Physical 1: Amount of Substance Flashcards
relative atomic mass (Ar)
relative atomic mass = (average mass of one atom of an element) / (1/12 mass of one atom of 12C)
relative atomic mass = (average mass of one atom of an element) / (mass of one atom of 12C)
relative molecular mass (Mr)
relative molecular mass = (average mass of one molecule) / (1/12 mass of one atom of 12C)
relative molecular mass = (average mass of one molecule x 12) / (mass of one atom of 12C)
relative formula mass (Mr)
used for ionic compounds because they don’t exist as molecules
avogadro constant
6.022x10^23
it is the number of atoms in 12g of carbon-12
the mole
the amount of substance that contains 6.022x10^23 particles is called a mole
number of moles formula
number of moles = mass / mass of 1 mole
concentration formula
concentration = mass / volume
Boyle’s Law
pressure x volume = constant
Charles’ Law
volume / temperature = constant
Gay-Lussac’s Law (constant volume law)
pressure / temperature = constant
ideal gas equation
PV = nRT P = pressure Pa V = volume m^3 n = number of moles R = gas constant = 8.31 JK-1mol-1 T = temperature K
rearrange ideal gas equation for volume
V = nRT / P
rearrange ideal gas equation for number of moles
n = PV / RT
empirical formula
simplest whole number ratio of atoms of each element present in a compound
how to find empirical formula
- find masses of each of the elements present in a compound
- work out the number of moles of atoms of each element :
number of moles = (mass of element) / (mass of 1 mol of element) - convert the number of moles of each element into a whole number ratio
molecular formula
actual number of atoms of each element in one molecule of the compound
empirical is not always the same as the molecular
how to find the number of units of the empirical formula in the molecular formula
divide the relative molecular mass by the relative mass of the empirical formula
stoichiometry
the ratio in which the reactants react and the products are produced in simple whole numbers
titration steps
- fill a burette with the acid of known concentration
- accurately measure an amount of the alkali using a calibrated pipette and pipette filler
- add the alkali to a conical flask with a few drops of a suitable indicator
- run in acid from the burette until the colour just changes, showing that the solution in the conical flask is now neutral
- repeat the procedure, adding the acid dropwise as you approach the end point, until two values of the volume of acid used at neutralisation are the same, within experimental error
atom economy
% atom economy = 100 x (mass of desired product) / (total mass of reactants)
atom economy vs percentage yield
atom economy = in theory how many atoms must be wasted in a reaction
percentage yield = tells us about the practical efficiency of the process, how much is lost by:
- the practical process of obtaining a product
- as a result of reactions that do not go to completion
formula of percentage yield
yield = 100 x (no. of moles of specific product) / (theoretical max no. of moles of product) yield = 100 x (no. of grams of specific product) / (theoretical max no. of grams of product)