection gaainst the dominant is stronger)

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11
Q

Model of purley Dominent Fitness

P = 0.9 S = 0.3

A

Selection against A BUT A is recsisve – a is domient because Aa is like aa = a is the dominenat and has the highest foitness = sleection gaainst the recssive A

S = 0.3 P = 0.9

w/ = 0.757

dP = 0.032 (different from selection against a dominant allele because w/ is different)

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12
Q

Model of purley recssive fitness (Selection against Dominenat)

S= 0.3 and P = 0.9

A

We know that the selection is pruley recessive fitness because teh heterozygous has teh same selection coeficiant (same Relative fitness) as the AA – fitness affect of A = fitness affect of Aa –> means that the fitness affect of A is dominent (Because AA and Aa have the same fitness)

HERE – fitness for a = highest = 1

S = 0.3 P = 0.9

Need to find dP –> Need relative fitness

wAA = 0.7 (W = 1-s – have have S)

WAa = 0.7

Aaa = 1

W/ = 0.703 – use equation

dP = -0.0038 –> Have a decrease in A because A is the lowest fitness = deleterious = goes down

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13
Q

Meaning of S = 0.3

A

Means that 30% difference in fitness across phenotypes

Relative fitness = 0.7

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14
Q

Overall – Change of alllele frequcney in dominant vs. recessive

A

IF Start will dominent in high frequncey

Selection against the purley recssive alllele (Recessive allele is less fit) = stringer

High freqincey of deleteriuos allele = get rid of it faster when it is recessive

IF start with dominant in low frequcney

Selection against the purley dominent alllele (dominant is less fit) = Stronger
- Selection against the recessive – For benefical dominant alleles at low frequnceies selections acts quickly but slows down as the allele appraches fixation

Low frequencey of deleterious allele = get rid of it fatser when it is dominant

Depends on if teh deleterious allele is dom/rec AND the context of the alllele frequncey in a population (The dominant will not always have stringer seleection)

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15
Q

Graphs – Change of alllele frequcney in dominant vs. recessive

A

Selection agsint the recessive and for the dominant – concave shape
- Selection against the recessive – For benefical dominant alleles at low frequnceies selections acts quickly but slows down as the allele appraches fixation
- Selection occurs rapidly because any time the dominant alelle shows up it is seen by Nastural selection = NS can act on it BUT slows down as ut aporaches fixation becayse increase mean popultion fitness to bring it close to 1 = NS can only act on the deletrious recessive allele of which there are very few = Selection slows down

Selectin against the dominant and for the recessive = convex shape
-

END POINTS of both systems are the same – they still both fix for an allele with higher fitness BUT one starts slow and finshes fast and one starts fast and ends slow

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16
Q

Selection for benefcial dominant alleles at low frequncey

A

Selection acts quickly but then slows down as the alleles apprach fixation
- Selection occurs rapidly because any time the dominant alelle shows up it is seen by Nastural selection = NS can act on it BUT slows down as ut aporaches fixation becayse increase mean popultion fitness to bring it close to 1 = NS can only act on the deletrious recessive allele of which there are very few = Selection slows down

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17
Q

Selection for benefical recessive allles at low Frequency (The dominant allele is in high frequncey)

A

Seleection acts slowly but speeds up as the allele appraches
fications
- NS can only see the allele if it is in aa – if the allele freqeuncey if a is low THEN teh frequncey of aa is even lower because aa is q^2 = have less aa for NS to act on – NS can only act against the A alllele – as frequncey of a increases = maintain varaiance in fitness because of teh heterozygous = NS can accelerate through to end point
- NS is slow acting in favor of recssive because recssive won’t have phenotypic affect = NS cam’t fo anything (opposite for dominant because anytime you have dominant NS can act on it)

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18
Q

Why is there a difference in change in allele freqeuncey acting against dominent or against recessive

A

The difference is in the average excess –
at low frequencies recessive alleles are most likely to combine with dominant gametes –> Therefore, the fitness effect of the allele is invisible to selection because it is mased by the dominant allele
- Makes the benefical recessive at low frequencey hace slow chnage but then speed up as the alleles approach fixation

Vs.

