PAG 1.1 Comparing Methods Of Determining g Flashcards

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1
Q

What is meant by free-fall?

A

An object is said to be falling in free-fall if the only force acting on it is gravity. This means that no resistive forces are acting (or in practice are considered negligible)

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2
Q

What is g?

A

Gravitational Field Strength (on the surface of the Earth)

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3
Q

Why can SUVAT equations by used in this experiment?

A

The object will fall with uniform acceleration. This is because the force of gravity is constant at the Earth’s surface

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4
Q

When plotting a graph of t^2 against h, how is g determined?

A

The gradient is t^2/h
Consequently the acceleration (g) will be equal to 2/gradient
Comes from the equation s=ut+1/2at^2
(s=1/2at^2 as u=0)

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5
Q

When plotting a graph of v^2 against h, how is g determined?

A

Gradient is v^2/h
Acceleration (g) is half the gradient
Comes from the equation v^2=u^2-2as

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6
Q

Describe how an electromagnet system can be used to determine g

A

A magnetic ball bearing can be released by an electromagnet clamped at a known height. The timing system starts when the electromagnet is switched off, and the timer is stopped when the ball lands on the finish pad

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7
Q

When using a clamp stand in this experiment, what safety precautions should be taken?

A

The clamp stand should have a counterweight or G-clamp attached to its base to provide a moment to prevent it toppling over

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8
Q

What safety precaution should be taken when using an electromagnet?

A

Electromagnets heat up over time. To reduce this heating effect, switch it off when not in use

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9
Q

Suggest how light-gates could be positioned to ensure that the ball or dowel falls directly through them

A

A plumb line could be used to demonstrate the expected path of the object. This allows the light-gates to be positioned in appropriate places so that the ball will fall through them

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10
Q

Why is it advantageous to use a small ball-bearing over a larger ball?

A

The smaller the ball, the smaller the effects of air resistance. In the case of a small ball-bearing, these effects can be considered negligible

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11
Q

Why should there be a gap between the release position and the first light-gate?

A

There should be a gap to ensure that the time over which the ball is passing through the light gate is negligible (the ball is moving sufficiently quick enough)

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12
Q

Explain why this experiment would not be valid if the air resistance acting on the ball wasn’t negligible

A

The ball wouldn’t be in free-fall since the acceleration would not be purely due to the force of gravity. The acceleration would also be variable since the air resistance increases with speed, and so the uniform acceleration equations couldn’t be used.

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13
Q

Suggest why your obtained value of g may not be the same as the accepted value

A

Delays in timing equipment (stopwatch=human reaction time)
Resistive forces are acting
Errors in height measurements, such as measuring different positions on the ball each time

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14
Q

What is the advantage of using light-gates over a stop clock in this experiment?

A

Using light-gates should result in a lower uncertainty in your time measurements. A stop clock will involve human reaction times

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15
Q

How could your results be improved?

A

Take repeat reading at each height and then calculate the mean time taken
Ensure height measurements are taken from the same position each time

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16
Q

How should you calculate uncertainty in time readings?

A

Uncertainty will be equal to half the range of time readings. This can then be converted into a percentage uncertainty

17
Q

How do you determine the percentage uncertainty in t^2?

A

Double the percentage uncertainty of the variable itself.
% uncertainty in t^2 is double % uncertainty in t

18
Q

What is the minimum number of repeat readings you should take in this experiment?

A

Take at least 3 repeat readings at each height. This allows for anomalous results to be more easily identified

19
Q

What is the equation used to convert an uncertainty into a percentage uncertainty?

A

(Uncertainty/mean value) x 100

20
Q

How can the percentage difference between your value of g and the accepted value be calculated?

A

(Your value - 9.81)/9.81 x 100

21
Q

Would you expect your value of g to be greater or lower than the accepted value?

A

Most likely lower than the accepted value due to air resistance reducing the downwards resultant force acting on the object