Percentage Yield & Atom Economy Flashcards

1
Q

Reasons for not getting a 100% conversion of reactants to products when oxidising ethanol & ethanoic acid

REACTION TIME

A

REACTION TIME:

  • Not all the ethanol / partial oxidation product ethanal had reacted.
  • due to insufficient time when refluxing
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2
Q

Percentage yield & formula

A
  • The amount of product made by the end of a reaction
  • Tells us how much of the reactants has been converted to products ( efficiency of the reaction)

actual amount of product (mol) x100
theoretical amount of product (mol)

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2
Q

Other general reasons for not getting 100% conversion of reactants to products

A
  • The reactants may not be PURE
  • The reaction may not go to COMPLETION~ applies to equilibrium reactions.
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3
Q

Reasons for not getting a 100% conversion of reactants to products when oxidising ethanol & ethanoic acid

DISTILLATION

A
  • A type of purification process which SEPARATES the product from other products and reagents.
  • Some of the ethanoic acid may not have been fully distilled
  • Leaving it in the round bottom flask or the joints of the apparatus.
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3
Q

Reasons for not getting a 100% conversion of reactants to products when oxidising ethanol & ethanoic acid

SIDE REACTIONS LEADING TO BY-PRODUCTS

A

Ethanol, in the presence of HEAT and c.H2SO4 , can be DEHYDRATED :

  • Produces ETHENE

CH3CH2OH —– H2C=CH2 + H2O

Unreacted ethanol, in the presence of heat and c.H2SO4, can react with ethanoic acid :

  • Produces ETHYL ETHANOATE

CH3CH2OH + CH3COOH —- CH3COOCH2CH3 + H2O

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4
Q

Procedure for working out % yield

A
  • Write a balanced EQUATION for the reaction.
  • Work out the MOLES of each REACTANT
  • Determine the LIMITING REAGENT and use this to calculate the THEORETICAL MOLES of the product using the reaction equation.
  • Calculate the ACTUAL MOLES of the product made in the reaction.
  • Calculate the PERCENTAGE YIELD using the equation.
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5
Q

Fermentation of glucose

A
  • An alternative method to the hydration of ethene to make ETHANOL.

C6H12O6(aq) — 2CH3CH2OH(aq) + 2CO2(g)

Reaction Conditions:
- Yeast
- 37 degrees
- Absence of oxygen

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6
Q

Atom economy

A

molecular mass of desired product/molecular mass of all products x 100

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7
Q

Percentage yield and its disadvantages

A

Percentage yield :
- measures how wasteful the reaction is based on how much product is lost.
- Often occurs due to the reaction being incomplete or losses during collection and purification procedures.

DISADVANTAGES:
- Does not measure how wasteful the reaction actually is.
- A reaction can have a 100% yield but still have a lot of the reactants end up as BY-PRODUCTS , rather than the desired product.

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8
Q

Why is atom economy better than percentage yield?

A
  • Measure the EFFICIENCY of a reaction
  • Based on the PROPORTION of reactant atoms which become part of the DESIRED PRODUCT, rather than the by-products.
  • The calculation is based on balanced symbol equation.
  • In an ideal chemical process, a use would be found for all the products and hence the atom economy would be 100%.
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9
Q

Problems & solution to a LOW atom economy

A
  • A reaction with a low atom economy means that most of the reactants turn into WASTE.
  • Particularly bad when FINITE MATERIALS are used and cannot be preserved.
  • Waste has to be DISPOSED of ~ COSTLY and poses ENVIRONMENTAL PROBLEMS.

SOLUTIONS:
- Sold off
- recycled
- used to make other products

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10
Q

Sustainability

A
  • Developing processes to PREVENT THE DEPLETION of natural resources
  • e.g crude oil & wood

LOW atom economy = process has LOW sustainability

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11
Q

The sustainability of a chemical process can be IMPROVED by:

A

REDESIGN PRODUCTION METHOD:
- Different/less hazardous starting materials are used

MILDER REACTION CONDITIONS:
- Better catalysts
- Less hazardous solvents

RECYCLING

SELLING BY-PRODUCTS

  • Using production methods with FEWER STEPS and HIGHER ATOM ECONOMIES.
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12
Q

Calculating atom economy

A
  • Write EQUATION for the reaction
  • Calculate the MOLECULAR MASS of DESIRED product.
  • Calculate the MOLECULAR MASS of ALL the products.
  • Use FORMULA to calculate ATOM ECONOMY.
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