Organic Reactions Flashcards
alkene –> alcohol
Direct (direct to alcohol, no need to go to alkane->haloalkane->alcohol)
Catalytic (H3PO4 + 300C)
Hydration (H2O)
+ H2O
{H3PO4} + 300C
alkane –> alcohol
CAN’T DO DIRECT CATALYTIC HYDRATION - only for alkenes
- sub Cl for a H {UV light}!!!
- sub OH for the Cl
e.g.
CH4 + Cl2 –> CH3Cl + HCl {UV light}!!!
CH3Cl + NaOH –> CH3OH + NaCl
{under reflux}
///or u use enzymes which is green chem! Less energy intensive than reflux
alkene + Cl2
normal substitution of BOTH chlorine atoms
alkane + Cl2 (a part of the full eq to turn alkanes to alcohols)
- substitution of 1 of the chlorine atoms for a hydrogen {UV light} !!!
- …normally leads to adding NaOH to form alcohol. (OH subs for Cl) = alcohol + NaOH
{req. no catalyst}
alcohol + {Cr2O7 2- + H+}
- (primary alc.) –> carboxylic acid or aldehyde (dk which one yet, fully oxidise?)
- (secondary alc.) –> ketone
- (tertiary alc.) –> *no reaction
alkene –> alkane
Catalytic Hydrogenation
+ H2
{metal catalyst eg. Pt or Ni}
alkane –> amine 1.(primary)
- alkane –> primary haloalkane
+ HCl / HBr (could we add Cl2? idk) - primary haloalkane –> primary amine
{NH3 + heat}
+ ethanol (which is a solvent for NH3)
**2 other methods. above is the cheapest method. look at pg50 booklet
Subbing Halogens onto Alkanes
eg. chloromethane –> dichloromethane –> trichloromethane –> tetrachloromethane
CATALYST REQUIRED! >:(
{UV light}
*depending on how much chlorine is present, will determine percentage of PURE tetrachloromethane.
Esterfication reaction (Condensation rxn)
carboxylic acid + alcohol –> ester + water
{H2SO4 + heat}!!
*concentrated acid
NOTE: naming wise, alcohol will become 1st name (no double C=C bond) & carboxylic will become 2nd name (contains double C=C bond)
eg. ester is… methyl (from methanol) ethanoate (from ethanoic acid)
Hydrolytic reaction
water + ester –> carboxylic acid + alcohol
{H2SO4 + heat}!!
*weak dilute acid