At low frequencies the fitness effect of dominant alleles show up no matter who they combine with however, as they approach fixation, the population mean fitness gets
closer and closer to the fitness of the allele –
Therefore, the relative benefit of carrying the allele isn’t as strong

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19
Q

Quantifying the degree of doninace

A

Real cases often don’t follow that strict dichotomy – So we can quantofy the degree of doinance and define the dominence coefficant for an allele (h)

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20
Q

Directional Selection

A

The highest or lowest value of a trait/alelle frequncey has the highest mean popultion fitness
- Will always end up in the same place – fixing for one allele
P = 1 OR p=0 = has the highest mean population fitness

In the absenece of other forces this leads to fixation for the favored allele

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21
Q

When does directional selection apply

A

Only applies if teh relative fitness of Aa is between the bounds or equal to AA and aa
- can be the same as AA or aa or in between the values of AA and aa

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22
Q

Overdominance

A

Heterozygous advatage – Aa has teh highest fitness

23
Q

Under dominance

A

Heterozygous infiriority – Aa has the lowest fitness

24
Q

Forms of selection

A
  1. Overdominance
  2. Underdominance
  3. Directional selection
25
Q

Example of Overdomiance

A

Here Aa has the higehst fitness = we set Aa equal to 1

26
Q

s vs. t in selection coefficients

A

s and t keep track of the two selection coeffcinats seeprations

IMAGE

A = p –> use s – Selection coefficient acting against AA

a = t

P –> S
q –> T

27
Q

Example for Underdominance

A

HERE WE MAKE THE LOWEST FITNESS EQUAL TO 1 – divide the absolute fitness by fitness of Aa

28
Q

Selection coeficiants in underdominance

A

s and t are negitive – because the fitness of aa and AA should both be higher than Aa

1 - (-#) = gives a number greater than 1

In under dominencae - scale Aa to one (it will be the lowest – only time you scale the lowest value to 1)

29
Q

When do we set the lowest fitness value to 1

A

ONLY for underdominance (If the Aa has the lowest fitness)

30
Q

Under dominance example – with work – calculating w

s = -0.2 t = -0.1

A
31
Q

What do we calculate for over/under dominance

A

calculate an equilibrium point – static point in system (forces are balanced)
- Static point in otherwise dynamic system – forces are balanced to make it stationary

Do this by solving for dP = 0

32
Q

Meaning of Equilbrium point

A

At that point evolution will no longer occur
- Solving for point where dp = 0

33
Q

Calculating P> In overdominance

Given: s = 0.2 t = 0.1

A

AA = 1-s –> RF = 0.8

aa = 1-t –> RF = 0.9

Aa = 1 – hightest

p> = 0.1/().2 + 0.1) = 0.33
- Have equilbirum when p = 0.33 OR when the frequcney of q (a) = 0.67

34
Q

P> in Overdominace vs. nder dominance

A

Might have the same P> value but the nature of p> is difefrent

P> for Overdominance is the highest point of fitness

P> for underdominance is the lowest point of mean fitness
- Fitness is lowest at p> for under dominance

35
Q

Adaptive topography for Overdominance

A

value of P> is the peak – theer is no dP
- At the peak there is NO uphill to go = NS will stop (because NS always oushes uphill)
- If to the left of the point – then P will increase
- If to the right of the point P will decrease
- If you start at P> it will stay there –> if you move away from P> it will evolve to go back to P>
- The direction depends on alelle frequncey BUT will always fix for the same point
- The dP to the left will be posiutive (incvrease P) and dP to the right will be negitive (Push to decrease p)

