Periodic Trend In EIectron Configuration And Ionisation Energy Flashcards
what is the periodic trend in electron configuration across period 2?
2s subshell fills followed by 2p subshell
what is the periodic trend in electron configuration across period 3?
3s subshell fills followed by 3p subshell
what is the classfication of elements into s, p. d and f blocks?
s on the left, p on the right, d in the middle and f block at the bottom
what is the first ionisation energy?
the energy required to remove one mole of electrons from one mole of gaseous atoms of an element to form one mole of gaseous 1+ ions
why are elements classified to specific blocks?
the highest energy electron is in that orbital (s,p,d or f)
what is the trend in first ionisation energy across period 2(general)?
first ionisation energy increases generally
- greater nuclear charge
- similar shielding
- greater nuclear attraction
- atomic radius decreases
what is the trend in first ionisation energy across period 3(general)?
first ionisation energy increases generally
- greater nuclear charge
- similar shielding
- greater nuclear attraction
- atomic radius decreases
what is the trend in first ionisation energy down a group?
first ionisation energy decreases down a group
- atomic radius increases
- electron shielding increases
- nuclear attraction weakens
- greater nuclear charge
where does the first ionisation energies drop in period 2?
- beryllium to boron
- nitrogen to oxygen
why does the first ionisation energy drop from beryllium to boron in period 2?
- B electron is removed from 2p
- Be electron is removed from 2s
- 2p electron in B has higher energy than the 2s electron in Be
- so it is easier to remove 2p electron in B compared to 2s electron in Be
why does the first ionisation energy drop from nitrogen to oxygen in period 2?
- in N2 and O2 highest energy electrons are in 2p subshell
- in O2, paired electrons in one of the 2p orbitals repel each other = easier to remove electron from oxygen atom compared to nitrogen atom
how can you see if the electron is being removed from a different shell?
a large increase in the ionisation energy
why does the first ionisation energy drop from phosphorus to sulfur in period 3?
- in P and S the highest energy electrons are in the 3p subshell
- in S, there are paired electrons in one of the 3p orbitals and these repel each other
- so it is easier to remove an electron from the sulfur atom compared to removing one electron from the phosphorus atom
why does the first ionisation energy drop from magnesium to aluminium in period 3?
- Mg electron is removed from 3s
- Al electron is removed from 3p
- 3p electron in Al has higher energy that 3s electron in Mg
- so it is easier to remove 3p electron from Al compared to 3s electron in Mg and requires less energy
how do you write the first ionisation energy(e.g. for magnesium)?
Mg(g)–> Mg+(g) + e-