page 1 Flashcards
alkyl halides
Alkyl Halides:
Compounds with a halogen (F, Cl, Br, or I) bonded to an sp³ hybridized carbon atom.
General formula: R-X, where R is the alkyl group and X is the halogen.
Nucleophilic Substitution:
Nucleophilic Substitution:
A reaction where a nucleophile (electron-rich species) replaces a leaving group (usually a halide) in a molecule.
Two main types:
SN2: A one-step, bimolecular mechanism where bond-making and bond-breaking occur simultaneously.
Key points:
Inversion of configuration (if the carbon is chiral).
Favored by strong nucleophiles and less steric hindrance.
SN1: A two-step, unimolecular mechanism involving the formation of a carbocation intermediate.
Key points:
Racemization occurs at the carbon center (50% retention, 50% inversion).
Favored by weak nucleophiles and stable carbocations.
Factors Affecting Substitution Reactions:
Factors Affecting Substitution Reactions:
Substrate: Primary carbons favor SN2, while tertiary carbons favor SN1
.
Nucleophile: Stronger nucleophiles favor SN2.
Leaving Group: Better leaving groups (weaker bases) facilitate substitution.
Solvent:
Polar protic solvents favor SN1 (e.g., water, alcohol).
Polar aprotic solvents favor SN2 (e.g., acetone, DMSO).
What is the general formula for an alkyl halide?
Answer: R-X, where R is an alkyl group and X is a halogen.
Which reaction mechanism involves a carbocation intermediate?
Answer: SN1 mechanism.
In SN2 reactions, what happens to the configuration of a chiral carbon?
Answer: The configuration inverts (backside attack).
What type of nucleophile is required for an SN2 reaction?
Answer: A strong nucleophile.
What is a good example of a polar aprotic solvent for SN2 reactions?
Answer: Acetone or dimethyl sulfoxide (DMSO).
Which type of alkyl halide is most likely to undergo an SN1 reaction?
Answer: A tertiary alkyl halide.
What functional group in adrenaline makes it polar and capable of hydrogen bonding?
Answer: Hydroxyl (-OH) groups.
Why is a good leaving group important in substitution reactions?
Answer: It stabilizes the negative charge after it leaves, making the reaction more favorable.
When Does Racemization Occur?
SN1 Reaction:
In an SN1 reaction, the first step involves the formation of a carbocation intermediate after the leaving group departs.
The carbocation is planar (sp² hybridized) and lacks chirality, so the incoming nucleophile can attack from either side (top or bottom of the plane).
This leads to the formation of both enantiomers in equal proportions, causing racemization.
Conditions for Racemization:
A chiral carbon atom connected to a good leaving group (e.g., halides like Cl, Br, or I).
A reaction mechanism where a planar intermediate (e.g., a carbocation) is formed, allowing for non-stereospecific attack.
Example: Racemization in SN1
Suppose you have the following chiral alkyl halide:
Starting compound: (R)−2-bromobutane
Reaction: SN1 substitution with water as the nucleophile.
Steps:
Formation of Carbocation:
The bromine atom (leaving group) departs, creating a planar carbocation at the chiral carbon center.
CH3−CH(+)−CH2−CH3
2.Nucleophilic Attack:
The water molecule (nucleophile) can attack the carbocation from either side of the planar structure.
3. Result:
This produces a racemic mixture:
(R)−2-butanol
(S)−2-butanol
Both enantiomers are formed in equal amounts.
Visualizing Racemization:
Before Reaction: The molecule exists as a single enantiomer (e.g.,
(R)−).
After Reaction: Equal amounts of
(R)− and
(S)− enantiomers are formed, resulting in no net optical rotation.
Key Points to Remember:
Racemization occurs when a reaction leads to the formation of a planar intermediate (like a carbocation in SN1
1).
SN2 reactions do not cause racemization; instead, they result in inversion of configuration because the nucleophile attacks from the opposite side of the leaving group.