Reason that P> is the highest population fitness in overdomainnece

36
Q

Equillirbium in Overdominance

A

STABLE equillbirum

37
Q

Fixing in Over vs. Underdominance

A

Overdomince = always fixing for one point
- No matter the allele frequcney – always fix for the same point

Under dominace = there are two points that you can fix for – don’t knwo what wilol be fixed for
- What will be fized for depends on allele frequcney

38
Q

Adaptive Topogrphy of Under dominance

A

Still alwats going uphil
- if start to the left of p> = the popultrion will evolove to p=0
- If start to the right of P. = NS will push P = 1
- If start at P> and all H-W assumptions are true – it will stary there but only if we keep it there – if it is perturbed = then it wil go uphill in eitehr way depending on how it was perturbed

39
Q

Equillibrium in Under dominance

A

Unstable Equillirbium – does not return when pushed
- if you start the poulation on one side it will go to fixation for p = 0
- If you start the population on the other side – it will go to fixation for P = 1

Harder to predict end point – depends on the starting allele frequencey
- Whether goes to P = 1 or P = 0 depends on the starting allele frequencey (Depends if the starting alelle frequncey starts above or below p>)

STILL – both will increase fitness

40
Q

Drawing Topographies for Over dominance

A

Need to find P>

P> = 0.33
0.8 = 1 - s –> s = 0.2

0.9 = 1 - t –> t= 0.1

THEN can calculate relative fitness
p =0.33
q = 0.67

w/ = 0.933 (using equation)

Have 3 points:
P = 1 –> w/ = 0.8
P = 0 –> w/ = 0.9
P = 0.33 –> w/ = 0.933

41
Q

Points for Adaptive topographies for over/under dominance

A

STILL NEED 3 points
P = 1
P = 0
P> –> Find w/
- Because P> is a critical value = needs to be our 3rd point

***P> = stable equilbbirum point in over BUT tipping point in unstable for under

42
Q

Testing for NS in the lab

A

Expect the effect of NS to be the primary driver of change

can run selection experiment and compare the outcome to expectations from model – asking if they evolove based on the adaptive topography

43
Q

Testing the math in the lab (Example – Flour Beetles)

A

Looking at selection against a lethal recessive

Populations = started with ONLY heterozygous (P=0.5) at the locus
- Start at p=0.5 (ALL heterozygotes)

THEN – get the H-W genotypes and track change in alllele frequncey iver time

s for lethal = 1 (1 - 1 = 0 RF)
- RF for aa = 0
- RF for AA and Aa = 1

THEN can find dP – get simplified expression for lethal recessives

LOOK at allele frequncies after 12 generations – compare the rate of chnage in allele freqncuencey with Adaptive Topographies
- They checked the data aginst the curve predicted by population genetics x

OVERALL – you are starting with a mid frequncey of A and you are selectingh against recesisve allele

IMAGE – as it gets rarer = only have issue in q^2 can’t affcet fitness unless in aa = rate of change tappers off

RESULTS – matched what is sepected for selection agaisnt recessive allle
- get fixation for A

44
Q

Testing math in the lab (Example #2) – Drosphila

A

Start = Lethal resseive allele starting at p=0.5 (same starting point as the beetles)

Results = The A alelle did NOT go to fixation (insetad it stalled around 0.79)
- Stoped evoloving when lethal allele was still in frequncey of 21% of the population

WHY did it stall?
- Reached a static equillibrium point = even though it was lethal for aa it has a benifit for Aa
NOW – it is not directional selection (the heterozygotes have the highest fitness) = over dominancve

THEN – They started with different allele frequnceies to see if it would stable to the same pount –> Found that it did get to the same point
- Confimed that this was due to overdomincae by starting the population at a very low frequncey of the recessivee (at 0.025) –> q evolove to increase to 0.21 – the leathal allele increased in frequncey because of its adavatage in Aa

Had an increase in frequncey in the lethal allele because of overdominance (Heterozygous advantage)
- Depsite being lethal as aa – teh a allele was a benefit to Aa = get equilibirum ppint

45
Q

Population genetics example in the real world with Over/under dominance

A

Sickle cell + Malaria

46
Q

Malaria

A

One of the greatest public health crisis
- Big porblem
- Hot sopt = wet warm places
- The plasmodium parasite gers into RBCs – ability to iteract with RBCs = important for malaria

47
Q

Anemia + malria

A

Sickle cell Anmeica = plats a role in malaria resistance
- hemoglobin peptides = bunch up = strtch out RBCs = wriong shaope RBCs –> hard for RBCs to pass through capilaries = decrease in oxygen + low Iron + low RBC count

48
Q

Fitness of Sickle cell in malaria envirnmnets

A

CLEAR case of over dominance

AS = the highest fitness

AA = get malaria –> S = 0.11 (RF = 0.89)

AS = 1.0 – in malaria envirnemnt you are better tan AA because resistant to malaria

SS = 0.2 – same in malaria and non-malraia envoirnmemnts – still same fitness decrease as before

49
Q

Calculating the P> + making Adaptive topography for Malaria (With two alleles)

A

Chart = shows that if to the right of equillibriounm in a place with malaria = will increase in S allele (Decrease A) THEN negitive affect of SS is overcome by the increase in fitness oif AS = the frequncey of S will increase until P>

50
Q

Calculating the expected frequncey of Hemolytic Anermia Phenotypes in malarial Envirnments

A

We already know that P = 0.88 –> Q = 0.12

Then we can know the frequncey of indovodulas maintained by NS

q^2 = 0.12^2 = 0.014 –> means that 1% of the population is mainatined by NS
- If you decrease S NS will push it basck up and increase the number of Individulas that have the disease

51
Q

Result of Heterozygous Advantage

A

The heterozygote advantage of the S allele results in natural selection maintaining a very negative trait – sickle cell anemia- at a rate of nearly 1.5% in those populations!

52
Q

Malaria Example – Add in C Alelle

A

NOW have a 3 allele system

AC – C has no effect on fitness if with A (In a malaria envirnmmet or NOT)

SC – Have decrease in fitness in maalria + non-malaria envirnmemt
- Have some finess cost with AC

CC – Same in non-malaria envirnmemnt BUT best in A malaria envrinment
- In malaria envirnment it is alwamost entireley resistent to malaria
- Have no Anemia + Most resistant to malaria = C is the best alelle

Best genotype is CC – has the higehst w/ when population is fixed for C (w/ would be 1.31)

Question - why hasn’t C gone to fixation? How will NS act on C?

Equilibirum between A and S
Pa> = 0.879
Ps> = 0.121

Start with
Frequncey of A (pA) = 0.879
Frequncey of S (pS) = 0.121

THEN If we have C and we make Frequncey of C (pC) = 0.01
- take away from A
NOW
pA = 0.869
pS = 0.121
pC = 0.01

NOW
w/ = 0.903
dPc = pC/w/ (Avegrage excess)
dPc = -0.0314

What happens to C – dpC = -0.03 –> NS acts against C – decrease the frequncey of C
- Before w/ = 0.933 BUT now w/ is 0.903 –> w/ decreased – even though C is a good alelle w/ Decreased (hurt the population fitness to have the good allele)

REASON – only get the beneficial genotupoe 1% of the time – very small amount - most of the time the otehr copes if C make the w/ decrease (when will SC – decreases w/) –> MEANS that the C alelles end up in genoptypes that NS acts against (because ends up in genotypes that have lower fitness)
- Even thought C is the best alelle it won’t go to fixation because NS will act against it because it will only act in uphill directions to increase w/ BUT most of the time C decreases w/ = it will not go to fixation)

Even though C is the best aellle (it has the highest w/) –> natutral selection with act agaionst C in the population (NS is determianistic NOT ominpotent)

53
Q
A